KSEEB Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3

Students can Download Chapter 6 Integers Ex 6.3 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 6 Maths Chapter 6 Integers Ex 6.3

Question 1.
Find
Solution:
a) 35 – (20)
35 – (20) = 15

b) 72 – (90)
72 – (90) = -18

c) (-15) – (-18)
(-15) – (-18) = -15 + 18 = 3

d) (-20) – (-13)
(-20) – (-13) = -33

e) 23 – (-12)
23 – (-12) = 23 + 12 = 35

f) (-32) – (-40)
(-32) – (-40) = -32 + 40 = 8

Question 2.
Fill in the blanks with >,< or = sign
a) (-3) + (-6) ___ (-3) – (6)
(-3) + (-6) = -9
(-3) – (-6) = -3 + 6 = 3 – 9 < 3
Hence (3) +(-6) < (-3)-(-6) b) (-21) – (-10) ___ (-31) + (-11) -31 + (-11) = -42 – 11 > -42
(9 – 21) – (- 10) ≥ (-31) +(-11)

c) 45 – (-11) ___ 57 + (-4)
57 + (-4) = 57 – 4 = 53
56 > 53

d) (-25) – (-42) ___ (-42) – (-25)
-42 – (-25) = -42 + 25 = -17
117 > -17
(-25) – (-42) ≥ (-42) – (-25)

Question 3.
Fill in the blanks
a) (-8) + 8 = 0
b) 13 + (-13) = 0
c) 12 + (- 12) = 0
d) (-4) + (-8) =-12
e) 5 – 15 = -10

Question 4.
Find
Solution:
a) (-7) -8 – (-25)
(-7) – 8 – (-25) = (-7) – 8 + 25 = -15 + 25 = 10

b) (-13) + 32 – 8 – 1
(-13) + 32 – 8 – 1 = -13 + 32 – 8 – 1 = 32 – 22 = 10

c) (-7) + (-8) +(-90)
(-7) + (-8) + (-90) = -7 – 8 – 90 = -105

d) 50 – (-40) – (-2)
50 – (-40) – (-2) = 50 + 40 + 2 = 92

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