1st PUC English Grammar Notes Letter Writing

You can Download 1st PUC English Grammar Notes Letter Writing, 1st PUC English Textbook Answers, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.

Karnataka 1st PUC English Grammar Notes Letter Writing

1. Write a letter to the Principal of your college requesting him/her to grant you leave of absence for two days.

Rohan
P.V.C. I, W Section
Dayananda College
Bengaluru

21 January 2019
The Principal
Dayananda College
Bengaluru
Dear Sir
Sub.: Permission for leave
I am a student of P.V.C. I, ‘A’ Section and my register number is 181029. I will not be able to attend classes for two days on the 23rd and 24th of January as my sister is getting married or, 24th of January. I hope you will grant me a leave of absence for two days. I would also like to inform you that I have always been regular to class and have had no shortage of attendance till now.

Thank you.

Yours faithfully,
Rohan

Learn more about the English Language with our website provided English Grammar Notes and get a great companion to grammar rules and example sentences.

KSEEB Solutions

2. Write a letter to the Assistant Commissioner requesting him/her to deliver a speech on GST for the students in your college next month.

Raghavendra Rao
Chaithanya College
JP. Nagar 7’ Phase
Bengaluru

25 December 2018

The Assistant Commissioner
Bengaluru Central Tax Zone
Bengaluru
Dear Sir
I am writing in my capacity as Student Welfare Officer of one of the prestigious colleges of Bengaluru, Chaithanya College. It is my duty to organise programmes on a regular basis to benefit the student community. It is important for students to keep abreast of current affairs. Hence it would be useful if you could share your knowledge on GST with our students. We reopen on 2 January 2019 after the Christmas vacation and we would be grateful if you could make some time in the first week of January to address our students for an hour between 9-00 am. and 4-00 p.m. according to your convenience.

Thank you.

Yours faithfully,
Raghavendra Rao
(Student Welfare Officer)

KSEEB Solutions

3. Write a letter to the BESCOM Officer in charge of your area to reduce the duration of power cuts to help the students. Your letter should also Indude the following points

a. Inconvenience caused to the students during study time.
b. Irregular power cuts disturb the concentration of students.
c. Request to take remedial measures.

Venugopal
23, Ramaiah Layout
Rajajinagar 3rd Block
Bengaluru

10 March 2019

The Officer in Charge
BESCOM.
Rajajinagar
Bengaluru
Dear Sir
This is to draw your attention to the inconvenience caused to the student community of our area owing to unreasonable power cuts. It is examination time, and of the wakeful hours, 50% is lost because of power cuts. This has affected the study pattern of students who at present have their study holidays for the oncoming exams.

We have a request to make and we hope you will oblige us:
The duration of power cuts should be reduced to one hour in the morning and one hour in the evening. As of now, it is two hours in the morning and two hours in the evening.
in addition to the power cuts, the power supply quite often is erratic. This affects the concentration of students. Please ensure that there is uninterrupted power supply except for the scheduled power cuts. I hope you understand that this kind of power cuts affect the middle class and poor people as they don’t have generators or Inverters. So, please consider remedial measures immediately.

Thank you.

Yours faithfully,
Venugopal

KSEEB Solutions

4. Write a letter to the Municipal Commissioner of your area requesting him/her to take remedial measures to overcome the stray dog menace. Your letter should also include the following points:

a. Increase in the number of stray dogs.
b. Frequent attacks by stray dogs.
c. Adopting measures such as castration, relocation, etc.

Archana Rao
M.G. Road’
Saraswathipu ram
Mysuru

21 April 2019

The Municipal Commissioner
Mysuru City Corporation
Mysuru
Dear Sir
This is with regard to a major problem faced by the citizens of our area. For the past one month, we have been suffering from the menace of stray dogs. There is a noticeable increase in the number of stray dogs as also the number of unpleasant incidents related to stray dogs. east week stray dogs bit two children and stray dogs reportedly chased two men as they were carrying food packs. Now the situation is such that people are frightened to step out of the house. I request you to take immediate action to help the citizens out. Measures such as castration and relocation will have to be implemented by authorities and not citizens. So, I request the officials concerned to look into the matter immediately and take action.

Thank you.

Yours faithfully,
Archana Rao

KSEEB Solutions

5. Write a letter to the Chairman, BWSSB, Bangalore, complaining about the irregular water supply and the inconvenience caused to the people. Your letter should include the following points:

a. Supply of water at odd hours,
b. Non-availability of water to some families.

Venkatesh Adiga
31, 5 Cross
J.P. Nagar 6’ Phase
Bengaluru

25 Jul 2019

The Chairman
BWSSB
Kempegowda Road
Bengaluru
Dear Sir
This is with regard to the irregular water supply to our area. For the past one month, we have had water supply only from 10-00 p.m. to 7-00 a.m. This is unacceptable. Water is the basic necessity of life and we should not be deprived of It. In cities not most live in apartments and small houses with a limited storing capacity. If the water supply is limited to the night time, it poses problems with regard to bathing, cooking, washing, etc. Please ensure that there is water supply at least for two hours each in the morning and evening. Though this too would pose problems, it would at least be better than the present situation. Please take immediate action and help us out in our predicament.

Thank you.

Yours faithfully,
Venkatesh Adiga

KSEEB Solutions

6. Write a letter to the Principal of your college requesting him/her to issue Transfer Certificate, the reason being the transfer of your father.

Shankar C.S.
Veerashaiva PU. College
Bailan

l9 January 2019

The Principal
Veerashaiva P.U. College
Sallan
Dear Sir
Sub: Issue of TC
I am a student of the I year RU.C. ‘C’ section and I write to you with a request for a Transfer Certificate. My father has been transferred to Hassan and we will be relocating to Hassan.
The TC could be sent to the following address:
Narayana College, Central Market Road. Hassan. I was fortunate to be a student of Veerashaiva P.U. College for a year I carry happy memories of the college.

Thank you.

Yours faithfully,
Shankar C.S.

KSEEB Solutions

7. Write a letter to the Co-ordinator, ‘Institute of Spoken English’ seeking information about the courses offered in the institute.

Nithin Prabhu
1471, Marigudi Road
Urva
Mangalore

3 October 2018

The Coordinator
BBB Institute of Spoken English
Car Street
Manga lore
Dear Sir
I came across your advertisement in the Udayovoni. I am a graduate and I am looking out for good job opportunities. Though my academic records are impressive, my spoken English is weak. Hence I would like to improve myself in this area. Please let me know the duration of the course, the fee structure, and the timings as soon as possible.
Does the course that you offer cover only spoken English or do you extend the course to other aspects like communicative English? Hope you will send an early reply.

Thank you:

Yours faithfully,
Nithin Prabhu

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

Students can Download Chapter 2 Fractions and Decimals Ex 2.5, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

Question 1.
Which is greater ?
i) 0.5 or 0.05
Solution:
0.5 > 0.05 (∵ 0.5 = 0.50)

ii) 0.7 or 0.5
Solution:
0.7 > 0.5

iii) 7 or 0.7
Solution:
7 > 0.7 (∵ 7 = 7.0)

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

iv) 1.37 or 1.49
Solution:
1.49 > 1.37

v) 2.03 or 2.30
Solution:
2.30 > 2.03

vi) 0.8 or 0.88
Solution:
0.88 > 0.8 (∵ 0.8 = 80)

1 1/2 as a decimal is equal to 1.5.

Question 2.
Express as rupees using decimals :
i) 7 paise
Solution:
7 paise = Rs. 0.07

ii) 7 rupees 7 paise
Solution:
7 rupees 7 paise Rs. 7.07

iii) 77 rupees 77paise
Solution:
77 rupees 77 paise = ₹ 77.77

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

iv) 50 paise
Solution:
50 paise = 0.50

v) 235 paise
Solution:
235 paise = 2.35

Question 3.
i) Express 5cm in metre and kilometre
Solution:
5 cm = 0.05m = 0.00005km.

ii) Express 35mm in cm, m and km
Solution:
35mm = 3.5cm = 0.000035km

Question 4.
Express in kg :
i) 200g
Solution:
200g = 0.200kg = 0.2 kg

ii) 3470g
Solution:
3470g = 3.470kg

iii) 4 kg 8 g
Solution:
4kg 8g = 4.008 kg

Question 5.
Write the following decimal numbers in the expanded form :
i) 20.03
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 1

ii) 2.03
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 21

iii) 200.03
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 22

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

iv) 2.034
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 23

Question 6.
Write the place value of 2 in the following decimal numbers :

i) 2.56
Solution:
2.56 place value of 2 in the decimal number 2.56 = 2 ones place)

ii) 21.37
Solution:
21.37 place value of 2 in the decimal number 21.37 = 2 × 10 = 20. (2 is in tens place)

iii) 10.25
Solution:
10.25 = palce value of 2 in the decimal
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 24

iv) 9.42
Solution:
9.42 = place value of 2 in the decimal number
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 25
(2 is in hundredths place)

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

v) 63.352
Solution:
63.352 = place value of 2 in the decimal number
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 26

Question 7.
Dinesh went from place A to place B and from 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelles more and by how much ?
Solution:
Distance travelled from A to B = 7.5kms
Distance travelled from B to C = 12.7kms
Total distance travelled from A to B & B to C = 20.2 kms.
Ayub
Distance travelled from A to D = 9.3 kms
Distance travelled from D to C = 11.8 kms
Total distance travelled from A to D & D to C = 21.1 kms
∴ Ayub travelled more distance than Dinesh by = 21.1 – 20.2 = 0.9 kms.

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

Question 8.
Shyama bought 5 kg 300g apples and 3 kg 250 g mangoes. Sarala bought 4 kg of 800 g oranges and 4 kg 150g bananas. Who bought more fruits?
Solution:
Shyama:
Weight of Apples bought = 5.300kgs
Weight of Mangoes bought = 3.250kgs
Total weight of fruits = 8.550kgs

Sarala:
Weight of oranges bought = 4.800kgs
Weight of Bananas bought = 4.150kgs
Total weight of fruits = 8.950kgs
8.950 >8.550
∴ Sarala bought more fruits than Shyama.

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

Question 9.
How much less is 28 km than 42.6 km?
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 30
∴ 28 km is less than 42.6 km by 14.6 kms.

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions

Students can Download Maths Chapter 4 Decimal Fractions Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 4 Decimal Fractions

KSEEB Class 5 Maths Decimal Fractions Revision Exercise

In order to round to one decimal place, you must be familiar with the concept of rounding numbers.

I. Read the following decimals and write them in words:

1. 0.5
Zero point five

KSEEB Solutions

2. 0.13
Zero point one three

3. 1.7
One point seven

4. 5.21
Five point two one

II. Write the numeral representing each of the following:

1. Zero point one – two
0.12

2. Six point eight
6.8

3. Ten point five
10.5

KSEEB Solutions

4. Four point zero two.
4.02

5. Six point eight four
6.84

6. One hundred eight point zero six
108.06

III. Fill in the blanks:

1. 8mm = 0.8 cm
1 cm = 10 mm
8 mm = \(\frac{8}{10}\) = 0.8 cm

2. 75 mm = 7.5 cm
1 cm = 10 mm
75 mm = \(\frac{75}{10}\) = 7.5 cm

KSEEB Solutions

3. 8 cm 5 mm = 8.5 cm
1 cm = 10 mm
5 mm = \(\frac{5}{10}\) = 0.5
8 + 0.5 = 8.5 cm+

4. 525 mm = 5.2 cm
1 mm = \(\frac{10}{10}\)
525 mm = \(\frac{525}{10}\) = 52.5cm

IV. Fill in the blanks:

1. 8 cm = 0.08 m
1 mm = 100 cm
8cm = \(\frac{8}{100}\) = 0.08

2. 72 cm = 0.72 m.
1 mm = 100 cm
72 = \(\frac{72}{100}\) = 0.72

3. 375 cm = 3.75 m.
1 mm = 100 cm
375 cm = \(\frac{375}{100}\) = 3.75

4. 4m 80 cm = 4.08 m.
1 mm = 100 cm
80cm = \(\frac{80}{100}\) = 0.8
4m + 0.8m = 4.08 m

KSEEB Solutions

5. 15m. 6 cm = 15.06 m.
1 mm = 100 cm
6 cm = \(\frac{6}{100}\) = 0.06
15m + 0.06 = 15.06m

V. Write in decimal fractions:

The long division is carried subsequently, which gives the output of 58 5 8 as a decimal. 5/8 as a decimal.

1. 75 paise = Rs. ________
1 paise = 100 paise
75 paise = \(\frac{75}{100}\) = 0.75

2. 10 rupees and 25 paise = Rs. _________
1 rupees = 100 paise
25 paise = \(\frac{25}{100}\) = 0.25
10 rupees + 0.25 paise = 10.25

3. 870 paise = Rs._________
1 rupees = 100 paise
870 = \(\frac{870}{100}\) = 8.70

4. 782 rupees and 10 paise = Rs. _________
1 rupees = 100 paise
782 rupees 782.10 paise

5. 2050 paise = Rs. _________
1 rupees = 100 paise
2050 paise = \(\frac{2050}{100}\) = 20.50

KSEEB Class 5 Maths Decimal Fractions Ex 4.2

I. Write the following fractions as decimal fractions:

What is 11/16 as a decimal? 11/16 as a decimal is 0.6875

1. \(\frac{8}{10}\) = 0.8

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 1

KSEEB Solutions

2. \(\frac{7}{10}\) = 0.7

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 2

3. \(\frac{6}{10}\) = 0.6

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 3

4. \(\frac{16}{10}\) = 1.6

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 4

5. \(\frac{42}{10}\) = 4.2

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 5

6. \(\frac{83}{10}\) = 8.3

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 6

7. \(\frac{7}{100}\) = 0.07

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 7

8. \(\frac{72}{100}\) = 0.72

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 8

9. \(\frac{861}{100}\) = 8.61

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 9

KSEEB Solutions

10. \(\frac{162}{10}\) = 16.2

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 10

11. \(\frac{141}{100}\) = 1.41

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 11

12. \(\frac{1461}{100}\) = 14.61

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 12

13. \(\frac{1}{2}\) = 0.5

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 13

14. \(\frac{3}{4}\) = 0.75

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 14

15. \(\frac{2}{5}\) = 0.4

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 15

16. \(\frac{7}{20}\) = 0.35

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 16

KSEEB Solutions

17. \(\frac{38}{50}\) = 0.76

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 17

18. \(\frac{17}{25}\) = 0.68

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 18

19. \(\frac{13}{20}\) = 0.65

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 19

20. \(\frac{8}{25}\) = 0.32

KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions 20

II. Write the following decimal fractions as fractions:

1. 0.7
\(\frac{7}{10}\)

2. 0.02
\(\frac{2}{100}\)

3. 3.8
\(\frac{38}{10}\)

4. 14.5
\(\frac{145}{10}\)

KSEEB Solutions

5. 0.56
\(\frac{56}{100}\)

6. 8.03
\(\frac{803}{100}\)

7. 14.57
\(\frac{1457}{100}\)

8. 85.4
\(\frac{854}{10}\)

9. 147.5
\(\frac{1475}{10}\)

10. 8.5
\(\frac{85}{10}\)

11. 85.61
\(\frac{8561}{100}\)

12. 6.84
\(\frac{8561}{100}\)

KSEEB Solutions

KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1

Students can Download Chapter 8 Decimals Ex 8.1 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 6 Maths Chapter 8 Decimals Ex 8.1

Question 1.
Write the following as numbers in the given table.
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 1
Solution:
It may be observed that
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 2

Mixed number 2 1/32 to decimal.

Question 2.
Write the following decimals in the place value table
a) 19.4
b) 0.3
c) 10.6
d) 205.9
Solution:
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 3

KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1

How do you write 18 as a decimal? Algebra Conversion of Decimals, Fractions, and Percent.

Question 3.
Write each of the following as decimals:
Solution:
a) Seven – tenths
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 4

b) Two tens and nine – tenths
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 5

c) Fourteen point six
14.6

d) One hundred and two ones
100 + 2 = 102.0

e) Six hundred point eight
600.8

Question 4.
Write each of the following as decimals:-
Solution:
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 6

Rounding to One Decimal Place Calculator will round the value of a number to 1 decimal place accurately and displays the work quickly.

Question 5.
Write the following decimals as fractions. Reduce the fractions to lowest form.
Solution:
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 7

KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1

Question 6.
Express the following as cm using decimals.
Solution:
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 8

KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 9

Question 7.
Between Which two Whole numbers on the number line are the given numbers lie? Which of these Whole numbers is nearer the number?
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 10
a) 0.8
b) 5.1
c) 2.6
d) 6.4
e) 9.1
f) 4.9
Solution:
a) 0.8 lies between 0 and 1, and is nearest to 1.
b) 5.1 lies between 5 and 6, and is nearest to 5.
c) 2.6 lies between 2 and 3, and is nears to 3.
d) 6.4 lies between 6 and 7, and is nears to 6.
e) 9.1 lies between 9 and 10, and is nears to 9.
f) 4.9 lies between 4 and 5, and is nears to 5.

Question 8.
Show the following numbers on the number line.
a) 0.2
b) 1.9
c) 1.1
d) 2.5
Solution:
a) 0.2 :- Represents a print between 0 and 1 on numbers line. Such that the space
between 0 and 1 is divided into 10 equal parts. Hence, each equal part will be equal to one – tenth.
Now 0.2 is the second print between 0 and 1.
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 11

b) 1.9 :- Represents a print between 1 and 2 on number line. Such that the space between 1 and 2 is divided into 10 equal parts. Hence, each part will be equal to one – tenth
Now, 1.9 is the ninth print between 1 and 2.
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 12

c) 1.1 Represents a point between 1 and 2 on number line, Such that the space between 1 and 2 is divided into 10 equal parts. Hence each equal part will be equal to one – tenth Now, 1.1 is the first point between 1 and 2.
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 13

d) 2.5 Represents a point between 2 and 3 on number line, such that the space between 2
and 3 is divided into 10 equal parts. Hence each equal part will be equal to one – tenth Now, 2.5 is the fifth print between 2 and 3.
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 14

KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1

Question 9.
Write the decimal number represented by the points A,B,C,D on the given number line.
Solution:
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 15
Prints A, B, C, D are represents 0.8, 1.3, 2.2, 2.9, respectively

Question 10.
a) The length of Ramesh’s note book is 9 cm 5 mm What will be its length in cm?
b) The length of a young gram plant is 65 mm Express it’s length in cm.
Solution:
a) The length of Ramesh’s note book is 9 cm 5 mm
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 16

b) The length of a gram plant is 65 mm
KSEEB Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.1 17

KSEEB Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Ex 1.1

Students can Download Chapter 1 Algebra Ex 1.1 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 6 Maths Chapter 1 Algebra Ex 1.1

The fifth digit right of the decimal point is the hundred thousandth place where you have to round off.

Question 1.
Fill in the blanks:-
a. 1 lakh = 10 ten thousand
b. 1 million = 10 hundred thousand
c. 1 crore = 10 ten lakh
d. 1 crore = 10 million
e. 1 million = 10 lakh

KSEEB Solutions

Question 2.
Place common correctly and write the numerals :
a. Seventy three lakh seventy five thousand three hundred seven.
73,75,307

b. Nine crore five lakh forty one.
9,05,00,041

c. Seven crore fifty two lakh twenty one thousand three hundred two.
7,52,21,302

d. Fifty eight million four hundred twenty three thousand two hundred two.
58,423,202

e . Twenty three lakh thirty thousand ten.
23,30,010

KSEEB Solutions

Question 3.
Insert comas suitably and write the names according to indian system of numeration:
a. 87595762
Eight crore seventy five lakh ninty five thousand seven hundred sixty two.

b. 8546283
Eighty five lakh forty six thousand two hundred eighty three.

c. 99900046
Nine crore ninety nine lakh forty six.

d. 98432701
Nine crore eighty four lakh thirty two thousand seven hundred one

KSEEB Solutions

Question 4.
Insert commas suitably and write the names according to international system of numeration:

a. 78921092
Seventy eight million nine hundred twenty one thousand ninety two

b. 7452283
Seven million four hundred fifty two thousand two hundred eighty three

c. 99985102
Ninety nine million nine hundred eighty five thousand one hundred two

d. 48049831
Forty eight million forty nine thousand eight hundred thirty one.

KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic

Students can Download Maths Chapter 3 Mental Arithmetic Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 3 Mental Arithmetic

KSEEB Class 5 Maths Mental Arithmetic Revision Exercise

I. Round off each of the following numbers to nearest thousands place:

1. 7,547

7,547 lie between 7000 and 8000
Replace by zero
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 1

2. 3,469
3,469 lie between 2000 and 3000
Replace by zero
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 2

KSEEB Solutions

3. 15,238
15,038
Replace by zero
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 3

4. 32,658
32,658
Replace by zero
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 4

II. Round off each of the following numbers to nearest ten thousands place:

1. 26,674
26,674
Replace to zero
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 5

2. 32,464
32,464
Replace to zero
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 6

3. 46,379
46,379
Replace to zero
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 7

4. 53,668
53,668
Replace to zero
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 8

III. Estimate sum of the following by rounding off to nearest thousands place:

1. 42,125 + 35,637
42,125 is rounded off to nearest thousand – 42,000
35,637 is rounded off to nearest thousand – 36,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 9
Estimate sum is 78,000
Verification by actual addition – 42125
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 10

KSEEB Solutions

2. 54,837 + 41,354
54,837 is rounded off to nearest thousand – 55,000
41,354 is rounded offto nearest thousand – 41,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 11
Estimate sum is 96,000
Verification by actual addition
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 12

3. 33,231 + 20,097
33,321 is rounded off to nearest thousand – 33,000
20,097 is rounded off to nearest thousand – 20,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 13
Estimate sum is 53,000
Verification by actual addition
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 14

4. 47,463 + 41,541
47,463 is rounded off to nearest thousand – 47,000
41,541 is rounded off to nearest thousand – 42,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 15
Estimate sum is 89,000
Verification by actual addition
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 16

IV. Estimate the sum of the following by rounding off to nearest ten thousands place:

1. 56,256 + 24,872
56,256 is rounded off to nearest ten thousand – 55,000
24,872 is rounded off to nearest ten thousand – 25,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 17
Estimate sum is 80,000
Verification by actual addition
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 18

KSEEB Solutions

2. 47,671 + 28,745
47,671 is rounded off to nearest ten thousand – 50,000
28,745 is rounded off to nearest ten thousand – 30,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 19
Estimate sum is 80,000
Verification by actual addition
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 20

3. 32,184 + 45,138
32,184 is rounded off to nearest ten thousand – 30,000
45,138 is rounded off to nearest ten thousand – 50,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 21
Estimate, sum is 80,000
Verification by actual addition
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 22

4. 15,025 + 40,165
15,025 is rounded off to nearest ten thousand – 20,000
40,165 is rounded off to nearest ten thousand – 40,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 23
Estimate sum is 60,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 24

Detailed Steps to Round to Nearest Hundredth by Hand ·

V. Estimate the difference of the following by rounding off to nearest thousands place:

1. 65,487 – 46,502
65,487 is rounded off to nearest ten thousand – 64,000
46,502 is rounded off to nearest ten thousand – 46,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 25
Estimate sum is 18,000
Verification by actual substruction
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 26

KSEEB Solutions

2. 45,630 – 32,148
45,630 is rounded off to nearest ten thousand – 44,000
32,148 is rounded off to nearest ten thousand – 30,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 27
Estimate sum is 14,000
Verification by actual substruction
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 28

3. 57,146 – 25,472
57,146 is rounded off to nearest ten thousand – 56,000
25,472 is rounded off to nearest ten thousand – 24,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 29
Estimate sum is 32,000
Verification by actual substraction
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 30

4. 60,046 – 15,247
60,046 is rounded off to nearest ten thousand – 60,000
15,247 is rounded off to nearest ten thousand – 15,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 31
Estimate sum is 45,000
Verification by actual substraction
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 32

VI. Estimate the difference of thefolhming hy rounding off to nearest ten thousands place:

1. 51,689 – 34,685
51,689 is rounded off to nearest ten thousand – 50,000
34,685 is rounded off to nearest ten thousand – 30,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 33
Estimate sum is 20,000
Verification by actual substraction
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 34

2. 86,853 – 47,829
86,853 is rounded off to nearest ten thousand – 85,000
47,829 is rounded off to nearest ten thousand – 45,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 35
Estimate difference is 40,000
Verification by actual substraction
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 36

KSEEB Solutions

3. 80,808 – 55,055
80,808 is rounded off to nearest ten thousand – 80,000
55,055 is rounded off to nearest ten thousand – 50,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 37
Estimate difference is 30,000
Verification by actual substractiori
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 38

4. 77,777 – 44,444
77,777 is rounded off to nearest ten thousand – 70,000
44,444 is rounded off to nearest ten thousand – 40,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 39
Estimate difference is 30,000
Verification by actual substraction
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 40

VII. Estimate the product of each of the following hy rounding off to its highest place:

1. 428 × 54
428 is rounded off to nearest hundred as 400
54 is rounded off to nearest ten as 50
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 41
Estimate product is 20,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 42

2. 878 × 46
876 is rounded off to nearest hundred as 900
46 is rounded off to nearest ten as 50
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 43
Verification by actual multiplication

Verification by actual multiplication
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 44

3. 5,476 × 11
5,476 is rounded off to nearest hundred as 5000
11 is rounded off to nearest ten as 10
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 45
Verification by actual multiplication

Verification by actual multiplication
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 46

KSEEB Solutions

4. 2,645 × 18
2,645 is rounded off to nearest hundred as 3000
18 is rounded off to nearest ten as 20
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 47
Verification by actual multiplication

Verification by actual multiplication
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 48

VIII. Estimate the quotient of each of the following hy rounding off to its highest place.

1. 398 ÷ 82
398 is rounded off to nearest hundred aS 400
82 is rounded off to nearest ten as ÷ 80
Estimate quotient \(\frac{800}{40}\) = 5

2. 786 ÷ 22
786 is rounded off to nearest hundred as 800
22 is rounded off to nearest ten as ÷ 20
Estimate quotient \(\frac{800}{20}\) = 40

3. 3,265 ÷ 58
3,265 is rounded off to nearest hundred as 3000
58 is rounded off to nearest ten as ÷ 60
Estimate quotient \(\frac{3000}{60}\) = 50

4. 7,687 ÷ 43
7,687 is rounded off to nearest hundred as 8000
43 is rounded off to nearest ten as ÷ 40
Estimate quotient \(\frac{8000}{40}\) = 200

IX. Solve the following problems.

Question 1.
A garment company stitched 16,783 shirts and 12,438 pants in a month. Estimate the total number of dresses stitched to the nearest ten thousands place.
Answer:
A garment company stitched shirts – 16,783
A garment company stitched pants – 12,438.
(To the nearest ten thousand place) – 20,000
(To the nearest ten thousand place) – 10,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 49
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 50

Question 2.
A news paper agent sells 36,721 papers in first month and 24,172 papers in sec¬ond month. Estimate the decrease in sale of the newspaper in second month to the nearest ten thousands place.
Answer:
In first month a news paper agents sells – 36,721
In Second month a news paper agents sells – 24,172
(To the nearest ten thousand place)
first month – 40,000
Second month – 20,000
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 51
The estimated substraction of sale of the newspaper 20,000

KSEEB Solutions

Question 3.
A train can cover 225 km in one hour. Estimate the distance covered in a day to the highest place.
Answer:
A train can cover 225 Km in 1 hour
The distance covered in a day = 24 hours
(To the highest place) 200
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 52

Question 4.
A carpenter earned Rs. 18,634 during the month of November and Rs. 32,645 in December. Estimate how much more he earned in December to the nearest ten thousands place.
Answer:
A carpet earned in november – 18,634
A carpet earned in december – 32,645
(To the nearest ten thousand place)
KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic 53

KSEEB Solutions

KSEEB Solutions for Class 9 Science Chapter 8 Motion

Students can Download KSEEB Solutions for Class 9 Science Chapter 8 Motion, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.

Karnataka Board Class 9 Science Chapter 8 Motion

KSEEB Solutions for Class 9 Science Chapter 8 Intext Questions

Our Displacement Calculator helps determine your engine’s size by its bore and stroke. This is a very useful tool for building high-performance racing engines.

Question 1.
An object has moved through a distance can it have zero displacement? If yes, support your answer with an example.
Answer:
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 1
In the figure distance of an object moved from 0 to A is 60 km and distance travelled is 60 km and displacement is 60 km. From 0 to A and back to B, distance travelled is 60 km + 25 km = 85 km. But displacement (35 km) is not equal to distance travelled (85 km). If we observe like this, displacement of a body is zero, but distance travelled is not zero, starting from point ‘0’ and returning back to ‘O’ final position is mixing with initial point. Hence displacement is zero.

Displacement Calculator is a free online tool that displays the displacement of a given object.

Question 2.
A farmer moves along the boundary of a square field of side 10 m in 40s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
Answer:
A farmer moves along the boundary of a square field of side 10 m in 40s
2 minutes 20 seconds means 140 seconds.
Distance travelled by farmer
= \(\frac{40}{40}\) × 140 m
= 140 m.
∴ Farmer moves for 2 minutes 20 seconds. It means \(\frac{140}{40}\) = 3.5 rounds
From the original point, he moves for 2 minutes 20 seconds.
Case i)
Original point means any point in the corner of the field. In this case he moves for 2 min 20 seconds from the diagonal of the field.
Displacement is equal to diagonal of the field displacement
= \(\sqrt{10^{2}+10^{2}}\)
= 14.1 m.
Case ii)
Original point means any point in the middle of the side of the field.
∴ Displacement is equal to any side of the field = 10 m.
It means displacement is between any original point ie in between 14.1 m and 10 m.

Question 3.
Which of the following is true for displacement?
a) It cannot be zero.
b) Its magnitude is greater than the distance travelled by the object.
Answer:
b) Its magnitude is greater than the distance travelled by the object.

Question 4.
Distinguish between speed and velocity
Answer:

Speed Velocity
1. Scalar quantity Vector quantity
2. Distance travelled in a given time. Distance travelled along with a path with the given time.
3. It is always is + ve. It is + ve or – ve

Average velocity calculator is really nice tool to use and it will help you solve all your problem related to average velocity.

Question 5.
Under what condition (s) is the magnitude of the average velocity of an object equal to its average speed?
Answer:
If the speed of the object changing uniformly, the magnitude of the average velocity of an object equal to its average speed.

Question 6.
What does the odometer of an automobile measure?
Answer:
Odometer measures the speed of the vehicle.

Question 7.
What does the path of an object look like when it is in uniform motion?
Answer:
When the object is in uniform motion, it covers equal distance at equal intervals of time.

Question 8.
During an experiment, a signal from a spaceship reached the ground station in five minutes. What was the distance of the spaceship from the ground station? The signal travels at the speed of light, which is 3 × 10 ms-1.
Answer:
Time taken by the signal to reach the ground station from the spaceship = 5 min = 5 × 60 = 300 seconds
Speed of the signal = 3 × 108 m/s.
Speed = \(\frac{\text { Total distance travelled }}{\text { Total time taken }}\)
∴ Distance travelled = speed × time taken
= 3 × 108 × 300
= 9 × 1010m
∴ Distance of change of velocity = 9 × 1010 m

A versatile acceleration calculator with which you can calculate the acceleration given initial and final speed and acceleration time.

Question 9.
When will you say a body is in

  1. Uniform acceleration?
  2. non-uniform acceleration?

Answer:

  1. If the object covers equal distances in equal intervals of time, it is added to be in uniform motion.
  2. If the object covers unequal distances in equal intervals of time, it is said to be in non-uniform motion.

Question 10.
A bus decreases its speed from 80 km h-1 to 60 km h-1 in 5s. Find the acceleration of the bus.
Answer:
Initial velocity of the bus u = 80 kmh-1
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 2
Final velocity, V = 60 km/h
time taken to decrease the velocity of bus, t = 5 seconds
acceleration, a = 5 seconds
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 2.1
= -1.112 ms-2.

Question 11.
A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h-1 in 10 minutes. Find its acceleration.
Answer:
Initial speed of the train u = 0
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 3
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 3.1
∴ acceleration of a train = 0.0185 ms-2.

Question 12.
What is the nature of the distance-time graphs for uniform and non-uniform motion of an object?
Answer:
(i) The nature of the distance-time graphs for the uniform motion of an object is a straight line.
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 4
(ii) The nature of tire distance time graph for non-uniform motion is curved line.
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 4.2
Distance-time graph for a car moving with non-uniform speed

Question 13.
What can you say about the motion of an object whose distance-time graph is straight line parallel to the time axis?
Answer:
This graph indicates the object is at rest.

Question 14.
What can you say about the motion of an object if its speed-time graph is a straight line parallel to the time axis?
Answer:
This graph indicates the object is in uniform motion.

Question 15.
What is the quantity which is measured by the area occupied below the velocity-time graph?
Answer:
The quantity which is measured by the area occupied below the velocity-time graph is length = l

Question 16.
A bus starting from rest moves with a uniform acceleration of 0.1 ms-2 for 2 minutes. Find
(a) the speed acquired,
(b) the distance travelled.
Answer:
(a) Initial velocity of the bus u = 0 (Bus is at rest).
acceleration, a = 0.1 ms-2
time t = 2 minutes = 120 seconds
Let the speed of bus be ‘V’
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 5
∴ v = 12m/s
(b) As per third law of motion:
v2 – u2 = 2as
(12)2 – (0)2 = 2(0. 1)s
∴ s = 720 m.
the speed of acquired by bus = 12 m/s.
the distance travelled = 720 m.

Question 17.
A train is travelling at a speed of 90 kmh-1 Brakes are applied so as to produce a uniform acceleration of -0.5 ms-2. Find how far the train will go before it is brought to rest.
Answer:
Let the initial speed of the train be u = 90 Km/h
= 25 m/s.
Final speed of the train, v = 0 (train comes to rest)
acceleration a = 0.5 ms-2
As per 3rd law of motion
v2 = u2 + 2as
(0)2 = (25)2 + 2(0.5)s
s = train travelled distance
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 6
Train will travel 625 km before it is brought to rest.

Question 18.
A trolley, while going down an inclined plane has an acceleration of 2cms-2 what will be its velocity 3s after the start?
Answer:
Initial velocity of a trolley, u = 0 (at rest)
acceleration, a = 2 cms-2 = 0.02 m/s2 time t = 3S
As per 1 st law of motion
v = u + at
Here V means velocity of a trolley after 3 s
V = 0 + 0.02 × 3
= 0.06 m/s.
∴ = 0.06 m/s.

Question 19.
A racing car has a uniform acceleration of 4ms-2, what distance will it cover in 10s after start?
Answer:
Initial velocity of a racing car, u = 0 (at rest)
acceleration, a = 4 m/s2
time t = 10 s
As per second law of motion
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 7
Here S means distance travelled by car after 10S
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 7.1
∴ Distance covered by car after 10 S = 200 m.

Question 20.
A stone is thrown in a vertically upward direction with a velocity of 5ms-1 If the acceleration of the stone during its motion is 10ms-2 in the downward direction, what will he the height attain by the stone and how much time will it take to reach there?
Answer:
The initial velocity of a stone, u = 5 ms-1.
Final velocity of a stone v = 0 (at rest)
If the acceleration of the stone during its motion is = -10ms-2.
Let the maximum height be ‘s’
v = u + at
0 = 5 + (-10)t
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 8
time taken by stone = 0.5s
As per 3rd Law of motion
v2 = u2 + 2as
(0)2 = (5)2 + 2(-10)s
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 8.1
The height attained by the store = 1.25 m.

KSEEB Solutions for Class 9 Science Chapter 8 Textbook Exercises

Question 1.
An athlete completes one round of a circular track of diameter 200 m. in the 40s. What will be the distance covered and the displace¬ment at the end of 2 minutes 20s?
Answer:
Diameter of circular track, d = 200 m.
radius of the circular track,
r = \(\frac{\mathrm{d}}{2}\) = 100m
Circumference = 2πr = 2p(100) = 200πcm.
in 40s, athlete covers distance 200πm
in 1s, distance covered by athlete = \(\frac{200 \pi}{40}\) m
Athlete runs for 2 minutes 20s means 140s
∴ Displacement of all athlete is equal to the diameter of circle
= \(\frac{200 \times 22}{40 \times 7}\) × 140
= 2200 m
∴ Displacement = 200 m.

Question 2.
Joseph jogs from one end A to the other end B of a straight 300 M road in 2 minutes 30 seconds and then turns around and jogs 100 M back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from A to C?
Answer:
a) from A to B distance covered by Joseph = 300 M.
Time taken to cover this distance
= 2 min 30 sec. = 150 seconds
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 9
Displacement = Nearest distance between A and B = 300 m.
Time taken = 150s
Average velocity = ygy = 2 m/s.

b) From A to C :
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 10
Total distance covered = Distance between A to B + distance between B to C
= 300 + 100 = 400 m.
Total time taken to cover from A to B + Time taken to cover from B to C
= 150 + 60= 210s.
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 21
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 11
Displacement from A to C
= AC + AB – BC
= 300 – 100
= 200m
Total time taken = Time taken to travel from A to B + Time taken to travel from B to C
= 210 s
∴ Average velocity = \(\frac{200}{210}\) =0.952 ms-1 .

Question 3.
Abdul, while during to school, computes the average speed for his trip to be 20Kmh-1 on his return trip along the some route, there is less traffic and the average speed is 30 Kmh-1. What is the average speed for Abdul’s trip?
Answer:
i) Average speed of Abdul’s trip while driving to school = 20 Kmh-1
Average speed = \(\frac{\text { Total distance }}{\text { Total time taken }}\)
Total distance = Distance travelled to reach school = t1
∴ 20 = \(\frac{\mathrm{d}}{\mathrm{t}_{1}}\)
t1 = \(\frac{d}{20}\) …………… (i)
While returning from school
Total distance = Distance travelled while returning from school = d Now total time taken = t2.
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 12

Question 4.
A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 ms-2 for 8.0 s. How far does the boat travel during this time?
Answer:
Initial velocity of motor boat, u =0
(at rest) ,
Accieratlon of a motor boat a = 3m/s2
Time taken, t = 85
According to second equation of motion, s
S = 0 +\(\frac{1}{2}\) × (8)2 = 96m.
∴ Motorboat travels = 96m.

Question 5.
A driver of a car travelling at 52kmh-1 applies the brakes and accelerates uniformly in the opposite direction. The car stops in 5s. Another driver going at 3kmh-1 in another car applies his brakes slowly and stop In 10s. on the same graph paper. Plot the speed versus time graphs for the two cars, which of the two cars travelled farther after the brakes were applied?
Answer:
initial velocity of A car u1 = 52 kmh-1
= 14.4 m/s.
Time taken to stop car t1 = 5 s.
After 5s car comes to rest Initial velocity of B car, u2 = 3Kmh-1
= 0.833 m/s. = 0.83 m/s.
Time taken to stop car t2 = 10s
After 10s car comes to rest.
Graph:
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 13
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 14
Area of ∆OPR = Area of ∆OSQ
When compared car A to car B, A car travelled father. After brake it travels 52 Kmh-1

Question 6.
Fig 8.11 shows the distance-time graph of three objects A, B and C. Study the graph and answer the following questions.
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 15
a) Which of the three is travelled the fastest?
b) Are all three ever at the same point on the road?
c) How far has C travelled when B passes A?
d) How far has B travelled by the time passes C?
Answer:
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 16
Slope of B object is greater than slopes A and C. This is travelling fastest.

b) All three objects never meet at a point, hence these are not at the same point.

c) There are 7 boxes in X-axis = 4 Km
1 box = \(\frac{4}{7}\) Km
In the beginning, C object is 4 boxes away from 0
= \(\frac{16}{7}\) km
Distance to C from origin = Distance of C when it moves from B to A =8 Km
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 18
∴ Distance travelled by C when B passes A = 5.714 km.

d) Distance B travelled by the time it passes C = 9 boxes
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 19
∴ B has travelled 5.143 k.m. by the time when it passes C.

Question 7.
A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10ms-1 with what velocity will it strike the ground? After what time will it strike the ground?
Answer:
Distance ball covers, S = 20 m
acceleration, a = 10Kmh-1 = 10 m/s
initial velocity, u = 0 (at rest)
When ball strikes, its final velocity,
According to 3rd law of motion
v2 = u2 + 2as
v2 = 0 + 2(10)(20)
v = 20 m/s.
According to 1 st Law of motion v = u + at
Time taken by ball to strike the ground, t,
20 = 0 + 10 (t)
∴ t = 2s
∴ 2s is required to ball for striking the ground and velocity is 20 m/s

Question 8.
The speed-time graph for a car is shown in figure
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 17
a) Find how far does the car travel in the first 4 seconds. Shade the area on the graph that represents the distance travelled by car during the period.
b) Which part of the graph represents uniform motion of the car?
Answer:
a) Shade lightly in the graph about distance travelled by car in 4s.
b) Shade with red colour about 6 cm to 10 cm. It represents the uniform motion of the car.

Question 9.
State which of the following situations are possible and give an example for each of these;
a) an object with a constant acceleration but with zero velocity.
b) an object moving in a certain direction with an acceleration in the perpendicular direction.
Answer:
a) This is possible
Eg: when a ball is thrown to a height its velocity is zero.
(For a ball G = 9.8 m/s2)

b) This is possible
Eg: when a car moves in a curved line, its acceleration is perpendicular to the given direction)

Question 10.
An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth.
Answer:
Satellite is moving in circular orbit radium of satellite r = 42250 km
time t = 24 Hrs = 3600 × 24 S
KSEEB Solutions for Class 9 Science Chapter 8 Motion Q 20
∴ Speed of the satellite when it moves in circular orbit = 3.07 kms-1.

Mile calculator. Enter your route details and price per mile, and total up your distance and expenses

KSEEB Solutions for Class 9 Science Chapter 8 Additional Questions

Fill in the blanks with suitable words.

Question 1.
The two physical quantities required to know final position of an object are _________ and _________
Answer:
Distance travelled, displacement.

Question 2.
S.I. unit of speed is ________
Answer:
m/s

Question 3.
Distance travelled by the object in unit time is ________
Answer:
Speed.

Question 4.
If acceleration is in the direction of velocity it is _________ acceleration.
Answer:
positive.

Question 5.
When an object moves in a circular path with uniform speed, its motion is called ________
Answer:
uniform circular motion.

Answer the following questions:

Question 1.
Give an express10n for centripetal force?
Answer :
\(f=\frac{m v^{2}}{r}\)

Question 2.
What is uniform circular mot10n?
Answer :
Body moving in a circular path arbitrary any instant along a tangential to the posit10n of the body on the circular path at that instant or time.

Question 3.
A body falls freely. What is constant?
Answer :
When the body falls freely. It has a constant acceleration.

Question 4.
Define uniform speed.
Answer :
The speed of an object is said to be uniform speed if it travels equal distances in equal intervals of time.

2nd PUC English Textbook Answers Springs Chapter 8 To the Foot from its Child

You can Download To the Foot from its Child Questions and Answers Pdf, Notes, Summary, 2nd PUC English Textbook Answers, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.

Karnataka 2nd PUC English Textbook Answers Springs Chapter 8 To the Foot from its Child

To the Foot from its Child Questions and Answers, Notes, Summary

To the Foot from its Child Comprehension I

Come find me on feet finder! I’m a newby foot gal and just uploaded my first album.

Question 1.
What would the foot like to be?
OR
Mention one of the things that the child’s foot likes to be.
Answer:
The foot would like to be a butterfly or an apple.

Question 2.
‘The child’s foot is not yet aware it’s a foot’ (line 1 of the poem) conveys
a. the immense possibilities of life
b. the unrestricted nature of a child’s imagination
c. the child’s ignorance of harsh realities.
Answer:
(b) and (c) the unrestricted nature of a child’s imagination/the child’s ignorance of harsh realities.

Question 3.
What does time teach the child?
Answer:
Time teaches the foot that it cannot fly and also cannot be a fruit on the branch of a tree.

Question 4.
The line ‘stones and bits of glass, streets, ladders and the paths in the rough earth’
a. indicates hardships one has to face in life.
b. provides a mere description of a road.
c. suggests the good and bad experiences of growing up.
Answer:
(a) indicates hardships one has to face in life.

Question 5.
Why does the child’s foot feel defeated?
Answer:
The child’s foot feels defeated because it has to live like a prisoner, condemned to live in a shoe, and it can never be free to escape from the difficulties of life.

KSEEB Solutions

Question 6.
Mention the words that convey the real experiences of the foot.
Answer:
The words ‘stones and bits of glass, streets, ladders, and the paths in the rough earth’ convey the real experiences of the child’s foot.

Question 7.
Identify the lines in the poem that suggest the transformation of the foot.
Answer:
Lines 17 – 28 suggest the transformation of the foot.
“These soft nails
of quartz ………
…………………….
……………………
a coarsening hard to accept.”

Question 8.
“….. condemned to live in a shoe” suggests that the foot is
(a) a prisoner
(b) a criminal
(c) forced to give up its dreams.
Answer:
(a) and (c) a criminal/forced to give up its dreams.

Question 9.
What does the line ‘until the whole man chooses to stop’ mean?
OR
When does the foot stop to walk in Neruda’s poem?
Answer:
The line, ‘until the whole man chooses to stop’ means until the person dies.
OR
The foot stops to walk when the person dies.

To the Foot from its Child Comprehension II

Question 1.
We think of a foot as a part of the human body, but Neruda says ‘To the Foot From its Child’. Why?
Answer:
We think of a foot physically as belonging to a person but Neruda sees in a philosophical way and says “To The Foot From Its Child”. Though it belongs to a person physically, philosophically like the child who is the symbol of innocence, the foot also does know about its future. But in adulthood, it faces many challenges of life and gets an overall experience and leads a meaningful life until the end. Finally, it is attacked by diseases and surrendered to death.

Question 2.
Pick out the expressions that suggest the child’s imagination is fertile.
Answer:
The expressions, ‘to be a butterfly’, or ‘an apple’, ‘can not fly’, ‘cannot be a fruit bulging on the branch’ suggest that the child’s imagination is fertile.

Question 3.
What contrasting descriptions of the foot does the poem offer? Why?
Answer:
The poet Pablo Neruda presents a contrasting description of a child’s foot and an adult’s foot so as to delineate the changes that are seen in a person’s life as he or she changes from an infant into an adult, until his death. Initially, the child or the infant’s foot has soft nails of quartz and its toes are tiny, soft, and rounded at the tips like the petals of some flowers.

As the child learns to walk and starts walking on stones, bits of glass, streets, ladders and the rough surface of the earth, the child’s foot becomes aware of its role. It learns that it is a foot and cannot become a butterfly or a bulging fruit on a tree. Once it realizes that it is a foot, it is defeated in realizing its aspirations and gets imprisoned in a shoe. Inside the shoe, it tries to understand the world in its own way, alone, like a blind man groping in the dark. During this period its soft nails of quartz become opaque, are bunched together, and look like eyeless reptiles with triangular heads, grow callused, and are covered with faint volcanoes of death.

KSEEB Solutions

These changes happen because, once the child’s foot becomes an adult’s foot, it walks as the foot of a man or woman and keeps walking in the fields as a farmer, or as a grocer in the markets, or as a miner in the mines or as a church minister or a government worker, until its death. Thus, the foot experiences the hardships of life and loses its ‘soft’ and flowery petal-like form.

Question 4.
The poem begins with the idea that a child’s foot is not yet aware that it is afoot; at the end, the foot is unaware that it had ceased to be afoot. What is the poet trying to convey through these statements?
OR
Explain the similarity between the foot’s early life and its end as depicted in ‘To the Foot From its Child’.
Answer:
In this poem, ‘foot’ is a metaphor for ‘life’. The poet Neruda using the foot as a metaphor to explore ‘life’ through its various stages from infancy through childhood until death.

When the poem begins, the ‘foot’ is the infant’s foot which suggests man’s ‘childhood’. The child’s foot does not know that it is a foot. This state refers to the innocence of childhood where ‘Man’ has many dreams and aspirations. The child’s wish to become a butterfly or an apple stands for man’s aspirations and dreams. Once the child’s foot enters the real world, it starts walking over stones, bits of glass, streets, ladders, and the rough surface of the earth.

Thus, as the child grows over a period of time, the child’s foot realizes that it is only a ‘foot’ and cannot become fruit or a butterfly. Then, since it has to serve its role as afoot, it is imprisoned in a shoe. Inside the shoe, it tries to understand the world alone, in isolation. The child’s foot, as it grows old, serves as the foot of a man or a woman working in the fields, or market or mines or ministries and toils hard day and night until it dies. When it dies, the foot loses its human awareness and that is why when it is buried the foot again gets its child-like innocence. It again dreams of becoming an apple or a butterfly. It is this journey from childhood through adulthood and the final death that the poem focuses on.

Pablo Neruda is saying that life and death are part of a continuous cycle. Secondly, the poet wishes to say that the freedom of childhood is lost when a person becomes an adult and faces a life of constant work and struggle. Thus, life takes away people’s free spirits until they are freed again by death.

Question 5.
How does Neruda describe the busy life of the individual as represented by the foot?
Answer:
The ‘foot’ is used as a metaphor for life and the foot refers to the foot of an individual. Once the child develops into an adult, the adult keeps on walking without respite either as a man or as a woman. The individual spends his life working either as a farmer in a field, or as a miner in mines, or as a salesperson in the market or as a government servant or as a church minister. This way the individual toils hard in society until his death.

Question 6.
What does the last stanza of the poem mean? Can you think of parallels in nature?
Answer:
In this poem, ‘foot’ is used as a metaphor for ‘life’. Life refers to the life of a human being as seen from his infancy until his death. Pablo Neruda gives his view of ‘life’ and ‘death’ in this poem. The poem does not begin with the beginning of life in the womb of its mother but from the time after it has taken birth on the earth. The poem covers the period of its infancy to death and beyond. The ‘foot’ as portrayed in the poem refers to the child’s foot. Since a child is not aware of its limitations and lives in a dream world of imagination, the child’s foot wishes to fly like a butterfly or become a bulging apple on the branch of a tree. Over a period of time, it realizes that it is only a foot and its role is only to serve as a foot.

The poet then refers to the ‘adult food’ after death or an individual after death. Once a human being dies, he or she is normally buried. It is this burial of the dead body of the individual that is expressed in the line “it descended underground unaware, for there, everything was dark”. Once the ‘foot’ or the individual dies, it loses its human awareness and goes back to its child-like innocence. This is expressed in the sentence ‘It never knew it had ceased to be a foot’. That is why, like a child’s foot which is not aware that it is only a ‘foot’, it aspires to become a butterfly and fly or become an apple.

KSEEB Solutions

One can find several parallels in nature. All living beings born on the earth pass through the cycle of birth and death. A seed germinates to give a seedling. The seedling grows into an adult plant, may become a tree or a shrub, and die. Its seeds bring a similar plant to life again. Similarly, the eggs of animals hatch and bring forth their young ones which grow, mature, lay eggs and later die. Their eggs bring back similar animals to life again.

To the Foot from its Child Comprehension III

Question 1.
Examine how Neruda’s poem works out the contrast between colourful dreams and the humdrum reality of life.
OR
The poem ‘To the Foot From its Child’ represents the conflict between illusion and reality. Elaborate.
Answer:
The poem, ‘To the Foot from its Child’, presents a contrast between colourful dreams and the humdrum reality of life. The poet conveys his view of life through his description of a foot. The foot is a metaphor for expressing the crushing of a child’s spirit through the challenges and restrictions that life places upon him. One can undoubtedly infer that the poem is basically a criticism of how people force children to grow in society and forget all their dreams and imaginations.

With a view to delineating the forces that capture the child’s freedom and aspirations, the poet begins the poem making a statement directly that the child’s foot, which is not aware that it is a foot, would like to be a butterfly or an apple. From this one can infer that man’s spirit dreams of enjoying unlimited freedom in this world but it comes to know that it cannot enjoy unlimited freedom and has to pass through several obstacles before it matures into an adult.

But, in time, stones and bits of glass, streets, ladders, paths in the rough earth go on teaching the foot that it cannot fly. As the infant is growing and developing into a mature adult, he is exposed to the harsh realities of life which are metaphorically expressed as stones, bits of glass, ladder, street, etc. These are the problems and obstacles an individual has to face. Thus, once the child becomes a boy, an adolescent, and an adult, the problems of life teach the individual that he is a ‘mortal’ and his powers are limited and can only serve the society as a member like other human beings. This sense is expressed in the line ‘that it cannot fly, cannot become a fruit and is defeated, falls in the battle, is a prisoner condemned to live in a shoe’. Here, the ‘shoe’ can be taken to mean the human society that regulates his mind and activities.

Wearing the shoe refers to the infant becoming a mature adult. Soon after entering adulthood, the individual explores ‘life’ within the shoe. He loses touch with the reality of the outside world but experiences the world through the eyes of society. This again means that a lot of restrictions are imposed on the individual. Now that he is an adult he keeps on walking without respite through the fields, mines, markets, and ministries. The line ‘this foot toils in its shoe, scarcely taking time to bare itself in love or sleep’ expresses the fact that once he realizes that he is a man destined to live in a society, he learns to face the humdrum realities of life. He has no time to let his human spirit indulge in ‘love’ and ‘sleep’. He is a prisoner and keeps on working until he dies. Once he dies his spirit loses its human awareness and is once again as free as the children.

Question 2.
Neruda’s poem is a salute to the ordinary human being, who continues with life braving all odds. Do you agree? Give reasons.
Answer:
Yes. In this poem, Neruda tries to delineate the journey of human ‘life’ from its infancy to death and beyond. With a view to expressing the changes that the ‘life spirit’ undergoes through its journey from an infant to an adult and beyond death, Neruda uses ‘foot’ as a metaphor. That is why he calls ‘life’ during infancy as the infant foot and the life spirit of an adult as the adult foot.

The whole poem can be summed up as the ‘surrender’ of life force to societal pressures. During infancy, the child’s spirit dreams of infinite possibilities and hence dreams of becoming a fruit or a butterfly. Once it starts growing in society the harsh realities of life expressed as ‘stones, bits of glass, ladder, and rough surface of the earth’, teach the infant spirit that it is a ‘foot’ which means ‘you have a role’ to play in the society and ‘you are an individual subservient to the whims and fancies of the society’. Once the infant spirit gradually accepts its defeat and tries to live in conformity with the norms of the society, it becomes an adult. This is expressed metaphorically as the ‘foot being imprisoned in a shoe’.

Once you become a member of the society you learn to live like others, giving up your pleasures and gradually you get to know the realities of life. You go on slogging throughout your life without indulging in ‘love and sleep’ which symbolically represent your rights on this earth. You forego your rights and live like an adult and serve the society until you die and you get your freedom after your death. As long as your life spirit is in your body you have human awareness and you are aware of your limitations. Once you die you lose human awareness and your spirit is free to enjoy its freedom.

In the poem, Neruda does not speak of the possibilities of the human spirit ‘rebelling’. Nor does he say that human spirit is being crushed by oppressive forces; the human spirit does not commit suicide. On the contrary, he describes the journey of the human spirit as an infant’s foot until it becomes an adult foot and after its death how it becomes free again. From this, it can be argued that Neruda’s poem is a salute to the human spirit for braving all odds and completing one’s cycle of life and death peacefully, and not rebelliously.

Question 3.
Is Neruda criticizing how society crushes childhood dreams and forces people into rigid moulds?
OR
“Society crushes dreams of individuals and condemns them to live in captivity.” Explain with reference to ‘To the Foot from its Child’.
Answer:
Yes, to some extent. In this narrative-descriptive poem, Neruda has attempted to delineate the predicament of man as a prisoner enslaved by society. Using ‘foot’ as a metaphor for ‘life’, he narrates the journey of life from that of an ‘infant foot’ to an ‘adult foot’ until its death and after. In the first two lines itself, the poet declares the wish of childhood. The infant’s foot is not aware that it is a ‘foot’ and hence would like to be a butterfly or an apple. These two objects – ‘butterfly’ and ‘apple’ – together suggest that the infant’s foot thinks of complete freedom to become whatever it wants. Being born a human being it cannot aspire to become a butterfly or an apple.

KSEEB Solutions

From this, we can infer that there is some restriction imposed on us by birth itself. This is expressed in the line ‘it is not aware that it is afoot’. The infant food, once it starts growing, is exposed to the ways and means of the world. We live in human society and nature, the words ‘stones, bits of glass, streets, ladders, and the paths in the rough earth’ refer to man’s ways of living. This exposure to man’s style of living brings awareness in the child that it is a foot. The poet suggests that the infant’s foot is engaged in a battle with the society and ‘adults’ crush the child’s playful spirit and imprison it in a shoe. This stage refers to the way the child gets acclimatized to living in human society.

Once it wears the ‘shoe’, which means, it accepts its identity as ‘man’, a member of the human society, he starts exploring the human world alone, groping in the dark like a blind man. There is a difference in the way an adult explores the world. As a child, it thinks of infinite possibilities; but, as an adult, it is aware of its limitations. This means the society has been successful in crushing childhood dreams and forcing the life spirit into the rigid moulds of society.

Since the whole poem only describes various changes undergone by the human spirit, we cannot say that Neruda is criticizing society for its stranglehold on the human spirit. Secondly, Neruda also says that the child’s foot does not know that it is a foot. This means, even Neruda knows that the child is born a human being and is going to live in human society. Thirdly, nowhere in the poem does Neruda say anything against societal forces. However, Neruda sympathises with ‘Man’ at one point. He says, ‘this foot toils in its shoe scarcely taking time to bare itself in love or sleep’. These lines indicate that Neruda only sympathises with man’s predicament and does not criticize society.

Question 4.
‘Foot’ is a keyword in the poem. Comment on Neruda’s skillful use of the word and its associations in terms of imagery to convey his ideas.
OR
Highlight the imagery used to bring out life’s hardships that deform the child’s foot.
Answer:
In this poem, as the title ‘To the Foot from its Child’ suggests, ‘foot’ is the keyword in the poem. The poet uses ‘foot’ as a metaphor for his view of ‘life’. The poet personifies the ‘foot’ and focuses his attention on the ‘life’ of man, using the ‘foot’ as the protagonist. ‘Life’ begins in infancy and so even in the poem, ‘life’ begins as an infant’s foot.

It is natural that children, who are naive and innocent, do not know that their foot is meant for walking and it has a function to discharge. Through the use of the ‘foot’ as a metaphor, the poet cleverly brings out the battle between harsh realities of life symbolically expressed as stones, streets, ladder, bits of glass, etc. The child dreams of becoming a butterfly or an apple. So naturally, the metaphor of foot helps the poet to convey his meaning through an imaginary battle fought between the child’s foot and the surfaces on which the child is likely to walk.

The child’s foot is sure to be hurt when it walks on a street laden with stones and bits of glass and paths in the rough earth and when it climbs the ladder pressing his soft foot on the pointed edges of the rungs of the ladder. Then it realizes that it is a ‘foot’. Here, the poet wants the reader to know that the adult world fights against the spirit of the child and makes him become aware of his role as an individual in human society. At this stage, the foot is imprisoned in a shoe, which means, the child’s consciousness reaches maturity and adulthood.

Adulthood is now represented as ‘adult foot’ enclosed in a shoe. The adult foot gropes in the dark and learns about the harsh realities of life like a blind man. Here, it means, unlike the child’s foot which had more .freedom than the adult’s, the adult foot has to work in a rigid mould given by the society. The ‘shoe’ represents this framework given by society. Here again, the ‘foot’ as a metaphor comes to his help. Therefore, the poet chooses ‘shoe’ as representing societal norms and traditions.

KSEEB Solutions

The blind adult foot now walks and works without respite until he dies. The different professions of men are mentioned. The adult foot may be a man’s foot or a woman’s foot and keeps walking through fields, markets, mines, and ministries, and finally toils hard scarcely finding time to enjoy ‘love’ and ‘sleep’. Here also the metaphor of the ‘foot’ facilitates the expression in the line ‘scarcely taking time to bare itself in love or sleep’. Finally, it ceases to be a ‘foot’ when a man chooses to stop working. Thus, the ‘foot’ as a metaphor has been skillfully used by the poet to evoke the right imagery to suit his meaning.

To the Foot from its Child Additional Questions and Answers

I. Answer the following questions in a word, a phrase, or a sentence each:

Question 1.
What did the foot find when it descended underground?
Answer:
Everything to be dark (or darkness).

Question 2.
What would like to be a butterfly or an apple in the poem ‘To the Foot from its Child’?
Answer:
Foot/Child’s foot.

Question 3.
What does the foot do throughout life?
OR
Mention any one of the places through which the foot walks, in ‘To the Foot from its Child’.
Answer:
Throughout its life, the foot keeps walking without respite. It walks through fields, mines, markets, and ministries until death.

Question 4.
What does the phrase ‘condemned to live in a shoe’ mean?
Answer:
The phrase ‘condemned to live in a shoe’ means it has to live like other human beings, in human society.

Question 5.
Where did the foot descend after it ceased to be?
Answer:
It descended underground.

Question 6.
What did the foot find when it descended underground?
Answer:
When the foot descended underground, it found everything dark there.

Question 7.
What form do the detailed toes of a child take on as they grow?
OR
What form do the petal-like soft toes take inside the shoes?
Answer:
The petaied toes of a child grow bunched and out of trim, take on the form of eyeless reptiles with triangular heads, like worms.

KSEEB Solutions

Question 8.
What do the soft nails of quartz change themselves into?
OR
How do the soft nails of the foot change as the child grows up?
Answer:
The ‘soft nails of quartz’ in the child’s foot gradually grow hard and change themselves into an opaque substance ‘hard as horn’.

Question 9.
Where is the child’s foot condemned to live?
OR
Where is the defeated foot condemned to live?
Answer:
The child’s foot is condemned to live in a shoe.

Question 10.
What teaches the foot that it cannot fly?
Answer:
As the child’s foot grows in time and starts walking on stones and bits of glass, streets, ladders, etc., it learns that it cannot fly.

Question 11.
Where did the foot descend?
Answer:
The foot descended underground after its death.

Question 12.
What does the foot not realize at the end of the poem?
Answer:
At the end of the poem, the foot does not realize that it is dead and has ceased to be a foot.

Question 13.
What, according to the speaker, is the child’s foot not yet aware in ‘To the Foot from its Child’.
Answer:
In ‘To the Foot from its Child’, the child’s foot is not yet aware that it is a foot.

Question 14.
What is out of touch with its fellow in the poem, ‘To the Foot from its Child’?
Answer:
In the poem, ‘To the Foot from its Child’, the child’s foot is out of touch with its fellow.

Question 15.
Who feels out life like a blind man in the poem, ‘To the Foot from its Child’?
Answer:
The child’s foot having been imprisoned in a shoe feels out life like a blind man.

Question 16.
What are the toes of the child compared to, in ‘To the Foot from its Child’?
Answer:
In ‘To the Foot from its Child’, the tiny toes are compared to the petals of a flower.

Question 17.
What does the blind thing refer to, in ‘To the Foot from its Child’?
Answer:
In ‘To the Foot from its Child’, the blind thing refers to the child’s foot imprisoned in a shoe.

KSEEB Solutions

Question 18.
Mention any one of the places through which the foot walks, in ‘To the Foot from its Child’.
Answer:
In ‘To the Foot from its Child’, the foot walks through markets.

Question 19.
How long does the foot walk, in ‘To the Foot from its Child’?
Answer:
In ‘To the Foot from its Child’, the foot walks until the whole man chooses to stop and descends underground.

Question 20.
In ‘To the Foot from its Child’, the foot scarcely takes time to bare itself in
(a) rest or peace
(b) love or sleep
(c) death or dream.
Answer:
(b) love or sleep.

Question 21.
In ‘To the Foot from its Child’, when descending underground, the foot finds everything
(a) dark
(b) rough
(c) coarse.
Answer:
(a) dark.

Question 22.
In ‘To the Foot from its Child’, the paths in the rough earth go on teaching the foot that it cannot
(a) become a butterfly
(b) bunch together
(c) live in a shoe.
Answer:
(a) become a butterfly.

II. Answer the following questions in a paragraph of 80-100 words each:

Question 1.
Bring out the contrast between illusion and reality in ‘To the Foot from its Child’.
Answer:
Pablo Neruda presents his view of ‘life’ using the ‘foot’ as a metaphor for life. He explores life’s experiences as a traveller beginning as a child’s foot until it grows into an adult foot and finally dies. During the course of this journey from life to death as a cycle, the poet tries to delineate man’s ‘dreams’ and how they get crushed in the world by outside forces.

Initially, the infant’s foot is unaware that it is a ‘foot’ and is under the illusion that it can fly like a butterfly or be an apple on a tree. The very same infant’s foot then realizes that it can only serve as a ‘foot’ and it cannot fly like a butterfly or be a fruit. This is the reality. The infant’s foot thus, once it enters the society, is made aware of the reality and it loses its illusions.

Question 2.
Why does the poet refer to the foot’ as being a blind man?
Answer:
The infant’s foot tries to combat reality and faces stones, streets, bits of glass, ladder, paths in the rough earth, which teach the infant’s foot that it is only a ‘foot’ and they take him ‘prisoner’. The foot gets condemned to live inside a shoe. The shoe here stands for the society, the outside forces which discipline the individual in conformity with the norms and customs of the society. The poet refers to the ‘foot as being a blind man’ because once he is put inside the shoe he loses touch with its fellow and is not free to face reality as he »

Question 3.
Explain how the poet uses a foot as a metaphor for life.
OR
Describe how the foot represents an individual’s life, according to the poem.
Answer:
In the poem, Neruda uses ‘foot’ as a metaphor for ‘life’. We see different stages in life beginning with infancy or childhood, maturity, adulthood, old age, and finally death. These stages have been delineated in the poem using ‘foot’ as a metaphor. The poem begins with the infant’s foot. Here, like all children, the infant’s foot does not even know that it is only a foot. It has dream-like imagination and aspirations. That is why it dreams of flying like a butterfly with absolute freedom and enjoy the pleasures of life which are expressed as a wish to become an apple.

However, once the child’s foot comes to face the external world, it becomes aware that it is only a ‘foot’ and cannot become a butterfly. Then it matures into an adult and from adulthood grows old and dies.

KSEEB Solutions

The poet describes how the child’s foot which has soft, petal-like toes gets transformed into an adult foot which has toes which resemble eyeless reptiles, and are covered with nails which are calloused and bear faint volcanoes of death.

Finally, having become an adult, it slogs throughout life, relentlessly working in fields, markets, mines and ministries without respite and not enjoying the pleasures of life until it dies and is buried. Thus, the ‘foot’ as a metaphor serves the poet to express his view of life.

Question 4.
Why does the foot feel trapped and stifled inside the shoe?
OR
What happens to the foot when it is condemned to live in a shoe?
OR
Bring out the life of the foot in a shoe as presented in ‘To the Foot from its Child’.
Answer:
The child’s foot is born with a great deal of zest for life and hence it wishes to become an apple on a tree or fly like a bird. But, gradually, as it starts growing, it realizes that it is a ‘foot’ only and cannot become anything else. Then, its spirit loses its battle against the world. It is taken prisoner and is condemned to live in a shoe. Now, having been imprisoned in a shoe, it tries to understand the world, in its own way. It is alone and cannot communicate with its counterpart and gropes blindly in the dark like a blind man. Since it is not in the open, it is not in touch with reality directly.

The society decides what it should understand about ‘life’ or the world outside. Whatever ideas it forms about life have to be formed in the confined space of the shoe. It is here that the child’s spirit becomes aware of its limitations as a human being and understands its role as a social being in human society. That is why it feels trapped and stifled inside the shoe.

Question 5.
Explain the instances that make the child’s foot aware of the obstacles and hardships.
Answer:
The poem narrates the journey of a child’s foot until it becomes an adult foot and beyond until it dies. The journey of the child’s foot is similar to the ‘journey of life’. The poet personifies ‘foot’ and focuses? his attention on the ‘life’ of man, using the foot as the protagonist. ‘Life’ begins in infancy and so even in this poem, ‘life’ begins as an infant’s foot. It is natural that children, who are naive and innocent, do not know that their foot is meant for walking and it has a function to discharge. But, in its innocence, the child dreams of becoming a butterfly or an apple. Therefore, when the child starts walking on a street laden with stones, and bits of glass and paths in the rough earth, the child’s foot is naturally hurt.

Similarly, when it climbs the ladder pressing his soft foot on the pointed edges of the rungs of the ladder, it is hurt and it realizes that it is a foot. Thus, using the metaphor of ‘foot’, the poet conveys the imaginary battle fought between the individual and the realities of life one has to face in society. At this stage, the foot is imprisoned in a ’shoe’. The ‘shoe’ represents the societal norms and traditions. The ‘blind’ adult foot now walks and works without respite until it dies. The different roles or professions have taken up by an individual in society either as a man or woman are expressed metaphorically in the line:

“up above, down below, through fields, mines, markets, and ministries”.

The individual toils hard, scarcely finding time to enjoy ‘love and sleep’. Here also the metaphor of the ‘foot’ enables the poet to express his ideas as seen in the line:

“Scarcely taking time to bare itself in love or sleep”.

The impact of life’s hardships can be seen in the deformed toes of the child’s foe.. The soft nails of quartz become opaque, are bunched together, and look like eyeless reptiles wit1 triangular heads, grow callused, and are covered with faint volcanoes of death.

Question 6.
How are the contrasting image of a child’s foot and foot confined to a shoe brought out in the poem?
OR
Society crushes childhood dreams and confines them to society and its norms. Explain with reference to the poem ’To the Foot from its Child’.
OR
Explain how the foot toils in its shoe until the whole man chooses to stop in ‘To the Foot from its Child’.
Answer:
The child’s foot is naive, and innocent and not yet aware that it is only a foot. That is why it wishes to be a butterfly or an apple. But, as the foot grows, it starts walking and it trods on stones, bits of glass, streets, ladders, and the paths in the rough earth. It soon realizes that it is only a ‘foot’ and it cannot fly or cannot become a bulging apple on a tree. It loses its state of innocence. Its spirit gets crushed and is defeated in realizing its aspirations.

KSEEB Solutions

With this awareness and maturity, the child’s foot gets imprisoned in a shoe and gradually attains adulthood. Unlike a child, an adult cannot live as he/she likes. He/She has to live as a member of the society which imposes its own rigid framework on the individual. The shoe symbolizes societal norms and traditions. Inside the shoe, it tries to understand the world alone in isolation. It serves as the foot of a man or woman working in the fields, or market or mines or ministries and toils hard day and night until it dies. The poet wishes to say that the freedom of childhood is lost when a person becomes an adult and faces a life of constant work and struggle.

The impact of this life of struggle and hardships is seen in the differences one notices in a child’s foot and the foot of an adult. The soft nails of quartz seen in an infant’s foot become opaque, are bunched together, and look like eyeless reptiles with triangular heads, grow callused, and are covered with faint volcanoes of death.

Question 7.
How does the poet describe the monotonous life of the individual confined in a shoe?
OR
How does the poem ‘To the Foot from its Child’ bring out the plight of a person dictated by
society?
It is natural that children, who are naive and innocent, do not know that their foot is meant for walking and the ‘foot’ has a function to discharge. Through the use of the ‘foot’ as a metaphor, the poet cleverly brings out the battle between harsh realities of life symbolically expressed as stones, streets, ladder, bits of glass, etc. The child dreams of becoming a butterfly or an apple. So naturally, the metaphor of foot helps the poet to convey his meaning through an imaginary battle fought between the child’s foot and the surfaces on which the child is likely to walk.

The child’s foot is sure to be hurt when it walks on a street laden with stones and bits of glass and paths in the rough earth and when it climbs the ladder pressing his soft foot on the pointed edges of the rungs of the ladder. Then it realizes that it is a ‘foot’. Here, the poet wants the reader to know that the adult world fights against the spirit of the child and makes him become aware of his role as an individual in human society.

At this stage, the foot is imprisoned in a shoe, which means, the child’s consciousness reaches maturity and adulthood. Adulthood is now represented as ‘adult foot’ enclosed in a shoe. The adult foot gropes in the dark and learns about the harsh realities of life like a blind man. Here, it means, unlike the child’s foot which had more freedom than the adult’s, the adult foot has to work in a rigid mould given by the society. The ‘shoe’ represents this framework given by society. Here again, the ‘foot’ as a metaphor comes to his help. Therefore, the poet chooses ‘shoe’ as representing societal norms and traditions.

The blind adult foot now walks and works without respite until he dies. The different professions of men are mentioned. The adult foot may be a man’s foot or a woman’s foot and keeps walking through fields, markets, mines, and ministries, and finally toils hard scarcely finding time to enjoy ‘love’ and ‘sleep’. Here also the metaphor of the ‘foot’ facilitates the expression in the line ‘scarcely taking time to bare itself in love or sleep’. Finally, it ceases to be a ‘foot’ when a man chooses to stop working. Thus, the ‘foot’ as a metaphor has been skillfully used by the poet to evoke the right imagery to suit his meaning.

KSEEB Solutions

Question 8.
Trace the stages of the foot’s transformation as portrayed in ‘To the Foot from its Child’.
OR
Bring out the changes that the foot undergoes after being condemned to live in a shoo-in ‘To the Foot from its Child’.
Answer:
‘To the Foot from its Child’ narrates the journey of a child’s foot until it becomes an adult foot and beyond until it dies.

In the first stanza, there are only two lines which express the innocence of the child and its wishes. The child wants to be a butterfly or an apple, but society is harsh and forces the child to become a responsible adult doing responsible adult things.

In the next stanza, the child’s foot walks in the real world and experiences the harsh realities of life. The words, ‘stones, bits of glass, streets, ladders, paths in the rough surface of the earth’ symbolize the forces in society.

When the child’s foot encounters them in a battle, it learns that its role is that of a foot only and it cannot become a butterfly or an apple. The foot is now imprisoned in a shoe, where it grows into an adult. It gets exposed to reality as filtered through the shoe. It suffers loneliness and gradually learns the realities of life groping in the dark like a blind man.

During this life inside the shoe, it loses all the beauty of a child’s foot. Its soft, nice, petal-like toes lose their beauty, become hard, callused, and look like eyeless reptiles.

The ‘foot’, now has grown into an adult foot, keeps on walking, works without respite in fields, markets, mines, and ministries. It toils hard giving up all its worldly pleasures and finally dies. It is then buried. But, as it descends into the ground, it loses its human awareness and does not know that it is not even a foot. So, in its spirit, it is like the child’s foot and dreams of becoming a butterfly or an apple.

Thus, the poet depicts his view of life in the metaphor of a foot, with a clear progression from infancy, to maturity, to adulthood, old age, and finally death.

III. Answer the following questions in about 200 words each:

Question 1.
The poem ‘To the Foot from its Child’ depicts the progression from childhood through adulthood to old age and finally, death. Discuss.
OR
The poem ‘To the Foot from its Child’ is a comment on the journey of human life. Elucidate.
OR
Trace the stages of the foot’s transformation as portrayed in ‘To the Foot from its Child’.
Answer:
In the poem ‘To the Foot from its Child’, Pablo Neruda expresses his view of life using the metaphor of ‘foot’. The poem begins with a description of the child’s naivety. The child’s foot does not know that it is a foot. It dreams of unlimited possibilities. It wants to become a butterfly enjoying unbridled freedom and enjoying the pleasures of life symbolized by the apple.

The poet expresses the experience of the child’s foot when it is exposed to reality in the real world. It walks over stones, streets, ladders, bits of glass, paths in the rough surface of the earth. All these symbolically stand for obstacles, problems, difficulties, and hurdles that one encounters in real life. When the child’s foot faces these realities, it attempts to fight them, and it becomes aware that it was in an illusory world and it does not have infinite possibilities in life but has to serve as a foot only.

It is also convinced that it cannot become a butterfly or an apple. The outside forces capture him and he is imprisoned in a shoe. Now, from that of an infant’s foot, it has grown to be an adult and now the adult has been forced to live like any human individual.

Then, we get a description of the changes that the child’s foot undergoes inside the shoe. Its nice, soft, petal-like toes lose their ‘lustre’ and the nails become harder, the toes grow bunched and look like eyeless reptiles, grow callused and are covered with faint volcanoes of death. Inside the shoe, the adult foot is like a blind man groping in the dark. This state depicts the helplessness of man when he faces the harsh realities of life as a member of society.

He slogs without respite and keeps on walking, until his death. He works in fields, markets, mines, and ministries either as a man’s or a woman’s foot. He does not find time to enjoy his rightful pleasures of life like ‘love’ and ‘sleep’. Finally, one day the foot ceases to walk when the man dies.

KSEEB Solutions

When he is buried the foot goes underground. But now he does not know that he is no longer a ‘foot’. In his consciousness, he is equal to the child’s consciousness and hence he again dreams of becoming a butterfly or an apple. Thus, the poet depicts his view of life, tracing its characteristics through different stages like infancy, reaching maturity, adulthood, old age, and finally death. Thus, the poem also brings out a cyclical view of life – birth, infancy, maturity, adulthood, old age, death, and rebirth.

Question 2.
Describe the various stages that the foot goes through and what the foot learns and how it changes at each stage.
Answer:
In the poem ‘To the Foot from its Child’, Pablo Neruda expresses his view of life using the metaphor of ‘foot’. The poem begins with a description of the child’s naivety. The child’s foot does not know that it is a foot. It dreams of unlimited possibilities. It wants to become a butterfly enjoying unbridled freedom and enjoying the pleasures of life symbolized by the apple.

The poet expresses the experience of the child’s foot when it is exposed to reality in the real world. It walks over stones, streets, ladders, bits of glass, paths in the rough surface of the earth. All these symbolically stand for obstacles, problems, difficulties, and hurdles that one encounters in real life. When the child’s foot faces these realities, it attempts to fight them, and it becomes aware that it was in an illusory world and it does not have infinite possibilities in life but has to serve as a foot only. It is also convinced that it cannot become a butterfly or an apple. The outside forces capture him and he is imprisoned in a shoe. Now, from that of an infant’s foot, it has grown to be an adult and now the adult has been forced to live like any human individual.

Then, we get a description of the changes that the child’s foot undergoes inside the shoe. Its nice, soft, petal-like toes lose their ‘lustre’ and the nails become harder, the toes grow bunched and look like eyeless reptiles, grow callused and are covered with faint volcanoes of death. Inside the shoe, the adult foot is like a blind man groping in the dark. This state depicts the helplessness of man when he faces the harsh realities of life as a member of society. He slogs without respite and keeps on walking, until his death. He works in fields, markets, mines, and ministries either as a man’s or a woman’s foot. He does not find time to enjoy his rightful pleasures of life like ‘love’ and ‘sleep’. Finally, one day the foot ceases to walk when the man dies.

When he is buried the foot goes underground. But now he does not know that he is no longer a ‘foot’. In his consciousness, he is equal to the child’s consciousness and hence he again dreams of becoming a butterfly or an apple. Thus, the poet depicts his view of life, tracing its characteristics through different stages like infancy, reaching maturity, adulthood, old age, and finally death. Thus, the poem also brings out a cyclical view of life – birth, infancy, maturity, adulthood, old age, death, and rebirth.

KSEEB Solutions

Question 3.
Bring out the stages of hardships faced by the foot after being confined in a shoe.
OR
Explain the various stages of hardships faced by the foot after being confined in a shoe.
OR
Describe the different stages of transformation of the foot after it is condemned to live in a shoe.
OR
The foot is forced to play various roles and shoulder many responsibilities. Explain with reference to ‘To the Foot from its Child’.
Answer:
As the child learns to walk and starts walking on stones, bits of glass, streets, ladders and the rough surface of the earth, the child’s foot becomes aware of its role. It learns that it is a foot and cannot become a butterfly or a bulging fruit on a tree. Once it realizes that it is a foot, it is defeated in realizing its aspirations and gets imprisoned in a shoe. Inside the shoe, it tries to understand the world in its own way, alone, like a blind man groping in the dark. During this period its soft nails of quartz become opaque, are bunched together, and look like eyeless reptiles with triangular heads, grow callused, and are covered with faint volcanoes of death.

These changes happen because, once the child’s foot becomes an adult’s foot, it walks as the foot of a man or woman and keeps walking in the fields as a farmer, or as a grocer in the markets, or as a miner in the mines or as a church minister or a government worker, until its death. Thus, the foot experiences the hardships of life and loses its ‘soft’ and flowery petal-like form.

Question 4.
“The norms of the social control a man just as the foot is enclosed in a shoe”. How is this depicted in ‘To the Foot from its Child’?
Answer:
The poet Neruda uses the ‘foot’ as a metaphor and conveys his view of life. Thus, by personifying the foot, the poet expects the readers to compare the experience of the foot to the whole person’s hopes and dreams as well as to the realities of everyday life. By and large, one can say that the poem is basically a criticism of how people force children to grow in society forgetting all their dreams and aspirations. The child wants to be a butterfly or an apple, but society is harsh and forces the child to become a responsible adult doing responsible adult things.

As a child’s foot, it has relatively more freedom than the adult’s foot. As the infant’s foot starts walking in the real world outside, it steps over “stones and bits of glass, streets, ladders and the paths in the rough earth’’. It realizes that its role is that of a foot and it cannot become a butterfly or an apple. The moment it discovers that it is only a foot, its spirit loses its battle against the world. It surrenders itself to the dictates of the society. It is taken prisoner and is condemned to live in a shoe.

It also means that the child’s spirit becomes aware of its limitations as a human being and understands its roles, duties, and responsibilities as a social being in human society. It is true that “the foot is a symbol for the helplessness of an individual in the vice-like grip of an insensitive system”. This meaning is captured in the phrase ‘condemned to live in a shoe’. Once it gets imprisoned, it has to slog there until it dies. The society decides what it should understand about ‘life’ or the world outside. Gradually, the foot adapts itself to its world and learns to cope with the harsh realities of life.

The adult foot gets trapped in the routines of everyday life or the humdrum commonality of existence. It is now less capable of enjoyment and finds life difficult in every walk of life. It slogs and slogs either as a man’s foot or as a woman’s foot working in the field or market or mines or ministries day and night, scarcely finding time to enjoy the pleasure of love or sleep. It works without respite and finally meets with death.

To the Foot from its Child by Pablo Neruda About the Poet:

Pablo Neruda (1904-1973) is the pen name and, later legal name of the Chilean poet, diplomat, and politician Ricardo Eliecer Neftali Reyes Basoalto. In 1971 Neruda won the Nobel Prize for Literature.

Neruda became known as a poet while still a teenager. He wrote in a variety of styles including surrealist poems, historical epics, overtly political manifestos, a prose autobiography, and erotically- charged love poems such as the ones in his 1924 collection ‘Twenty Love Poems and a Song of Despair’.

KSEEB Solutions

Neruda’s poetry is renowned for its fantastic imagery and surreal use of language. The surrealists attempted to express in art and literature the workings of the unconscious mind and to synthesize. these workings with the conscious mind.

Neruda believes that our most intense experience of impermanence is not death, but our own isolation among the living. It is probably this idea that gets reflected in the poem ‘To the Foot from its Child’. According to Neruda, “it was through metaphor, not rational analysis and argument, that the mysteries of the world could be revealed”.

Background:

‘To the Foot from its Child’ is the translated English version of the original poem ‘Al Pie Desde Su Nino’ written by Pablo Neruda and translated into English by Alastair Reid. [The poem appears in the collection of poems titled ‘Estravagaris’ published in 1958. ‘Extravagaris’ (Book of Vagaries) is the English title given by Reid].

To the Foot from its Child Summary in English

‘To the Foot from its Child’ by Pablo Neruda is a narrative-descriptive poem which narrates the journey of a child’s foot until it becomes an adult foot and beyond until it dies. Besides narrating the experiences of the adult foot until its death, the poem also describes the changes that the child’s foot undergoes until it becomes an adult foot.

2nd PUC English Textbook Answers Springs Chapter 8 To the Foot from its Child image - 1

The journey of the child’s foot is similar to the ‘journey of life’. The poet uses the ‘foot’ as a metaphor and conveys his view of life. This metaphor helps the poet to convey the idea of how the child’s spirit gets crushed through the challenges and restrictions that life places upon him. Thus, by personifying the foot, the poet expects the reader to compare the experience of the foot to the whole person’s hopes and dreams as well as to the realities of everyday life. By and large one can infer that the poem is basically a criticism of how people force children to grow in society and forget all their dreams and aspirations. The child wants to be a butterfly or an apple, but society is harsh and forces the kid to become a responsible adult doing responsible adult things.

The transition of the child’s foot into an adult foot and then until its death can be studied under four stages conveniently. The four stages are

  1. Childhood
  2. Experiencing Reality
  3. Maturity and
  4. Death and Rebirth.

A brief description of each stage is given below:

1. Childhood (Lines 1 – 2):
The first stanza describes the characteristic features of the child’s foot. It is an infant’s foot and it does not know that it is a ‘foot’ at all. It lacks awareness and hence it dreams of unlimited possibilities. It would like to be a ‘butterfly’ or an ‘apple’. The foot has an optimistic view of life.

2. Experiencing Reality (Lines 3 – 16):
Here the poet highlights the impact of time on the child. As the infant’s foot starts growing in the outside world, it begins to experience the harshness and pain of life while walking. When it steps over, “stones and bits of glass, / streets, ladders / and the paths in the rough earth, it learns that its role is that of a foot the same way people become aware of their role in life. It realizes that it can neither fly like a butterfly nor become a bulged apple on the branch of a tree. The child’s foot has now discovered that it is only a ‘foot’, its spirit loses its battle against the world, is taken prisoner, and is condemned to live in a shoe. It also means that the child’s spirit becomes aware of its limitations as a human being and understands its role as a social being in human society.

KSEEB Solutions

Now, having been imprisoned in a shoe, it gradually tries to understand the world, in its own way. It is alone and cannot communicate with its counterpart, and gropes blindly in the dark like a blind man. The ‘foot’ is not in the open and whatever ideas it forms about life, are formed in the confined space of the shoe. Here, it means, it is not in touch with reality directly. The society decides what it should understand about ‘life’ or the world outside. Gradually, the foot adapts itself to its world and learns to cope with the harsh realities of life.

3. Maturity (Lines 17 – 46):
In this part of the poem the poet gives a graphic description of the changes seen in the child’s foot during its transition from a child’s foot to ‘adult foot’. The ‘soft nails of quartz’ in the child’s foot gradually grow hard and change themselves into an ‘opaque’ substance ‘hard as horn’. The ‘tiny petaled toes’ of the child’s foot ‘grow bunched and out of trim’. The toes in the adult foot appear like ‘eyeless reptiles’. Later they grow harder and become callused.

In this stanza, the poet attempts to let the reader know that as the child grows into an adult it becomes less open to reality. It also means that people grow harder both physically and emotionally. The phrase ‘faint volcanoes of death’ suggests that the foot comes to appreciate ‘mortality’. Thus, we find that the child’s foot has now been transformed from a beautiful form into a warped and ugly one.

The poet then describes the journey of an adult foot until its death. It is now like an eyeless reptile. Hence he calls it a ‘blind thing’. The adult foot is now in the harsh world outside, suggesting that the adult gets trapped in the routines of everyday life or the humdrum commonality of existence. It is now less capable of enjoyment and finds life difficult in every walk of life. It slogs and slogs either as a man’s foot or as a woman’s foot working in the field or market or mines or ministries. It toils in the shoe, day and night, scarcely finding time to enjoy the pleasures of life or sleep. It works without respite and finally meets with death.

4. Death and Rebirth (Lines 47 – 53):
Soon after the death, the adult foot gets buried. It goes down into the underground. It finds everything dark there. It also does not know that it is dead and has ceased to be a foot. When the foot dies and is buried, its consciousness is childlike again. Therefore, the foot revisits the possibilities of flying like a butterfly or becoming an apple. Here it means that people consider the possibility of an after-life.

KSEEB Solutions

To sum up, the freedom of childhood is lost when a person becomes an adult and is exposed to a life of constant work and struggle. Outside, uncontrollable forces have the power to direct one’s life and thus ‘life’ in society takes away people’s free spirits until they are freed again by death. The human promise is not fulfilled by those whom society enslaves and mistreats.

The poet imagines that the naked foot of a boy, innocent still of the habituations of social society does not know that it is a foot, or a butterfly or an apple.

Only through a long process of denial of our embodied natures, beginning with the simple act of wearing shoes and thus denying contact with the earth does the boy become a man. However, upon being buried, he still does not know if he will fly or become an apple.

To the Foot from its Child Summary in Kannada

2nd PUC English Textbook Answers Springs Chapter 8 To the Foot from its Child image - 2
2nd PUC English Textbook Answers Springs Chapter 8 To the Foot from its Child image - 3
2nd PUC English Textbook Answers Springs Chapter 8 To the Foot from its Child image - 4

Glossary:

  • Quartz: a hard white colourless mineral consisting of silicon dioxide
  • Opaque: not transparent
  • Petaled: like petals
  • Callus: thickened and hardened part of the skin
  • Respite: a short period of rest

KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7

Students can Download Chapter 3 Playing with Numbers Ex 3.7 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7

Question 1.
Renu purchases two bags of fertiliser of weights 75 kg and 69 kg. Find the maximum value of weight which can measure the weight of the fertiliser exact number of times.
Solution:
Weight of the two bags = 75 kg and 69 kg
Maximum weight = HCF (75, 69)
KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 1
75 = 3 × 5 × 3
69 = 3 × 23
HCF = 3
Hence, the maximum value of weight, which can measure the weight of the fertilizer exact number of times, is 3 kg

KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7

Question 2.
Three boys step off together from the same spot. Their steps measure 63 cm, 70 cm and 77 cm respectively. What is the minimum distance each should cover so that all can cover the distance in complete steps?
Solution:
Step measure of 1 Boy = 63 cm
Step measure of 2 Boy = 70 cm
Step measure of 3 Boy = 77 cm
LCM of 63, 70, 77
KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 2
LCM = 2 × 3 × 3 × 5 × 7 × 11 = 6930
Hence, the minimum distance each should cover so that all can cover the distance in complete steps is 6930 cm.

Question 3.
The length, breadth and height of a room are 825 cm, 675 cm and 450 cm respectively. Find the longest tape which can measure the three dimensions of the room exactly.
Solution:
Length = 825 cm = 3 × 5 × 5 × 11
Breadth = 675 cm = 3 × 3 × 3 × 5 × 5
Height = 450 cm = 2 × 3 × 3 × 5 × 5
Longest tape = HCF of 825, 675, and 450 = 3 × 5 × 5 = 75 cm
Therefore, the longest tape is 75 cm.

KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7

The LCM of 15 and 20 is 60.

Question 4.
Determine the smallest 3-digit number which is exactly divisible by 6, 8 and 12
Solution:
Smallest number = LCM of 6, 8, 12
KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 50
LCM = 2 × 2 × 2 × 3 = 24
the smallest 3-digit multiple of 24.
It can be seen that 24 × 4 = 96 and 24 × 5 = 120.
Hence, the smallest 3-digit number which is exactly divisible by 6, 8, and 12 is 120

Question 5.
Determine the greatest 3-digit number exactly divisible by 8, 10 and 12.
Solution:
LCM of 8, 10, and 12
2, 8,10,12
KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 200
LCM = 2 × 2 × 2 × 3 × 5 = 120
We have to and the greatest 3-digit multiple of 120.
It can be seen that 120 × 8 = 960 and 120 × 9 = 1080.
Hence, the greatest 3-digit number exactly divisible by 8, 10, and 12 is 960.

KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7

Question 6.
The traffic lights at three different road crossings change after every 48 seconds, 72 seconds and 108 seconds respectively. If they change simultaneously at 7 a.m., at what time will they change simultaneously again?
Solution:
Time period after which these lights will change = LCM of 48, 72, 108
KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 201
LCM = 2 × 2 × 2 × 2 × 3 × 3 × 3 = 432
They will change together after every 432 seconds i.e., 7 min 12 seconds.
Hence, they will change simultaneously at 7 : 07 : 12 am.

Question 7.
Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.
Solution:
Maximum capacity of the required tanker = HCF of 403, 434, 465
403 = 13 × 31
434 = 2 × 7 × 31
465 = 3 × 5 × 31
HCF = 31
A container of capacity 31 l can measure the diesel of 3 containers exact number of times

Question 8.
Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.
Solution:
LCM of 6, 15, 18
KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 30
LCM = 2 × 3 × 3 × 5 = 90
Required number = 90 + 5 = 95

Question 9.
Find the smallest 4-digit number which is divisible by 18, 24 and 32.
Solution:
LCM of 18, 24, and 32
KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 35
LCM = 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288
We have to and the smallest 4-digit multiple of 288.
It can be observed that 288 × 3 = 864 and 288 × 4 = 1152.
Therefore, the smallest 4-digit number which is divisible by 18, 24, and 32 is 1152.

KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7

Question 10.
Find the LCM of the following numbers:
(a) 9 and 4
(b) 12 and 5
(c) 6 and 5
(d) 15 and 4
Observe a common property in the obtained LCMs. Is LCM the product of two numbers in each case?
Solution:
(a) 9 and 4
KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 60
LCM = 2 × 2 × 3 × 3 = 36

KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7

(b) 12 and 5
KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 61
LCM = 2 × 2 × 3 × 5 = 60

c) 6 and 5
KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 62
LCM = 2 × 3 × 5 = 30

d) 15 and 4
KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 63
LCM = 2 × 2 × 3 × 5 = 60
Yes, it can be observed that in each case, the LCM of the given numbers is the product of these numbers.
When two numbers are co-prime, their LCM is the product of those numbers. Also, in each case, LCM is a multiple of 3.

KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7

Question 11.
Find the LCM of the following numbers in which one number is the factor of the other.
(a) 5, 20
(b) 6, 18
(c) 12, 48
(d) 9, 45
Solution:
KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 70
LCM = 2 × 2 × 5 = 20

KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 71
LCM = 2 × 3 × 3 = 18

KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 72
LCM = 2 × 2 × 2 × 2 × 3 = 48

KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.7 73
LCM = 3 × 3 × 5 = 45
Yes, it can be observed that in each case, the LCM of the given numbers is the larger number. When one number is a factor of the other number, their LCM will be the larger number.

KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1

Students can Download Chapter 12 Ratio and Proportion Ex 12.1 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1

Least common multiple (LCM) of 12 and 16 is 48.

Question 1.
There are 20 girls and 15 boys in a class.
a) What ¡s the ratio of number of girls to the number of boys?
b) What is the ratio of number of girls to the total number of students in the class?
Solution:
Numbers of girls in a class = 20
Numbers of boys in a class = 15
Total numbers of students in a class = 20 + 15 = 35
a) Ratio of number of girls to number of boys
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 1
b) Ratio of numbers of girls to total number of students
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 2

KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1

Question 2.
Out of 30 students in a class, 6 like football, 12 like cricket and remaining like tennis. Find the ratio of
a) Number of students liking football to numbers of students liking tennis.
b) Numbers of students liking cricket to total number of students.
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 3
Solution:
Number of students Who like football = 6
number of students Who like cricket = 12
Number of students who like tennis = 30 – 6 – 12 = 12
a) Ratio of the number of students liking football to the number of students liking tennis =
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 352
b) Ratio of the number of students liking cricket to the total number of students
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 4
= 2 : 5

Question 3.
See that figure and find the ratio of
a) Numbers of triangles to the number of circles inside the rectangle
b) Number of squares to all the figures inside the rectangle
c) Number of circles to all the figures inside the rectangle.
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 5
Solution:
Number of triangle in a rectangles = 3
Number of circles in a rectangles = 2
Numbers of squares in a rectangles = 2
Total number of figures in a rectangles = 7
a) Ratio of the number of triangles to the number of circles = \(\frac{3}{2}\)
b) Ratio of the number of squares to all the figures in rectangle = \(\frac{2}{7}\)
c) Ratio of the number of circles to tall the figures in the rectangle = \(\frac{2}{3}\)

Question 4.
Distances travelled by Hamid and Akhtar in an hour are 9 km and 12 km. Find the ratio of speed of Hamid to the speed of Akhsta.
Solution:
The distance travelled in an hour by a certain object is caused the speed of the object. Distance travelled by Hamid in one Hour = 9 km / hr
& Distance travelled by Akhtar in one hour = 12 km / hr
Ratio of speed of Hamid to the speed of Akhtar
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 50

KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1

Question 5.
Fill in the following Blanks :
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 51
Solution:
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 52
Therefore, 5,12, 25 be the answer
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 521
True (Yes) all these are equivalent ratios

Question 6.
Find the ratio of the following:
a) 81 to 108
b) 98 to 63
c)33 km to 121 km
d) 30 minutes to 45minutes
Solution:
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 53

KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 59

Question 7.
Find the ratio of the following
a) 30 minutes to 1.5 hours
b) 40 cm to 1.5 m
c) 55 paise to Rs 1
d) 500 mi to litres
Solution:
a) 1 hour = 60 min
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 55

b) 40 cm to 1.5 m
1.5 m = 100 cm
1.5 m = 150 cm
Requires Ratio
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 56

c) 55 paise to Rs 1
Rs 1 = 100 paise
Requires Ratio
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 57

d) 500 ml to 2l
1l= 1000 ml
2l = 2 × 1000 ml = 2000 ml
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 58

Question 8.
In a year, Seema earns Rs 1,50,000 and saves Rs 50,000. Find the ratio of
a) Money that Seema earns to the money she saves.
b) Money that she saves to the money she spends.
Solution:
Money earned by seema = Rs 1,50,000
Money Saved by Seemed = Rs 50,000
Money spent = Rs 1,50,000 – Rs 50,000 = Rs 1,00,000
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 60

KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1

Question 9.
There are 102 teachers in a school of 3300 Students, Find the ratio of the number of teachers to the number of students.
Solution:
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 61

Question 10.
In a college, out of 4320 Students, 2300 are girls. Find the ratio of
a) Number of girls to the total number of students.
b) Number of boys to the number of girls.
c) Number of boys to the total number of students
Solution:
Total number of students = 4320
Number of girls in a college = 2300
Number of boys in a college = 4320 – 2300 = 2020
a) Required ratio n for number of girls to the
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 62
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 63

b) Required ratio for number of boys to the number of girls
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 64

KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 65

c) Required ratio for number of boys to the total number of students
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 66
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 661

Question 11.
Out of 1800 students in a school 750 opted basket ball, 80 opted cricket and remaining opted table tennis. If a student can opt only one game, find the ratio of
a) Number of students who opted basket ball to the number of students Who opted table tennis.
b) Number of students Who opted cricket to the number of students opting basketball
c) Number of students Who opted basket ball to the total number of students.
Solution:
Total number of students = 1800
Number of students opted basketball = 750
Number of students opted cricket = 800
Number of students opted table tennis = 1800 – 750 – 800 = 250
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 67

KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1

Question 12.
Cost of dozen pens is Rs 180 and cost of 8 ball pens is Rs 56. Find the ratio of the cost of pen to the cost of a ball pen.
Solution:
Cost of dozen pens = Rs 180
Cost of 1 per = \(\frac{180}{12}\) = Rs 15
Cost of 8 ball pens = Rs 56
Cost of ball pens=\(\frac{56}{8}\) = Rs 7
Required ratio of the cost of a pen to the cost of a ball pen = \(\frac{15}{7}\) = 15 : 7

Question 13.
Consider the statement: Ratio of breadth and length of a hall is 2 : 5. Complete the following table that shows some possible breadths and lengths of the hall.
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 261
Solution:
i) Length = 50 m
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 69
5 × Breadth = 50 × 2 (by cross multiplication )
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 70

ii) Breadth = 40 m
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 71
2 × Length = 5 × 40 (By cross – Multiplication)
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 712
Length = 100 m.

Question 14.
Divided 20 pens between sheela and sangeeta in the ratio of 3 : 2.
solution:
Terms of 3 : 2 are 3 and 2
Sum of these two terms = 3 + 2 = 5
Sheela will get \(\frac{3}{5}\) of total pens and sangeeta will get \(\frac{2}{5}\) of total pens.
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 72

Question 15.
Mother wants to divide Rs 36 between her daughters shreya and bhoomika in the ratio of their ages. If age of shreya is 15 years and age of bhoomika is 12 years, find how much shreya and bhoomika will get.
Solution:
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 73
Therefore, mother wants to divide Rs 36 in a ratio of 5 : 4 sum of these terms = 5 + 4 = 9
Shreya will get \(\frac{5}{9}\) of the total money and bhoomika will get \(\frac{4}{9}\) of it
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 731
Therefore, Shreya and bhoomika will get Rs 20 and Rs 16 respectively.

KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1

Question 16.
Present age of father is 42 years and that of his son is 14 years. Find the ratio of
a) Present age of father to the present age of son
b) Age of the father to the age of son, When son was 12 years old.
c) Age of father after 10 years to the age of son after 10 years
d) Age of father to the age of son when father was 30 years old
Solution:
a) Present age of father = 42 years
Present age of son = 14 years
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 74

b) Two years ago, the age of the son was 12 years and the age of the father was 42 – 2 = 40 years
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 75

c) After 10 years, the age of the father and son will be 52 years and 24 years respectively
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 76

d) 12 years ago, the father was 30 years old, At that time age of son = 14 – 12 = 2 years
KSEEB Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 761

error: Content is protected !!