KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.4

Students can Download Maths Chapter 10 Exponents Ex 10.4 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka Board Class 8 Maths Chapter 10 Exponents Ex 10.4

Question 1.
Simplify
(i) \(\frac{\left(2^{5}\right)^{6} \times\left(3^{3}\right)^{2}}{\left(2^{6}\right)^{5} \times\left(3^{2}\right)^{3}}\)
(ii) \(\frac{\left(5^{-3}\right)^{2} \times 3^{4}}{\left(3^{-2}\right)^{-3} \times\left(5^{3}\right)^{-2}}\)
Answer:
KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex. 10.4 1

Question 2.
Can you find two integers m and n such that 2m+“ = 2m”?
Answer:
m + n = mn
2 + 2 = 2 x 2
4 = 4
∴ m = 2 & n = 2

Question 3.
If (2m)4 = 46 find the value of m.
Answer:
(2m)4 = 46 (am)n = amn
(2m)4 = 46
(2m)4 = (22)6
2m × 4 = 22 × 6
24m = 212
∴ 4m = 12
m = \frac { 12 }{ 4 }
m = 3

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