KSEEB Solutions for Class 8 Maths Chapter 2 Algebraic Expressions Ex 2.2

Students can Download Maths Chapter 2 Algebraic Expressions Ex 2.2 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka Board Class 8 Maths Chapter 2 Algebraic Expressions Ex 2.2

Question 1.
Classify into like terms
4x², \(\left(\frac{1}{3} x\right)\) , – 8x3, xy, 6x3, 4y, -74×3, 8xy, 7 xyz, 3x²
Answer:
Like terms I= (4x², 3x²)
II = \left(\frac{1}{3} x\right)
III = -8x3, 6x3, -74×3
IV = (xy, 8xy)
V = (4y)
VI = (7 xyz)

Question 2.
Simplify
i. 7x – 9y + 3 – 3x + 5y + 8
ii. 3x² + 5xy – 4y² + x² – 8xy – 5y²
Answer:
KSEEB Solutions for Class 8 Maths Chapter 2 Algebraic Expressions Ex. 2.2 1

Question 3.
Add
i. 5a + 3b, a – 2b and 3a + 5b
ii. x3 – xy + 5xy² + y , – x3 – 9xy² + y and 3x²y + 9xy²
Answer:
KSEEB Solutions for Class 8 Maths Chapter 2 Algebraic Expressions Ex. 2.2 2

Question 4.
Subtract
i. – 2xy + 3xy² from 8xy
ii. a – b – 2c from 4a + 6a – 2c
Answer:
KSEEB Solutions for Class 8 Maths Chapter 2 Algebraic Expressions Ex. 2.2 3

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