KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling

Students can Download Maths Chapter 10 Data Handling Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 10 Data Handling

KSEEB Class 5 Maths Data Handling Ex 10.1

1. Observe the pictograph and answer the questions

KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 2

  • Number of Science books read Six
  • Number of Kannada books read Four
  • Number of Adventure books read Twelve
  • Number of novels read Eight
  • Total number of books read Thirty

KSEEB Solutions

2. The following pictograph shows the number of cars in 5 villages of a taluk.

KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 1 Planet128

Observe the pictograph and answer the following questions:

  • Which village has the maximum number of cars? Village 3
  • Which village has the minimum number of cars? Village 1
  • What is the total number of cars in five villages? 150 cars
  • How many more cars are there in village 3 than in village 5? Twenty-five
  • Which two villages have the same number of cars? Village 2 & 4

KSEEB Solutions

Data Handling Additional Questions and Answers

1. A survey of sale of cars made by an agency for a particular month is an follows:

KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 3 Planet128

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Question
Represent this data through a pictograph.
Answer:
Scale = 5 cars.

Answer the following questions:

Question
In which week were the maximum number of cars sold?
Answer:
First week

KSEEB Solutions

Question
In which week were the minimum number of cars sold?
Answer:
Second week

Question
What is the difference in the number of cars sold in the third and fourth week?
Answer:
Five years

Question
What is the total number of cars sold in the month?
Answer:
110 cars

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Question
Arrange the number of cars sold in the descending order along with the week.
Answer:
Example:
35, 30, 25, 20
First Week

Question 3.
Ramu had 5 pens. 3 erasers, 6 books, 2 pencils and one sharpener in his bag.
Answer:
Write the data in tubular form and represent the same through a pictograph.

KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 4 Planet128KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 5

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4. The number of bulbs manufactured in a week by a factory is given below. Draw a pictograph to represent the data. (Choose a suitable scale)

KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 6 Planet128KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 7 Planet128

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Bar Graphs

I. Read the bar graph and answer the given questions:

KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 8 Planet128

Question
What is the information given in the bar graph?
Answer:
Days against Earnings of flourist in rupees

KSEEB Solutions

Question
Mention the scale taken.
Answer:
50 flourist = 1 cm

Question
Mention the earnings on each day.
Answer:
First day – 300
Second day – 500
Third day – 200
Fourth day – 400
Fifth day – 350

Question
What is the total earnings in five days?
Answer:
1750 flourist in Rupees

KSEEB Solutions

Question
What is the difference in the amount earned on the second day and the fifth day?
Answer:
150 flourist in Rupees

Question
Arrange the amount earned on each day in the descending order.
Answer:
500,400,350,300,200, 2nd day 4th day 5th day ! day 3rd day

2. Study the bar graph and answer the questions given.

KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 9 Planet128

KSEEB Solutions

Question
What is the information given in the bar graph?
Answer:
Saplings planted by a farmer against week

Question
Mention the scale taken.
Answer:
100 Plants = 1 week

Question
Mention the number of saplings planted in each week.
Answer:
First week – 700
Second week – 900
Third week – 500
Fourth week – 800
Fifth week – 600

KSEEB Solutions

Question
What is the total number of saplings planted in the five weeks?
Answer:
3500 saplings

Question
In which week did the farmer plant the maximum number of saplings?
Answer:
Second week

Question
In which week did he plant the minimum number of saplings?
Answer:
Third week

KSEEB Solutions

3. A survey of 120 school students was done to find the activity they prefer to do in their free time.

KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 10

Draw a bar graph to illustrate the above data.
Scale: 1 cm= 5 students

Question
Which activity is preferred by most of the students other than playing?
Answer:
KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 11 Planet128

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4. The number of belts sold by a shopkeeper on six consecutive days of a week is as follows:

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Draw a bar graph to represent the data.
Scale : 1 cm = 5 belts

Question
What is the total number of belts sold in 6 days?
Answer:
175

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5. The number of hours spent by a student on different activities in a day is given below.

KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 14

Represent the above data by a bar graph.
Scale: 1 cm = 1 hour
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6. The following table shows the number of bicycles manufactured in a factory during the year 2005 – 2009. Illustrate the data using a bar graph.
(choose a suitable scale)

KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 16

Question a.
In which year was the maximum number of bicycles manufactured?
Answer:
2007

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Question b.
In which year was the minimum number of bicycle manufactured?
Answer:
2008
KSEEB Solutions for Class 5 Maths Chapter 10 Data Handling 17 Planet128

KSEEB Solutions

KSEEB Solutions for Class 5 Maths Chapter 5 Money

Students can Download Maths Chapter 5 Money Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 5 Money

I. Find the following:

1. Sum of Rs. 13.25, Rs.6.30, Rs 10.40 = ____________

KSEEB Solutions for Class 5 Maths Chapter 5 Money 1

KSEEB Solutions

2. Difference of Rs,78.45 and Rs.69.70 = ___________

KSEEB Solutions for Class 5 Maths Chapter 5 Money 2

3. Product of Rs.147.25 and Rs 17 = _____________

KSEEB Solutions for Class 5 Maths Chapter 5 Money 3

4. Quotient of Rs. 4960 ÷ Rs. 8 = 620

KSEEB Solutions for Class 5 Maths Chapter 5 Money 4

II. Solve the following:

Question 1.
Subtract Rs. 95.80 from the sum of Rs.279.05 and Rs.103.25
Answer:
KSEEB Solutions for Class 5 Maths Chapter 5 Money 5

Question 2.
Express Rs.32 in paise.
Answer:
1Rs= 100 Paise
32 Rs = \(\frac{100 \times 32}{3200 \mathrm{Paise}}\)

Question 3.
Express Rs. 19.75 in paisa
Answer:
1 Rs = 100 Paise
19.75 Rs = \(\frac{19.75 \times 100}{1,975.00 \text { Paise }}\)

KSEEB Solutions

Question 4.
Express 4,705 paise in rupees.
Answer:
100 Paise = 1 Rupee.
4,705 Paise = \(\frac{4705}{100}\)
= Rs. 47.05

KSEEB Class 5 Maths Money Ex 5.1

Problems involving addition in Money system.

I. Solve:

Question 1.
I had Rs. 625 with me. My father gave Rs. 450.75 as pocket money. What is the total amount with me now?
Answer:
I had – Rs 625.00
My father gave – Rs 450.75
The total Amounts with me – Rs 1,075.75

KSEEB Solutions for Class 5 Maths Chapter 5 Money 6

Question 2.
Mahesh buys a pen for Rs. 18.5, a book for Rs.10.75 and a bag for Rs.125. What is the total cost of all the things bought?
Answer:
Mahesh buys a pen – Rs 18.50
Mahesh buys a book – Rs 10.75
Mahesh buys a Bag – Rs 125.00
The total cost of all thing – Rs. 154.25

KSEEB Solutions for Class 5 Maths Chapter 5 Money 7

Question 3.
Razia had Rs. 345 with her. She bought a dress for Rs. 245.75. What is the amount left with her?
Answer:
Girija buys 2 Kg of beans – Rs 36.50
Girijabuys 1 Kg of tomatoes – Rs 12.25
Girija buys 1 Kg of potatoes – Rs 14.75 6
The total Amount Girija pay to the shopkeeper – Rs 63.50

Problems involving subtraction in Money system.

II. Solve:

Question 1.
Subtract Rs. 348.25 from Rs. 500.
Answer:
KSEEB Solutions for Class 5 Maths Chapter 5 Money 8

KSEEB Solutions

Question 2.
Varun bought sweets for Rs.475.5. He paid Rs.500 to the shop keeper. What change should he get back from the shopkeeper?
Answer:
Varun paid – Rs 500.00
Varun bought sweets – Rs 475.50
Varun get back from the shopkeeper – Rs 124.50

KSEEB Solutions for Class 5 Maths Chapter 5 Money 9

Question 3.
Razia had Rs.345 with her. She bought a dress for Rs.245.75. What is the amount left with her?
Answer:
Razia had – Rs 345.00
Razia bought a dresses – Rs 245.75
Razia amount left – Rs 99.25

KSEEB Solutions for Class 5 Maths Chapter 5 Money 10

Question 4.
Poornima had Rs.3,425 with her. She gave Rs.2,745.75 to her friend to buy a saree. What is the amount left with her?
Answer:
Poornima had an amount – Rs 3,425.00
Poornima gave an amount – Rs 2,745.75
To her friend
The amount left with Poornima Rs 679.25

KSEEB Solutions for Class 5 Maths Chapter 5 Money 11

Question 5.
Joseph had Rs. 2,500 in the account in a bank. He withdrew Rs. 1,800.75 for his expenses. What is the amount left in his account in the bank?
Answer:
Joseph had amount in a bank – Rs 2500.00
Joseph withdraw amount in a bank – Rs 1800.75
The amount left with joseph – Rs 699.25

KSEEB Solutions for Class 5 Maths Chapter 5 Money 12

Problems involving Multiplication in Money system.

III. Solve:

Question 1.
The cost of an egg is Rs.4. What is the cost of a dozen eggs?
Answer:
The cost of an egg – Rs 4
The cost of a dozen egg – Rs 12 × 4
The amount of a dozen eggs – Rs 48

KSEEB Solutions

Question 2.
Swathi buys 8 metres of cloth at Rs.75 per metre. What is the amount to be paid to the shopkeeper?
Answer:
Swathi buy a cloth Rs 75 per metre
Swathi buys 8 metre of cloth – 75 x 8
Swathi paid to the shopkeeper – Rs 600

Question 3.
The cost of an umbrella is Rs.225 What is the cost of 15 umbrellas?
Answer:
The cost of an umbrella – Rs 225
The cost of 15 umbrella as 225 × 15 = 3,375

Question 4.
A labourer earns Rs.525 a day. How much will he earn in a week?
Answer:
A labourer earns amount – Rs 525
A labourer earns amount –  Rs 525 × 7
In a week = 3675

Question 5.
The cost of a table is Rs.4,320. What is the cost of 16 tables?
Answer:
The cost of a table Rs 4,320
The cost of a table Rs 4,320 × 16 = 69,120

Problems involving division in Money System

IV. Solve:

Question 1.
The Government higher primary school sanctioned a scholarship amount of Rs.4,000 for 10 students, How much amount did each one get?
Answer:
The government higher primary school sanctioned a scholarship amount – Rs 4,000
For 10 students – Rs 4,000
KSEEB Solutions for Class 5 Maths Chapter 5 Money 13
For each students gets – Rs 400

Question 2.
Mohan paid Rs. 1,422 for 9 shirts. What is the cost of each shirt?
Answer:
Mohan paid Rs 1,422 for 9 shirts
The cost of each shirts \(\frac{1422}{9}\)
The cost of Shirts Rs 158

Question 3.
Distribute Rs.4,425 among Amar, Akbar and Anthony equally. What is the amount of share that each one gets?
Answer:
Distribute Rs 4,425 among Akhbar Amar & Anthony equally
The amount of share each gets = \(\frac{4425}{3}\) = 1475 Rs

KSEEB Solutions

Question 4.
If the cost of a dozen apples is Rs. 96, what is the cost of one apple?
Answer:
The cost of a dozen apples = 96
The cost of one apple \(\frac{96}{12}\) = 8 Rs

Question 5.
Vinod, a carpenter earns Rs.9,666 in 6 days. What is the amount he earns in a day?
Answer:
Vinod a carpenter earns 9.666 in 6 days
The amount vinod earns a day = \(\frac{9666}{6}\) = 1611 Rs

KSEEB Class 5 Maths Money Ex 5.3

Miscellaneous Problems in Money System

I. Solve:

Question 1.
Subtract Rs. 687.25 from the sum of Rs.932.60 and Rs.403.7
Answer:
KSEEB Solutions for Class 5 Maths Chapter 5 Money 14

Question 2.
Ramegowda had Rs.8,000 with him. He spent Rs.2,450.25 to buy mango saplings, Rs.675.5 for seedlings and Rs.150 for transportation. What is the amount left with him?
Answer:
Ramegowda had amount Rs 8000
Ramegowda spent Rs 2,450.25 for mango
Ramegowda spent Rs 675.50 for seedlings
For transportation Rs 150.00
Total spent by Ramegowda Rs 3,275.75

KSEEB Solutions for Class 5 Maths Chapter 5 Money 15
The amount left Ramegowda Rs 4,724.25

Question 3.
Kishan had Rs.10,000 in his bank account. He withdrew Rs.5,475.5 for his expenses. Later he deposited Rs. 3,280.75. Find the amount left in his account in the bank?
Answer:
Krishna had an amount – Rs 10,000.00
Krishna deposit an amount – Rs 3,280.75
Total amount deposit in the bank – 13,280.75

KSEEB Solutions for Class 5 Maths Chapter 5 Money 16
Krishna withdraw an amount – Rs 5,475.50
The amount left with Krishna – Rs 7,805.25

KSEEB Solutions for Class 5 Maths Chapter 5 Money 17

Question 4.
Salma bought 20 chocolates at Rs.22 each. She gave the shopkeeper Rs. 500 note. What is the change she hds to get from the shopkeeper?
Answer:
Sahan bought 20 chocolates
Each chocolate of cost Rs 22
The cost of 20 chocolate = 20 x 22 = Rs 440
Sahana gave Rs 500 to the shopkeeper

KSEEB Solutions for Class 5 Maths Chapter 5 Money 18
Sahan Rs 60 from the shopkeeper

KSEEB Solutions

Question 5.
Raghu had Rs.25,000 in his account in the bank. He later deposited Rs. 15,000 to his account. He took 8 gift cheques of equal value for the total amount from the bank. What is the amount of each gift cheque?
Answer:
Raghu had an amount Rs 25,000
Raghu deposit Rs 15,000 to his account

KSEEB Solutions for Class 5 Maths Chapter 5 Money 19
Raghu took 8 gifts cheques of equal value for the total amount \(\frac{4000}{8}\) = Rs 5000
The amount of each gift cheques Rs 5000

KSEEB Class 5 Maths Money Ex 5.4

I. Check and correct the bills given below:

1.
KSEEB Solutions for Class 5 Maths Chapter 5 Money 20

2. Mrs. Uma bought the following articles from Sunny Enterprises.

  • 5 instrument boxes at Rs. 38 each 12 pencils at Rs. 3 each
  • 6 boxes of crayons at Rs.12 each.
  • 8 paint boxes at Rs. 25 each.

KSEEB Solutions for Class 5 Maths Chapter 5 Money 21

3. Miss Rita bought the following items for the school Annual Day from megha Stationaries:

  • 25 sheets of colour paper at Rs. 9 each
  • 18 sheets of gold colour paper at Rs. 19 each
  • 12 sheets of silver colour paper at Rs. 18 each.
  • 2 tubes of glue stick at Rs. 30 each.

KSEEB Solutions for Class 5 Maths Chapter 5 Money 22

4. Ranbir Singh bought the following articles from Hanuman Hardware shop.

  • 2 hammers at Rs.85 each.
  • 6 boxes of nails at Rs. 25 each.
  • 8 boxes of screws at Rs.30 each box.
  • 2 spanners at Rs.175 each.

KSEEB Solutions for Class 5 Maths Chapter 5 Money 23

KSEEB Solutions

KSEEB Solutions for Class 5 Maths Chapter 9 Three Dimensional Figures

Students can Download Maths Chapter 9 Three Dimensional Figures Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 9 Three Dimensional Figures

KSEEB Class 5 Maths Three Dimensional Figures Ex 9.1

I. Answer orally:

Question a.
What is the shape of the faces of a cube?
Answer:
Square

Question b.
How many circular faces are there in a cylinder?
Answer:
Two

KSEEB Solutions

Question c.
Mention the number of plane surfaces and curved surfaces in a cone.
Answer:
One, One

KSEEB Solutions

II. Observe the following table. Against each shape of solid, some pictures are given. Put (✓) against the figure which is an example of that shape and put (✗) against the figure which is not an example of that shape.

KSEEB Solutions for Class 5 Maths Chapter 9 Three Dimensional Figures 1KSEEB Solutions for Class 5 Maths Chapter 9 Three Dimensional Figures 2

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III. A robot is constructed using different solid shapes. Identify the shapes and write the number of times it is used.

KSEEB Solutions for Class 5 Maths Chapter 9 Three Dimensional Figures 3
Cube – 2, Cuboid -1, Cylinder – 3, Cone – 2

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IV. Different views of a table are given below. Name them

KSEEB Solutions for Class 5 Maths Chapter 9 Three Dimensional Figures 4KSEEB Solutions for Class 5 Maths Chapter 9 Three Dimensional Figures 5

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V. 1. Draw diagrams of cube, cylinder and cone with different measurements in 2D.
Do it your self

2. Draw diagrams of your school showing elevation, side view and plan.
Do it your self

3. Draw diagrams of different objects in your house to show elevation, side view and plan.
Do it your self

KSEEB Solutions

KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures

Students can Download Maths Chapter 8 Symmetrical Figures Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 8 Symmetrical Figures

KSEEB Class 5 Maths Symmetrical Figures Ex 8.1

1. Mark symmetric figures as (✓) and non symmetric figure as (✗) in the following:

KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 1KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 2

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2. A few lines have been drawn on the following figures and the lines are denoted by numbers. Identify the axes of symmetry and write its number.

KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 3

a) (2), b) (1), c) (1) ಮತ್ತು (3)

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3. Draw axes of symmetry to the following symmetrical figures.

KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 4KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 5

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4. A few symmetrical figures with only half part are given below. Complete the remaining half part by drawing.

KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 6KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 7

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5. Pairs of figures are given below. If one figure is the image of the other figure put a tick (✓) if not put (✗).

KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 8KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 9

6. Some figures are given below. Draw their images in the given space.

KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 10KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 11

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7. A few numerals and words are given below. Among them a few numerals or words are the images of original numerals and words. List them.
a) 818
b) 310
c) 18081
d) 80888
e) DAD
f) MAM
g) EVE
h) THAT
Answer:
a) 818 c) 1808 f) MAM

8. List the symmetrical objects you have seen in your surroundings.
Answer:
Paper, Mobile, Chair, lock, ball

KSEEB Solutions

KSEEB Class 5 Maths Symmetrical Figures Ex 8.2

1. Figures are given in the first row’ of the table given below. In the next rows, the rotations it has to be turned are given. If the figure is turned forgiven rounds and resembles the original figure, put (✓) in the box and if it does not resemble put (✗) in the box.

KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 12KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 13

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2. The follow ing figures when turned \(\frac{1}{3}\) round do not resemble the original figure. Make suitable changes in the figure, to make them resemble the original figure when turned \(\frac{1}{3}\) round.

KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 14KSEEB Solutions for Class 5 Maths Chapter 8 Symmetrical Figures 15

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3. a) List the letters from English alphabet, which will not change their shape, when turned \(\frac{1}{2}\) rotation.

Example: X
H, I, N, O, S, Z.

b) Which capital letter from English alphabet when turned \(\frac{1}{4}\) round gives another letter?
N

c) Which capital letter from English alphabet when rotated \(\frac{1}{2}\) round gives another letter?
M.

4. Draw the figures which resemble the original figure when rotated \(\frac{1}{4}\) round.
Do it your self

5. Draw the figures which resemble the original figure when rotated \(\frac{1}{3}\) round.
Do it your self

KSEEB Solutions

KSEEB Solutions for Class 5 Maths Chapter 10 Patterns

Students can Download Maths Chapter 10 Patterns Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 10 Patterns

KSEEB Class 5 Maths Patterns Ex 10.1

I. Solve the following problems:

1. Write the numbers from 1 to 50.

Color the square numbers in red and triangular numbers in blue.

KSEEB Solutions for Class 5 Maths Chapter 10 Patterns 1
KSEEB Solutions for Class 5 Maths Chapter 10 Patterns 2

Question a.
List the square numbers.
Answer:
1, 4, 9, 16, 25, 36, 49

Question b.
List the triangular numbers
Answer:
1, 3, 6, 10, 15, 21. 28, 36, 45

KSEEB Solutions

Question c.
How many square numbers are there from 1 to 50?
Answer:
7 Numbers

Question d.
How many triangular numbers are there from 1 to 50?
Answer:
9 Numbers

KSEEB Solutions

2. Observe e the given pattern of numbers and fill in the square provided.

KSEEB Solutions for Class 5 Maths Chapter 10 Patterns 3KSEEB Solutions for Class 5 Maths Chapter 10 Patterns 4

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3. Express the following square numbers as the sum of consecutive odd numbers. 16, 36, 81, 100, 121, 144, 169, 225
Example : 9 = 1 + 3 + 5

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4. Fill in the missing odd number and write the square number in the circle.

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5. List the first four square numbers and triangular numbers. Represent them through dot diagrams.

KSEEB Solutions for Class 5 Maths Chapter 10 Patterns 9

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6. Here is fun with triangular numbers. First complete the list and then write then write them in the table as shown.
1, 3, 6, 10, → → → 36, 45.

KSEEB Solutions for Class 5 Maths Chapter 10 Patterns 10
KSEEB Solutions for Class 5 Maths Chapter 10 Patterns 11

Now add them together and write the sum in the bottom row.
What can you say about the numbers formed in this row?
Write your conclusion in the form of a statement.
All numbers are square numbers.

KSEEB Solutions

7. Observe the given table

KSEEB Solutions for Class 5 Maths Chapter 10 Patterns 12KSEEB Solutions for Class 5 Maths Chapter 10 Patterns 13

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Write multiplication tables of 4,5 and 6. In each table, circle the triangular numbers as shown in the example. Draw a box for square numbers. List them in columns as shown.

KSEEB Solutions for Class 5 Maths Chapter 10 Patterns 14

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Write numbers from 51 to 100. Identify and list triangular numbers and square numbers.

KSEEB Solutions for Class 5 Maths Chapter 10 Patterns 15

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KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume

Students can Download Maths Chapter 6 Weight and Volume Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 6 Weight and Volume

KSEEB Class 5 Maths Weight and Volume Ex 6.1

I. Answer orally:

Question 1.
Albert buys 16 kg of jaggery and 15kg of rice from a shop. He puts both the packets into one bag. What is the total weight of the bag?
Answer:
Albert buys jaggry = 16 K.G
Albert buys Rice = 15 K.G
Albert puts jiggery and rice = 31 K.G in one bag

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 1

KSEEB Solutions

Question 2.
62kg of rice was supplied to a school under ‘Aksharadasoha Scheme’. If 15 kg of rice was used, find the quantity of rice remaining.
Answer:
Akshara dasoha supplied to school – 62 KG
The school used of rice – 15 KG
The remaining quantity of rice – 47 KG

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 2

Question 3.
A bag can hold 20kg of soji. If 140 of soji is to be filled equally, how many such bags are required?
Answer:
A bag can hold of soji = 20 KG
Soji is equally filled = 140KG
The number of bags = \(\frac{140}{20}\) = 7

Question 4.
A marchant has 5 packets of sugar, each packet weighting 15kg of sugar. What is the total weight of 5 packets of sugar?
Answer:
A merchant has 5 packets of sugar, Each packet weight of sugar 15 kg
The total weight of 5 packet of sugar = \(\frac{15 \times 5}{75 \mathrm{kgs}}\)

II. Convert the following:

1. 7 kg = ______ gram.
1 kg = 1000 gram
7 kg = 1000 × 7
= 7000 gram

2. 16 gram = ______ milligram.
1 gram = 1000 mg
16 gram = 1000 × 16
= 16000 milligrams

3. 6000 gram = _______ kg.
1 kg = 1000 gram
6000gram = \(\frac{6000}{1000}\) = 6kg.

4. 750 milligram = ______ gram.
1 grams = 1000 milligrams
750 milligrams = \(\frac{750}{100}\) = 7.5grams

5. 12 quintals = ________ kg.
1 quintals = 100 kg
12 quintals = 12 × 100 = 1200 kg

KSEEB Solutions

6. 1,500 kg = _______ quintals.
1 quintals = 100 kg
1500 kg = \(\frac{1500}{100}\)= 15 quintals

III. Add the following:

1. 4kg, 250g, 12kg and 355g.

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 3

2. 23kg, 432g,37 kg and 350g.

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 4

3. 12kg, 450g, 15kg and 550g.

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 5

4. 17kg, 370g, 18kg and 630g.

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 6

5. 6kg 250g, 8kg 430g, 7kg 220g and 430g.

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 7

IV. Subtract the fallowing:

1. 13kg 250g from 28kg 550g

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 8

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2. 35kg 550g from 70kg 675g

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 9

3. 55kg 335g from 85kg 730g

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 10

4. 28kg 650g from 63 kg 350g

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 11

5. 34 kg 585g form 75kg 475g

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 12

V. Solve the following:

Question 1.
Radha buys 2kg 500g of carrot, 2kg 5Q0g of brinjal and 3kg 250g of tomatoes from a vegetable shop. Find the total weight of vegetables bought by her.
Answer:
KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 13

Question 2.
A merchant has 68kg 250g of wheat with him. He sells 15kg 250g of wheat to one customer and 13kg 500g to another customer. What is the weight of wheat remaning with him?
Answer:
A merchant has 68 kg+250 grm of wheat ,(one customer) A merchant has soldi5kg 250gm. (Another customer) A merchant has sold 13kg500gm.
KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 14
The remaining wheat of a merchant 39 kg 500 gram

Question 3.
The yield of paddy per acre is 29 quintals and 50kg. Rachappa has 30 acres of field. What is the total yield of paddy?
Answer:
The yield of paddy per acre = 29 quintals and 50kg
KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 15
The total yield of paddy = 8 8,5 00 kgs

KSEEB Solutions

Question 4.
18kg 400g of sugar is to be packed in 4 bags equally. What is the weight of each bag?
Answer:
1kg = 100 grm
8 kg = 1000 × 18 = 18,000 kgs
18 kg + 400 grm of sugar is to be packed in 4 bags equally = \(\frac{18400}{4}\) = 4,600 grm
The weight of each bag 4,600 grm

Question 5.
A farmer gets 60 to 400 g of onion from one field and 56kg 800g from another field. If he sells 98kg 200g of onion, find the weight of onions left with him.
Answer:
From a land, A farmer 60kg+400 grm’of onion From another land, A farmer 56 kg + 800 grm of onion
KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 16
The weight of onion 19 kg left with him

KSEEB Class 5 Maths Weight and Volume Ex 6.2

I. Answer orally:

Question 1.
A glass contains 300ml of water and another glass contains 250ml of water. If water from both the glasses are poured into a jug, what is the quantity of water in the jug?
Answer:
A glass contains of water 300 ml
Another glass contains of water 250ml
The glasses ofwater poured into 300 + 250 = 550 ml

Question 2.
A milkman has 5l700ml of milk. Out of this he sells 11350ml of milk to one person and 21250ml to another person. Find the quantity of milk left with the milkman.
Answer:
A milk man has 5l700 ml of milk
For one person, A milkman sells 11350 ml
For another person A milkman sells 21250 ml
The total selling of milk
KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 17
KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 18
The quantity of milk left with milkman =?
KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 19
The quantity of milk left with milkman 2l 100 ml

Question 3.
A bottle contains 200ml of milk. What is the total quantity of milk contained in 5 such bottles?
Answer:
A bottle contains of milk 200 ml
5 such bottles of milk = 200 × 5 = 1000 ml
The total quantity of milk 1000 ml (or) 1l

Question 4.
100 ml of sugarcane juice is distrubuted among 4 friends equally. What quantity of sugarcane juice does each one get?
Answer:
There are 4 friends
Sugarcane juice=100 ml
The total quantity of milk= \(\frac{100}{4}\) = 25 = 25ml

II. Convert the following:

1. 5l = 5000 ml.
1l = 1000 ml
5l = 1000 × 5
= 5000 ml

KSEEB Solutions

2. 6ml = 600 l.
1 l = 1000 ml
6l = 1000 × 6 = 6000 ml

3. 500 ml. = 1/2l
1 l = 1000 ml.
500ml = \(\frac{500}{1000}\) = 1/2

4. 8,000 l = 8 kilolitre
1 l = 1000 ml
8000l = \(\frac{8000}{1000}\) = 8l.

III. Add:

1. 3l 250ml, 750 ml and 6l 500 ml.

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 20

2. 15l 450ml, 5l 350ml and 21l 750ml.

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 21

3. 12l. 550ml, 14l 450ml and 12l 650ml.

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 22

4. 8kl 250l, 3kl 350l and 4kl 550l.

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 23

IV. Subtract:

1. 15l 750 ml from 25l 350 ml

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 24

KSEEB Solutions

2. 24l 550ml from 64l 450ml

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 25

3. 45l 800 ml from 75l 750 ml

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 26

4. 34 kilolitre 750l from 55 kilolitre

KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 27
V. Solve the following:

Question 1.
Veena buys 3l 250 ml of groundnut oil while returning from her office. Her mother also bought 1l 500 ml of groundnut oil on the same day. What is the total quantity of groundnut oil bought by them?
Answer:
Veena buys of groundnut oil – 3(l), 250(ml)
Veena’s mother buys of groundnut oil – 1(l), 500(ml)
The total quantity of groundnut oil=4l, 750ml
KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 28

Question 2.
A milkman has 25 litres of milk. He sells 16l 750 ml of it. Find the quantity of milk left with him.
Answer:
A milkman has 25 litres of milk.
He sells of milk 16l750 ml
KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 29
The quantity of milk left 8 litres 250ml

Question 3.
A bottle contains 1l 500 ml of sandal oil. It has to be filled into bottles of 250 ml each. How many bottles are required?

A bottle contains of sandal oil 1 liter 500 ml
For each Bottle 250 ml fill
The no of Bottles = ?
ll = 1000 ml
1 l + 500 ml = 1500 ml
The no of bottle = \(\frac{1500}{250}\) = 6.

Question 4.
An oil can contains 15l of Sunpure oil. Out of this Ram uses 3/ 600 ml in the first month and 5/ 300 ml in the sec ond month. Find the quantity of oil left in the oil can.
Answer:
An oil can contains 15 l of sunpure
Rani uses in first month 31600 ml
Rani uses in second month 51300 ml
KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 30
The total oil used by Rani in 2 months 8l 900 ml
The quantity of oil left with Rani l ml
KSEEB Solutions for Class 5 Maths Chapter 6 Weight and Volume 31

Question 5.
A vessel contains l litre 800 ml of tea. It is poured into 12 glasses of thesame size equally. What is the quantity of tea contained in each glass?
Answer:
A vamel contains of Tea 11800 ml
Tea poured into 12 galsses of the same size equally
1 l = 1000 ml
1l + 800 = 1800 ml
12 such glasses = \(\frac{180}{12}\) = 150ml.

KSEEB Solutions

KSEEB Solutions for Class 5 Maths Chapter 8 Length

Students can Download Maths Chapter 8 Length Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 8 Length

KSEEB Class 5 Maths Length Ex 8.1

I. Answer orally.

Question 1.
How many millimeters make one centimeter?
Answer:
10 millimeters

Question 2.
How many centimeters make one meter?
Answer:
1m = 100cm

KSEEB Solutions

Question 3.
How many meters make one kilometer?
Answer:
1 kilometre = 1000 metres

Question 4.
How many meters make half a kilometer?
Answer:
500 meters

Question 5.
How many centimetres make \(\frac{3}{4}\)
Answer:
KSEEB Solutions for Class 5 Maths Chapter 8 Length 1
= 75 centimeters

KSEEB Solutions

II. Solve the following:

Question 1.
Convert 573cm into meters.
Answer:
1 meter = 100 Centimeter
573cm = 573/100 = 5.73
KSEEB Solutions for Class 5 Maths Chapter 8 Length 2

KSEEB Solutions

Question 2.
Convert 1,378m into kilometers.
Answer:
1 kilometer = 1000 meter
1378 meter = 1378/1000
= 1.378 kilometer
KSEEB Solutions for Class 5 Maths Chapter 8 Length 3

KSEEB Solutions

Question 3.
Convert 1,515 cm into millimeters.
Answer:
1cm = 10 millimeter
1515cm = 1515 × 10
= 15150 millimeter

KSEEB Solutions

Question 4.
Radha’s school is at a distance of 2,450m from her house. Express this distance in km.
Answer:
1 kilometer = 1000 meter
Radha’s school is at a distance of 2,450mt
The distance in km = 2400/1000
= 2.450 kilometers
KSEEB Solutions for Class 5 Maths Chapter 8 Length 4

Question 5.
The length of a ground is 15 meters. Express the length in centimeters.
Answer:
1 meter = 100 centimeter
The length of a ground = 15 meters
The length in centimeter = 100 × 15 = 1500

KSEEB Solutions

KSEEB Class 5 Maths Length Ex 8.2

I. Answer Orally:

Question 1.
The length of a wire is 3m. What is the total length of 5 such wire?
Answer:
The length of a wire is 3 meter The total length of 5 such wire = 5 × 3
= 15 meters

KSEEB Solutions

Question 2.
Out of a roll of cloth measuring 50m, 17m of cloth is sold. Find the length of the remaining cloth.
Answer:
A roll of cloth measure 50 meters 17 meter of cloth is sold
KSEEB Solutions for Class 5 Maths Chapter 8 Length 5
The remaining length of cloth = 33 meter

KSEEB Solutions

Question 3.
24m of colored ribbon is distributed among 8 students equally. What is the length of the ribbon that each one gets?
Answer:
The number of students = 8
The colored ribbons = 24 meter
KSEEB Solutions for Class 5 Maths Chapter 8 Length 6

Question 4.
How many centimeters are there in 9 meters?
Answer:
1 metre = 100 centimetre
9 metre 100 × 9
= 900 centimeter

KSEEB Solutions

Question 5.
The length of a wooden plank is 19m. Out of this 5 pieces of 3tn each is cut off. Find the length of the remaining piece.
The length of a wooden plank = 19 metre
5 pieces of 3 metre each cut off = 5 × 3 = 15

The length of the remaining piece
= 19 – 15
= 4 meter

KSEEB Solutions

II. Add the following:

1. 22m 71cm and 14m 30cm

KSEEB Solutions for Class 5 Maths Chapter 8 Length 7

2. 4km 230m and 22km 280m

KSEEB Solutions for Class 5 Maths Chapter 8 Length 8

KSEEB Solutions

III. Subtract the following:

1. 68m 35cm from 75m 48cm

KSEEB Solutions for Class 5 Maths Chapter 8 Length 9

2. 12km 425m from 17km 650m

KSEEB Solutions for Class 5 Maths Chapter 8 Length 10

KSEEB Solutions

IV. Solve the following:

Question 1.
The length of a line segment is 12cm. Into how many line segments of 3cm each, can it be divided?
Answer:
The length of a line segment = 12cm
Each line segment = 3cm
KSEEB Solutions for Class 5 Maths Chapter 8 Length 11
The length of each line segment = 4cm

KSEEB Solutions

2. Ravi bought 3m 60cm length of pant cloth. He gave lm 20 cm of cloth to his younger brother. What is the length of the remaining cloth?
Ravi bought of pant cloth – 3m, 60cm Ravi gave cloth to his younger brother . = 1m, 20cm
The length of the remaining cloth = ( 3m- lm) (60cm- 20cm)
= 2m, 40cm

KSEEB Solutions

Question 3.
The length of cloth purchased by John is as follows: 2m 20cm for shirt, 1m 20 cm for pant and 4m 80cm for coat. What is the total length of cloth purchased by John?
Answer:
The length of cloth purchased by John
2 m 20cm for shirt
1 m 20cm for pant
4 m 80cm for coat
8 m 20 cm
1 m = 100 centimetre
Total length of cloth purchased by john = 8m, 20cm

KSEEB Solutions

Question 4.
2m 80cm of cloth is required to stitch a frock. What is the length of cloth required to stitch 12 such frocks?
Answer:
To stitch a frock = 2m, 80cm
The length of cloth repaired to stitch 12
such frocks = 12 x 2 = 24
= \(\frac{12 \times 80}{960 \mathrm{cm}}\)
1 m = 100cm
960 cm = \(\frac{960}{100}\) = 9.6m
24 metre + 9 metre + 60 cemtimetre 33 metres, 60 centimetres

KSEEB Solutions

Question 5.
The length of cloth required to stitch 6 pairs of Kurta and Pyjama is 33m. What is the length of cloth required to stitch 1 pair of Kurta & Pyjama?
Answer:
Length of cloth required to stitch 6 pairs
of kurtha & pyjama = 33m
The length of cloth required to stitch are

pair of kurtha & pyjama \(\frac{33}{6}=5.5\)

KSEEB Solutions

Question 6.
The total length of 8 bundles of wire is 204m. Find the length of each bundle of wire.
Answer:
The total length of 8 bundles of wire = 204m
The length of each bundle of wire

KSEEB Solutions for Class 5 Maths Chapter 8 Length 12

KSEEB Solutions

Question 7.
The hight of a table is 1 m 25cm and the height of a stool is 50cm less than the height of the table. Find the height of the stool.
Answer:
The height of a table = 1 m + 25cm
The height of a stoll = 50 cm less than the height of table
= (1m + 25cm) – 50 cm = 75cm

KSEEB Solutions

Question 8.
A gram panchayat constructed a road to connect the village and the main road. On the first day 3 km 460 m of road was constructed and 4 km 540m of road was constructed on the next day. What is the total length of the road constructed?
Answer:
A gram panchayat construct a road on the

KSEEB Solutions for Class 5 Maths Chapter 8 Length 13
The total length of the road constructed 8km

KSEEB Solutions

KSEEB Solutions for Class 5 Maths Chapter 7 Circles

Students can Download Maths Chapter 7 Circles Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 7 Circles

KSEEB Class 5 Maths Circles Ex 7.1

I. Complete the following using suitable
answers:
a) The distance between the centre of a circle and a point on the circle is called radius.
b) In the given figure,

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 1
1. Centre of the circle is O
2. Radius of the circle is represented by the line segment OA
3. Radius of the circle is r

KSEEB Solutions

II. Mark the correct statement by (✓) and false statement by (✘)

a) Only one radius can be drawn to a circle (✘)
b) All radii of a circle are equal (✓)
c) There is only one centre for a circle (✓)
d) In the figure

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 2
i OC is the measure of the radius (✓)
ii. AB is the radius (✘)

KSEEB Solutions

III. i) in each of the following figures, identify the circle, its radius and centre.

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 3

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 4
O – is the centre
Radii – OA, OB, OC, OD, OE, OF, OG, OH

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 5

ii) In figure (c), how many circles are there? Do they have the same centre?

Four, yes

iii) In figure (c), the length of the needle which is showing the hour is the radius ______ of circle.
(c) No (d) Yes (e) OB

iv) In figure (d), the length of the needle which is showing the minute is the radius of ______ circle.

v) in figure (d), which cow’s thread will represent the radius of the circle?
___________. OB

KSEEB Solutions

IV. Measure the length of the radius of each of the following circles. Write them in the given space:

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 6

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 7

KSEEB Solutions

KSEEB Class 5 Maths Circles Ex 7.2

1. Construct the circles with the following radii.

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 8

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 9

KSEEB Solutions

2. The students in the following figures have to draw circles with the given radii. So the students have placed the composes on the scale as shown. If they have placed the compasses correctly put ‘✓’ if not put ‘✘’. Take correct measurements and construct the circles in your book.

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 10

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 11
KSEEB Solutions for Class 5 Maths Chapter 7 Circles 12

KSEEB Solutions

3. Observe the figures given below. Write the name of geometrical instruments required to construct them, against the space provided.

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 13

KSEEB Solutions

4. ‘O’ Mark a point O. With O as centre draw circles with radii 2cm, 3cm, 4cm, 5cm and 6cm.

KSEEB Solutions for Class 5 Maths Chapter 7 Circles 14

KSEEB Solutions

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication

Students can Download Maths Chapter 1 Multiplication Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 1 Multiplication

KSEEB Class 5 Maths Multiplication Revision Exercise

I. Find the product of the following:

1. 35 × 0

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication1

2. 164 × 1

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 2

3. 100 × 0

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 3

KSEEB Solutions

4. 1 × 235

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 4

5. 0 × 1,001

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 5

6. 1 × 55

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 6

II. Find the product of the following:

1. 45 × 16

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 7

2. 63 × 31

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 8

3. 162 × 17

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 9

4. 18 × 42

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 10

5. 83 × 17

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 11

6. 234 × 22

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 12

III. Solve the following problems:

Question 1.
Cost of one notebook is Rs. 16, What is the cost of 12 notebooks?
Answer:
Cost of 1 notebook = Rs. 16
Cost of 12 notebooks = 16 × 12 = 192

KSEEB Solutions

Question 2.
The school fee of a fifth class student is Rs. 38. What is the total fee of 128 students?
Answer:
Fee of a 5th class student = Rs 38
The total fee of student = 128 × 38
KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 13
total amount of 128 Rs.

Question 3.
63 students went on one-day excursion with their class teacher. The class teacher collected Rs. 150 from each student towards travel and lunch expenses. What is the total amount collected?
Answer:
The class teacher collects for each student Rs 150
The total number of students = 63 × 150
KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 14

Question 4.
The cost of a bag containing 10 kg. rice is Rs. 285. Find the cost of 25 bags of rice.
Answer:
The cost of a bay containing 10 kg rice Rs 85
The cost of 25 bays of rice = 285 × 10 = 2850 Rs

Question 5.
The headmaster decides to give first and second prize for various competitions. 16 students got first prize and 16 students got second prize. If the cost of first and second prize is Rs. 11 and Rs. 9 respectively, find the total amound required by headmaster to buy the prizes.
Answer:
The cost of First prise = Rs 11
16 students got First Prize = 16 × 11 = 170
The cost of second prize = Rs 9
16 students got second prize = 16 × 9
KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 15
The total amount required by headmaster to buy the prizes = 176 + 144 = Rs 320

KSEEB Class 5 Maths Multiplication Ex 1.1

I. Multiply:

1. 146 × 173

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 16

2. 178 × 142

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 17

3. 163 × 134

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 18

KSEEB Solutions

4. 183 × 208

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 19

5. 150 × 107

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 20

6. 248 × 212

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 21

7. 316 × 100

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 22

8. 100 × 523

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 23

II. Multiply:

1. 2,861 × 9

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 24

2. 3,947 × 7

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 25

KSEEB Solutions

3. 7,254 × 6

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 26

4. 6,041 × 5

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 27

5. 8,028 × 8

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 28

6. 4,395 × 9

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 29

III. Find the product:

1. 9,025 × 10

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 30

2. 2,549 × 20

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 31

3. 3,746 × 23

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 32

4. 4,756 × 19

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 33

KSEEB Solutions

5. 2,439 × 31

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 34

6. 1,258 × 13

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 35

7. 1,028 × 37

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 36

8. 2,375 × 16

vKSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 37

IV. Multiply:

1. 21,497 × 3

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 38

2. 15,746 × 5

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 39

3. 11,048 × 7

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 40

KSEEB Solutions

4. 10,039 × 9

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 41

V. Solve the following problems:

Question 1.
Mr. Siddappa is a fruit selling agent who e×port oranges. One bo× contains 144 oranges. If he export 259 boxes of oranges, find the total number of oranges exported.
Answer:
A box contains 144 oranges Mr. siddappa export 259 boxes of oranges
The total number of oranges Export 144 × 259 = 37,296

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 42

Question 2.
In a protected forest area, 160 trees and planted in each row and 108 trees in each column. Find the total number of trees planted in the forest area.
Answer:
Trees are planted in each row 160
Trees are planted in each column 108
The total number of trees planted in the forest area = 160 × 108 = 17,280

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 43

Question 3.
A dealer buys 37 bicycles for his showroom: Cost of each bicycle is Rs.2,067. Find the amount paid by the dealer.
Answer:
The cost of each bicycle Rs 2067
A dealer buys 27 bicycles
The amount paid by the dealer = 2,067 × 27 = 55,809 Rs.

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 44

Question 4.
A farmer grew 23 quintals of wheat. He sold them for Rs. 1,935 per quintal. How much amount did the farmer get by selling wheat?
Answer:
One quintal of wheat = Rs 1,935
A farmer grew 23 quiltals of wheat = 23
The farmer get by selling wheat = 1,935 × 23 = Rs 44,505

KSEEB Solutions for Class 5 Maths Chapter 1 Multiplication 45

KSEEB Solutions

KSEEB Solutions for Class 5 Maths Chapter 2 Addition

Students can Download Maths Chapter 2 Addition Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 2 Addition

KSEEB Class 5 Maths Addition Revision Exercise

I. Add the following numbers:

1) 4.368 + 2.521

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 1

2) 2.673 + 5.134

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 2

KSEEB Solutions

3) 3.653 + 4.213 + 1.156

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 3

4) 1.345 + 2.463 + 564

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 4

KSEEB Solutions

II. Solve the following problems:

1. Sanmati deposited Rs. 3,672 on Monday and Rs 4,678 on Tuesday in the bank. Find the amount deposited by her.

Sanmati deposit – Rs 3,672 on Monday
Sanmati deposit – Rs 4,678 on Tuesday
Total amount deposit by Sanmati – Rs 8,350

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 5

KSEEB Solutions

2. The population of a village is 3,389. The population of another village is 4,893. Find the total population of both the villages
The population of a village – 3,389
The population of Another village – 4,893
Total population of both villages – 8,282

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 6

KSEEB Solutions

3. The number of students of first standard in all the schools of a panchayat is 1,673, second standard is 1,845, third standard is 1,437 and the fourth standard is 1,547. Find the total number of students.

In a panchayat the member of students of 1st standard – 1,673
In a panchayat the member of students of 2nd standard – 1,845
In a panchayat the’member of students of 3rd standard – 1,437
In a panchayat the member of students of 4th standard -1,547
The total number of students – 6,502

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 7

KSEEB Solutions

KSEEB Class 5 Maths Addition Revision Ex 2.1

I. Find the sum of each of the following:

1) 36,417 + 32,532

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 8

2) 28,490 + 61,306

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 9

KSEEB Solutions

3) 12,973 + 46,016

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 10

4) 23462 + 52,304

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 11

5) 42,802 + 34,063

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 12

KSEEB Solutions

II. Find the sum of each of the following:

1. 36,907 + 53,613

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 13

2. 24,296 + 36,578

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 14

3. 43,374 + 36,654

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 15

KSEEB Solutions

4. 25,700 + 2,246 + 16,413

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 16

5. 25,236 + 34,051 + 8,368

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 17

KSEEB Solutions

III. Solve the following problems:

1. There were 26,759 trees in the protected area of a forest. 13,842 trees were planted during Vanamahostava. Find the total number of trees in the protected area of the forest.
There were trees in the protected area
Trees were planted – 26,759
During vanamahotsava – 13,842
The total number of trees in the protected area of the forest – 40,601

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 18

2. A co-operative milk dairy collects 15,209 liters of milk from farmers in a week and 16,826 liters of milk in the next week. How many liters of milk was collected from the farmers in two weeks?
A co-operative milk diary collect of milk from farmers in a week – 15,209
Milk from farmers in the next week – 16,826
The total liters of milk from farmers – 32,035

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 19

KSEEB Solutions

3. An Indian cricketer scored 14,025 runs in the test cricket matches and 15,759 runs in one-day cricket matches. How many runs did the cricketer score in all?
An Indian cricketer scored runs in the test cricket matches – 14,025
Runs scored in one-day matches – 15,759
The total runs scored in both matches – 29,784

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 20

KSEEB Solutions

4. A public library in a city has 17,943 books in Kannada, 14,635 books in Hindi and 10,284 books in English. How many books are there in the library altogether?
In a city, A public library books in Kannada – 17,943
In a city, A public library books in English – 10,284
In a city, A public library books in Hindi – 14,63 5
The total number of books in the library altogether – 42,862.

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 21

KSEEB Solutions

5. In an assembly election three candidates were polled 32,135 votes, 29,048 votes and 4,951 votes respectively. Find the total number of votes polled.
In a election three candidates were polled – 32,135 votes
The total number of votes polled – 66,134

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 22

6. The population of a town is 54,872 and another town is 45,127. Find the total population of both the towns. (Additional Question)
The population of a town – 54,872
The population of another town – 45,127
The total population of both the towns – 99,999.

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 23

KSEEB Solutions

7. During Dasara exhibition, 4,826 people visited agricultural stall, .15,468 people visited popcorn stall and 8,401 people visited handicraft stall. How many people visited these three stalls? (Additional Question)
During dasara Exhibition.
Agricultural stall – 04826 People
Popcorn stall – 15468 People
Handicraft stall – 08401 People
The total number of peoples in three stales – 28,695.

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 24

8. A Charitable trust distributes Rs. 9,275 as a scholarship to the students in the month of July and Rs. 10,325 in the month of August Find the total amount of scholarships distributed.
A charitable trust distributes (Additional Question)
Scholarships – 09,275
students in July Scholarships – 10,325
students in August. – 19,600
The total amount of scholarship – Rs 19,600.

KSEEB Solutions for Class 5 Maths Chapter 2 Addition 25

KSEEB Solutions

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