## KSEEB Solutions for Class 5 Maths Chapter 7 Time

Students can Download Maths Chapter 7 Time Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

## Karnataka State Syllabus Class 5 Maths Chapter 7 Time

### KSEEB Class 5 Maths Time Ex 7.1

Question 1.
At what time do you get up in the morning?
6.30 A.M

Question 2.
At what time do you go to school?
9.0 A.M

Question 3.
At what time do you go out to play?
5.0 P.M

Calculate How Many Weeks Between Dates

Question 4.
From what time to what time do you study during night?
6P.Mto 10 P.M

Question 5.
At what time you will have your dinner?
9 P.M

Question 6.
At what time do you go to bed at night?
10 P.M

II. Denote the following timings in a.m and p.m.

1. 10:15 morning
10.15 A.M

2. 8:10 night
8.10 P.M

3. 1:45 afternoon
1.45 P.M

4. 4:30 morning
4.30 A.M

5. 9:45 night
9.45 P.M

6. 5:35 evening
5.35 P.M

III. Convert the following timings to 12-hour clock timing. Also, write in a.m. and p.m.

1. 23:25 hour
11.25 P.M

2. 12:35 hour
12.35 P.M

3. 14:45 hour
2.45 P.M

4. 18:40hour
6.40 P.M

5. 08:30hour
8.30 P.M

6. 11:55hour
11.55 A.M

7. 02:15 hour
2.15 A.M

8. 15:37 hour
3.37 P.M

9. 21:40 hour
9.40 P.M

10. 16:45 hour
4.45 P.M

### KSEEB Class 5 Maths Time Ex 7.2

Question 1.
How many seconds make 1 minute?
60 Seconds

Question 2.
How many minutes make 1 hour?
60 minutes

Question 3.
How many hours are there in a day?
24 hours

Question 4.
How many days are there in a week?
7 Days

Question 5.
How many months are there in a year?
12 months

Question 6.
How many days are there in a year?
365 days

Question 7.
How many days are there in a month?
30 days

Question 8.
How many days are there in February?
28 days of February

Question 9.
What do you mean by leap year?
The year in which there are 29 days in February is called leap year.

Question 10.
What is the sum of 3hr 20min and 4hr 30min?

1. 4 hr 40 min and 6hr 10 min

2. 3 hr 30min and 2hr 20min

3. 2 hr 50min and 3hr 40min

4. 5hr 30min and 2hr 50min

5. 3 hr 15min 18s and 1 hr 19min 17s

6. 2 hr 30min 40s and 4hr 50min 30s

7. 5hr 45min 30s and 3hr 25min 40s

8. 3yr 8mth and 2yr 7mth

9. 5yr 6mth and 4yr 9mth

### KSEEB Class 5 Maths Time Ex 7.3

Question 1.
How many seconds make 5 minutes?
1 min = 60 sec
5 min = 60 × 5 = 300 sec

Question 2.
How many minutes are there in 10 hours?
10 hr = 60 min
= 60 × 10 = 600 min

Question 3.
How many seconds make 1 hour?
1 hr = 60 min
1 min = 60 sec
1 hr = 60 × 60
1 hr = 3600 sec

Question 4.
What is the time interval between 9:30 a.m. and 12.00 noon?

Question 5.
Find out the railway clock time for 5:30 p.m.
5.30 P.M – 17.30 hrs

II. Subtract the following:

1. 5hr 10min from 7hr 30 min

2. 3hr 20min 25s from 4hr 40min 50s

3. 2hr 5 min 5hr 30min

4. 5hr 40min from 6hr 10min

5. 3yr 8mth from 6yr 4mth year month

6. 2yr 9mth from 5yr 6mth

7. 4yr 11mth from 7yr 5mth

### KSEEB Class 5 Maths Time Ex 7.4

I. Solve the following problems:

Question 1.
A worker enters the factory at 6:15 a.m. He finishes his work and leaves the factory at 2:15 p.m. For how many hours has he worked in the factory?
A worker enters the factory 6:15 A.M
He finished works & leaves 2:15 P.M

8:00 He worked in the factory 8 hrs

Question 2.
A school closes for mid-term vacation on October 3rd and reopens on October 31st. How many days has the school closed for midterm vacation?
A school classes for midterm vacation on October 3rd
The school re-open on October 31st
31st of October
3rd of October
28
The school closed for midterm vacation = 28 days

Question 3.
A school starts at 8:00 on Saturday and closes at 12:30 p.m. How many hours did the school work on that day?
A school starts at 8.00 A.M on Saturday
The school closes at 12.30 P.M

The school work on Saturday = 4 hr 30 min

Question 4.
Shyam comes to his office at 9:00 a.m. He works 8 hours in his office. What time does he leave his office in the evening?
Shyam comes to his office 9.00 A.M.
Shyam works 8 hours in his office

Shyam leaves his office at 5 P.M in the evening

Question 5.
Fathima studies for 5hr. 10min in her school. At home, she studies 2hr. 50min. What is the total number of hours she studied on that day?
Fathima studies in Her school

Fathima total number of hours studies 8 hrs

Question 6.
Mahesh spends his 15days holidays in his uncle’s place from 3 – 10 – 2011. On which date does he leave his uncle’s place?
Mahesh spends his 15 days holidays
Mahesh spends his holidays on

Mahesh leave his uncle’s place on 18-10-2011

## KSEEB Solutions for Class 5 EVS Environmental Studies Karnataka State Syllabus

Expert Teachers at KSEEBSolutions.com has created KSEEB Solutions for Class 5 EVS Environmental Studies Pdf Free Download in English Medium and Kannada Medium of 5th Standard Karnataka Environmental Studies Textbook Solutions Answers Guide, Textbook Questions and Answers, Notes Pdf, Model Question Papers with Answers, Study Material, are part of KSEEB Solutions for Class 5. Here we have given KTBS Karnataka State Board Syllabus for Class 5 EVS Environmental Studies Textbook Solutions.

## Karnataka State Board Syllabus for Class 5 EVS Environmental Studies Solutions in English Medium

5th Class Environmental Studies Textbook Solutions Karnataka State Syllabus English Medium

## Karnataka State Board Syllabus for Class 5 EVS Environmental Studies Solutions in Kannada Medium

5th Class Environmental Studies Textbook Solutions Karnataka State Syllabus Kannada Medium

We hope the given KSEEB Solutions for Class 5 Environmental Studies Pdf Free Download in English Medium and Kannada Medium of 5th Std Karnataka Environmental Studies Textbook Answers Solutions Guide, Textbook Questions and Answers, Notes Pdf, Model Question Papers with Answers, Study Material will help you. If you have any queries regarding KTBS Karnataka State Board Syllabus for Class 5 Environmental Studies Textbooks Solutions, drop a comment below and we will get back to you at the earliest.

## KSEEB Solutions for Class 5 Maths Karnataka State Syllabus

Expert Teachers at KSEEBSolutions.com has created KSEEB Solutions for Class 5 Maths Pdf Free Download in English Medium and Kannada Medium of 5th Standard Karnataka Maths Textbook Solutions Answers Guide, Textbook Questions and Answers, Notes Pdf, Model Question Papers with Answers, Study Material, are part of KSEEB Solutions for Class 5. Here we have given KTBS Karnataka State Board Syllabus for Class 5 Maths Textbook Solutions.

## Karnataka State Board Syllabus for Class 5 Maths Solutions in English Medium

5th Class Maths Textbook Solutions Karnataka State Syllabus

5th Class Maths Textbook Solutions Karnataka State Syllabus Part 1

5th Class Maths Textbook Solutions Karnataka State Syllabus Part 2

## Karnataka State Board Syllabus for Class 5 Maths Solutions in Kannada Medium

5th Class Maths Textbook Solutions in Kannada Medium Karnataka State Syllabus

5th Class Maths Textbook Solutions Karnataka State Syllabus Part 1

5th Class Maths Textbook Solutions Karnataka State Syllabus Part 2

We hope the given KSEEB Solutions for Class 5 Maths Pdf Free Download in English Medium and Kannada Medium of 5th Std Karnataka Maths Textbook Answers Solutions Guide, Textbook Questions and Answers, Notes Pdf, Model Question Papers with Answers, Study Material will help you. If you have any queries regarding KTBS Karnataka State Board Syllabus for Class 5 Maths Textbooks Solutions, drop a comment below and we will get back to you at the earliest.

Tili Kannada Text Book Class 5 Answers Solutions Guide Notes Pdf free download is part of KSEEB Solutions for Class 5. Here we have given Karnataka State Board Syllabus 5th Standard 2nd Language Tili Kannada Textbook Solutions. Students can also read Siri Kannada Text Book Class 5 Solutions of 1st language.

## Tili Kannada Text Book Class 5 Answers Solutions Guide (2nd Language)

Class 5 Tili Kannada Puraka Odu Karnataka State Board Solutions

Purvasiddhata Pathagalu

We hope the given Tili Kannada Text Book Class 5 Solutions Answers Guide Notes Pdf free download will help you. If you have any queries regarding Karnataka State Board Syllabus 5th Standard 2nd Language Tili Kannada Textbook Answers, drop a comment below and we will get back to you at the earliest.

Siri Kannada Text Book Class 5 Answers Solutions Guide Notes Pdf free download is part of KSEEB Solutions for Class 5. Here we have given Karnataka State Board Syllabus 5th Standard 1st Language Siri Kannada Textbook Solutions. Students can also read Tili Kannada Text Book Class 5 Solutions of 2nd language.

## Siri Kannada Text Book Class 5 Answers Solutions Guide (1st Language)

Class 5 Siri Kannada Puraka Pathagalu Karnataka State Board Solutions

## Tili Kannada Text Book Class 5 Answers Solutions Guide (2nd Language)

Class 5 Tili Kannada Puraka Odu Karnataka State Board Solutions

Purvasiddhata Pathagalu

We hope the given Siri Kannada Text Book Class 5 Solutions Answers Guide Notes Pdf free download will help you. If you have any queries regarding Karnataka State Board Syllabus 5th Standard 1st Language Siri Kannada Textbook Answers, drop a comment below and we will get back to you at the earliest.

## KSEEB Solutions for Class 5 Karnataka State Syllabus

Expert Teachers at KSEEBSolutions.com has created KSEEB Solutions for Class 5 all subjects Pdf Free Download in English Medium and Kannada Medium of 5th Standard Karnataka Textbook Solutions, Textbook Questions and Answers, Guide, Notes Pdf, Model Question Papers with Answers, Study Material, are part of KSEEB Solutions. Here we have given KTBS Karnataka State Board Syllabus for Class 5 Textbook Solutions.

## Karnataka State Board Syllabus for Class 5 Textbooks Solutions

KSEEB Solutions for Class 5 Karnataka State Syllabus

We hope the given KSEEB Solutions for Class 5 all subjects Pdf Free Download in English Medium and Kannada Medium of 5th Std Karnataka Textbook Solutions, Textbook Questions and Answers, Guide, Notes Pdf, Model Question Papers with Answers, Study Material will help you. If you have any queries regarding KTBS Karnataka State Board Syllabus for Class 5 Textbooks Solutions, drop a comment below and we will get back to you at the earliest.

## KSEEB Solutions for Class 5 Maths Chapter 4 Decimal Fractions

Students can Download Maths Chapter 4 Decimal Fractions Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

## Karnataka State Syllabus Class 5 Maths Chapter 4 Decimal Fractions

### KSEEB Class 5 Maths Decimal Fractions Revision Exercise

In order to round to one decimal place, you must be familiar with the concept of rounding numbers.

I. Read the following decimals and write them in words:

1. 0.5
Zero point five

2. 0.13
Zero point one three

3. 1.7
One point seven

4. 5.21
Five point two one

II. Write the numeral representing each of the following:

1. Zero point one – two
0.12

2. Six point eight
6.8

3. Ten point five
10.5

4. Four point zero two.
4.02

5. Six point eight four
6.84

6. One hundred eight point zero six
108.06

III. Fill in the blanks:

1. 8mm = 0.8 cm
1 cm = 10 mm
8 mm = $$\frac{8}{10}$$ = 0.8 cm

2. 75 mm = 7.5 cm
1 cm = 10 mm
75 mm = $$\frac{75}{10}$$ = 7.5 cm

3. 8 cm 5 mm = 8.5 cm
1 cm = 10 mm
5 mm = $$\frac{5}{10}$$ = 0.5
8 + 0.5 = 8.5 cm+

4. 525 mm = 5.2 cm
1 mm = $$\frac{10}{10}$$
525 mm = $$\frac{525}{10}$$ = 52.5cm

IV. Fill in the blanks:

1. 8 cm = 0.08 m
1 mm = 100 cm
8cm = $$\frac{8}{100}$$ = 0.08

2. 72 cm = 0.72 m.
1 mm = 100 cm
72 = $$\frac{72}{100}$$ = 0.72

3. 375 cm = 3.75 m.
1 mm = 100 cm
375 cm = $$\frac{375}{100}$$ = 3.75

4. 4m 80 cm = 4.08 m.
1 mm = 100 cm
80cm = $$\frac{80}{100}$$ = 0.8
4m + 0.8m = 4.08 m

5. 15m. 6 cm = 15.06 m.
1 mm = 100 cm
6 cm = $$\frac{6}{100}$$ = 0.06
15m + 0.06 = 15.06m

V. Write in decimal fractions:

The long division is carried subsequently, which gives the output of 58 5 8 as a decimal. 5/8 as a decimal.

1. 75 paise = Rs. ________
1 paise = 100 paise
75 paise = $$\frac{75}{100}$$ = 0.75

2. 10 rupees and 25 paise = Rs. _________
1 rupees = 100 paise
25 paise = $$\frac{25}{100}$$ = 0.25
10 rupees + 0.25 paise = 10.25

3. 870 paise = Rs._________
1 rupees = 100 paise
870 = $$\frac{870}{100}$$ = 8.70

4. 782 rupees and 10 paise = Rs. _________
1 rupees = 100 paise
782 rupees 782.10 paise

5. 2050 paise = Rs. _________
1 rupees = 100 paise
2050 paise = $$\frac{2050}{100}$$ = 20.50

### KSEEB Class 5 Maths Decimal Fractions Ex 4.2

I. Write the following fractions as decimal fractions:

What is 11/16 as a decimal? 11/16 as a decimal is 0.6875

1. $$\frac{8}{10}$$ = 0.8

3/5 as a decimal is 0.6

2. $$\frac{7}{10}$$ = 0.7

3. $$\frac{6}{10}$$ = 0.6

4. $$\frac{16}{10}$$ = 1.6

5. $$\frac{42}{10}$$ = 4.2

6. $$\frac{83}{10}$$ = 8.3

7. $$\frac{7}{100}$$ = 0.07

8. $$\frac{72}{100}$$ = 0.72

9. $$\frac{861}{100}$$ = 8.61

10. $$\frac{162}{10}$$ = 16.2

11. $$\frac{141}{100}$$ = 1.41

12. $$\frac{1461}{100}$$ = 14.61

13. $$\frac{1}{2}$$ = 0.5

14. $$\frac{3}{4}$$ = 0.75

15. $$\frac{2}{5}$$ = 0.4

16. $$\frac{7}{20}$$ = 0.35

5/9 as a decimal is 0.56

17. $$\frac{38}{50}$$ = 0.76

18. $$\frac{17}{25}$$ = 0.68

19. $$\frac{13}{20}$$ = 0.65

20. $$\frac{8}{25}$$ = 0.32

II. Write the following decimal fractions as fractions:

1. 0.7
$$\frac{7}{10}$$

2. 0.02
$$\frac{2}{100}$$

3. 3.8
$$\frac{38}{10}$$

4. 14.5
$$\frac{145}{10}$$

5. 0.56
$$\frac{56}{100}$$

6. 8.03
$$\frac{803}{100}$$

7. 14.57
$$\frac{1457}{100}$$

8. 85.4
$$\frac{854}{10}$$

9. 147.5
$$\frac{1475}{10}$$

10. 8.5
$$\frac{85}{10}$$

11. 85.61
$$\frac{8561}{100}$$

12. 6.84
$$\frac{8561}{100}$$

## KSEEB Solutions for Class 5 Maths Chapter 3 Mental Arithmetic

Students can Download Maths Chapter 3 Mental Arithmetic Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

## Karnataka State Syllabus Class 5 Maths Chapter 3 Mental Arithmetic

### KSEEB Class 5 Maths Mental Arithmetic Revision Exercise

I. Round off each of the following numbers to nearest thousands place:

1. 7,547

7,547 lie between 7000 and 8000
Replace by zero

2. 3,469
3,469 lie between 2000 and 3000
Replace by zero

3. 15,238
15,038
Replace by zero

4. 32,658
32,658
Replace by zero

II. Round off each of the following numbers to nearest ten thousands place:

1. 26,674
26,674
Replace to zero

2. 32,464
32,464
Replace to zero

3. 46,379
46,379
Replace to zero

4. 53,668
53,668
Replace to zero

III. Estimate sum of the following by rounding off to nearest thousands place:

1. 42,125 + 35,637
42,125 is rounded off to nearest thousand – 42,000
35,637 is rounded off to nearest thousand – 36,000

Estimate sum is 78,000
Verification by actual addition – 42125

2. 54,837 + 41,354
54,837 is rounded off to nearest thousand – 55,000
41,354 is rounded offto nearest thousand – 41,000

Estimate sum is 96,000

3. 33,231 + 20,097
33,321 is rounded off to nearest thousand – 33,000
20,097 is rounded off to nearest thousand – 20,000

Estimate sum is 53,000

4. 47,463 + 41,541
47,463 is rounded off to nearest thousand – 47,000
41,541 is rounded off to nearest thousand – 42,000

Estimate sum is 89,000

IV. Estimate the sum of the following by rounding off to nearest ten thousands place:

1. 56,256 + 24,872
56,256 is rounded off to nearest ten thousand – 55,000
24,872 is rounded off to nearest ten thousand – 25,000

Estimate sum is 80,000

2. 47,671 + 28,745
47,671 is rounded off to nearest ten thousand – 50,000
28,745 is rounded off to nearest ten thousand – 30,000

Estimate sum is 80,000

3. 32,184 + 45,138
32,184 is rounded off to nearest ten thousand – 30,000
45,138 is rounded off to nearest ten thousand – 50,000

Estimate, sum is 80,000

4. 15,025 + 40,165
15,025 is rounded off to nearest ten thousand – 20,000
40,165 is rounded off to nearest ten thousand – 40,000

Estimate sum is 60,000

Detailed Steps to Round to Nearest Hundredth by Hand ·

V. Estimate the difference of the following by rounding off to nearest thousands place:

1. 65,487 – 46,502
65,487 is rounded off to nearest ten thousand – 64,000
46,502 is rounded off to nearest ten thousand – 46,000

Estimate sum is 18,000
Verification by actual substruction

2. 45,630 – 32,148
45,630 is rounded off to nearest ten thousand – 44,000
32,148 is rounded off to nearest ten thousand – 30,000

Estimate sum is 14,000
Verification by actual substruction

3. 57,146 – 25,472
57,146 is rounded off to nearest ten thousand – 56,000
25,472 is rounded off to nearest ten thousand – 24,000

Estimate sum is 32,000
Verification by actual substraction

4. 60,046 – 15,247
60,046 is rounded off to nearest ten thousand – 60,000
15,247 is rounded off to nearest ten thousand – 15,000

Estimate sum is 45,000
Verification by actual substraction

VI. Estimate the difference of thefolhming hy rounding off to nearest ten thousands place:

1. 51,689 – 34,685
51,689 is rounded off to nearest ten thousand – 50,000
34,685 is rounded off to nearest ten thousand – 30,000

Estimate sum is 20,000
Verification by actual substraction

2. 86,853 – 47,829
86,853 is rounded off to nearest ten thousand – 85,000
47,829 is rounded off to nearest ten thousand – 45,000

Estimate difference is 40,000
Verification by actual substraction

3. 80,808 – 55,055
80,808 is rounded off to nearest ten thousand – 80,000
55,055 is rounded off to nearest ten thousand – 50,000

Estimate difference is 30,000
Verification by actual substractiori

4. 77,777 – 44,444
77,777 is rounded off to nearest ten thousand – 70,000
44,444 is rounded off to nearest ten thousand – 40,000

Estimate difference is 30,000
Verification by actual substraction

VII. Estimate the product of each of the following hy rounding off to its highest place:

1. 428 × 54
428 is rounded off to nearest hundred as 400
54 is rounded off to nearest ten as 50

Estimate product is 20,000

2. 878 × 46
876 is rounded off to nearest hundred as 900
46 is rounded off to nearest ten as 50

Verification by actual multiplication

Verification by actual multiplication

3. 5,476 × 11
5,476 is rounded off to nearest hundred as 5000
11 is rounded off to nearest ten as 10

Verification by actual multiplication

Verification by actual multiplication

4. 2,645 × 18
2,645 is rounded off to nearest hundred as 3000
18 is rounded off to nearest ten as 20

Verification by actual multiplication

Verification by actual multiplication

VIII. Estimate the quotient of each of the following hy rounding off to its highest place.

1. 398 ÷ 82
398 is rounded off to nearest hundred aS 400
82 is rounded off to nearest ten as ÷ 80
Estimate quotient $$\frac{800}{40}$$ = 5

2. 786 ÷ 22
786 is rounded off to nearest hundred as 800
22 is rounded off to nearest ten as ÷ 20
Estimate quotient $$\frac{800}{20}$$ = 40

3. 3,265 ÷ 58
3,265 is rounded off to nearest hundred as 3000
58 is rounded off to nearest ten as ÷ 60
Estimate quotient $$\frac{3000}{60}$$ = 50

4. 7,687 ÷ 43
7,687 is rounded off to nearest hundred as 8000
43 is rounded off to nearest ten as ÷ 40
Estimate quotient $$\frac{8000}{40}$$ = 200

IX. Solve the following problems.

Question 1.
A garment company stitched 16,783 shirts and 12,438 pants in a month. Estimate the total number of dresses stitched to the nearest ten thousands place.
A garment company stitched shirts – 16,783
A garment company stitched pants – 12,438.
(To the nearest ten thousand place) – 20,000
(To the nearest ten thousand place) – 10,000

Question 2.
A news paper agent sells 36,721 papers in first month and 24,172 papers in sec¬ond month. Estimate the decrease in sale of the newspaper in second month to the nearest ten thousands place.
In first month a news paper agents sells – 36,721
In Second month a news paper agents sells – 24,172
(To the nearest ten thousand place)
first month – 40,000
Second month – 20,000

The estimated substraction of sale of the newspaper 20,000

Question 3.
A train can cover 225 km in one hour. Estimate the distance covered in a day to the highest place.
A train can cover 225 Km in 1 hour
The distance covered in a day = 24 hours
(To the highest place) 200

Question 4.
A carpenter earned Rs. 18,634 during the month of November and Rs. 32,645 in December. Estimate how much more he earned in December to the nearest ten thousands place.
A carpet earned in november – 18,634
A carpet earned in december – 32,645
(To the nearest ten thousand place)

## KSEEB Solutions for Class 5 Maths Chapter 4 Factors and Multiples

Students can Download Maths Chapter 4 Factors and Multiples Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

## Karnataka State Syllabus Class 5 Maths Chapter 4 Factors and Multiples

### KSEEB Class 5 Maths Factors and Multiples Ex 4.1

What is the factor of 50? The factors of 50 are 1, 2, 5,10, 25, …

Question 1.
Circle the multiples of 4 with blue colour, cross the multiples of 6 with red colour and underline the multiples of 9 with a pencil.

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96 & 100 → Multiples of 4
6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90 & 96 → Multiples of 6
9, 18, 27, 36, 45, 54, 63, 72, 81, 90 & 99 → Multiples of 9

Question 2.
Circle the multiples of 7 in the following numbers.
7, 13, 14, 21, 22, 35, 36, 42 and 45
7, 14, 21, 35, 42

Question 3.
Circle the multiples of 12 in the following numbers.
6,12,18, 24, 30, 36, 42, 48, 54, 60, 66, 72
12, 24, 36, 48, 60, 72

Question 4.
Write the multiples of 2 between the numbers 50 and 60.
52, 54, 56, 58
G : 52/2 = 26

Question 5.
Write the multiples of 15 between the numbers 50 and 100.
60, 75, 90
G : 15 × 4 = 60

Question 6.
Write five multiples of the following numbers.
5 multiples of 15 are 15, 30, 45, 60 & 75.
5 multiples of 17 are 17, 34, 51, 68 & 85.
5 multiples of 19 are 19, 38, 57, 76 & 95
5 multiples of 23 are 23, 46, 69, 92 & 115.

The factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24! 24 has 8 factors in total.

Question 7.
Find which of the following numbers are factors of 24?
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 16, 18, 20, 22 ಮತ್ತು 24
24 – 1 × 24
24 – 4 × 6
24 – 2 × 12
24 – 3 × 8
1, 2, 3, 4, 6, 8, 12 & 24

Question 8.
Write any two factors of the following numbers.
6, 18, 28, 36, 42, 48
Any two factors of 6 are 2 & 3
Any two factors of 28 are 2 & 14
Any two factors of 42 are 2 & 21
Any two factors of 18 are 2 & 9
Any two factors of 36 are 3 & 12
Any two factors of 48 are 2 & 24

Factoring Calculator will help you find the factors 18 i.e. 1, 2, 3, 6, 9, 18 the numbers that when divided results in a whole number and a zero remainder.

Question 9.
Write all the factors of the following numbers.
9, 13, 20, 26, 40
All the factors of 9 are 1,3 & 9 All the factors of 13 are 1 & 13 All the factors of 20 are 1, 2, 4, 5, 10 & 20
20 = 1 × 20
2 × 10 = 20
4 × 5 = 20
5 × 4 = 20
10 × 2 = 20
20 × 1 = 20
All the factors of 26 are 1 ,2, 13 & 26
All the factors of 40 are 1, 2, 4, 5, 8, 10, 20 & 40

Question 10.
Write the factor tree for the following numbers:

Prime factors of 84 are 2×2, 3, 7.

Question 11.
Complete the following factor tree by writing missing numbers.

(i)

(ii)

The prime factors of 38 are 2 and 19.

## KSEEB Solutions for Class 5 Maths Chapter 5 Fractions

Students can Download Maths Chapter 5 Fractions Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

## Karnataka State Syllabus Class 5 Maths Chapter 5 Fractions

### KSEEB Class 5 Maths Fractions Ex 5.1

Question 1.
Which of the following figures have been divided into parts of the same size?

b & c.

Question 2.
Draw a line to divide each of these figures into the required number of equal parts.

This online Least Common Denominator Calculator (or LCD calculator) calculates the least common denominator (or the lowest common denominator) of fractions.

Question 3.
Write each of the following as a fraction
a) Half –$$\frac{1}{2}$$
b) Two-third – $$\frac{2}{3}$$
c) Two-tenth – $$\frac{2}{10}$$
d) Five-seventh – $$\frac{5}{7}$$
e) Five-sixteenth – $$\frac{5}{16}$$
f) Five-twelveth – $$\frac{5}{12}$$
g) Eight-nineth – $$\frac{8}{9}$$
h) Four-nineth – $$\frac{4}{9}$$
i) Three-fourth – $$\frac{3}{4}$$
j) Two-fifth – $$\frac{2}{5}$$

Question 4.
Write each of the fraction in words
a) $$\frac{2}{5}$$ – two-fifth
b) $$\frac{3}{4}$$ – three-fourth
c) $$\frac{7}{10}$$ – seven-tenth
d) $$\frac{11}{12}$$ – eleven-twelveth
e) $$\frac{2}{3}$$ – two-third
f) $$\frac{4}{5}$$ – four-fifth
g) $$\frac{5}{8}$$ – five-eight
h) $$\frac{3}{7}$$ – three-seventh
i) $$\frac{5}{6}$$ – five-sixth
j) $$\frac{7}{9}$$ – seven-nineth

Question 5.
What fraction of the figure is shaded?
a) $$\frac{2}{3}$$

b) $$\frac{2}{4}$$

c) $$\frac{5}{8}$$

d) $$\frac{7}{12}$$

e) $$\frac{7}{15}$$

f) $$\frac{6}{18}$$

Question 6.
Fill in the blanks:
a) The denominator of the fraction $$\frac{1}{8}$$ is 8
b) The numerator of the fraction is $$\frac{2}{5}$$ 2
c) 3 is the denominator of fraction $$\frac{1}{3}$$
d) 1 is the numerater of the fraction $$\frac{1}{5}$$
e) In a fraction, the denominator is written below the numerator separated by a line.

Question 7.
Write down the fraction of the coloured portions in these figures.
a)
$$\frac{1}{5}$$

b)
$$\frac{2}{4}$$

c)
$$\frac{4}{12}$$

d)
$$\frac{3}{6}$$

e)
$$\frac{4}{9}$$

Question 8.
Write the fraction for the shaded part in each of the following figures.
$$\frac{4}{7}$$

$$\frac{2}{9}$$

$$\frac{7}{10}$$

Question 9.
Colour the figures as instructed.

Eg: $$\frac{7}{10}$$

$$\frac{1}{5}$$

$$\frac{2}{3}$$

$$\frac{2}{9}$$

Question 10.
Represent the given fraction by drawing a line.
a) What is $$\frac{1}{3}$$ of 12?

b) What is $$\frac{2}{5}$$ of 15?

c) What is $$\frac{2}{7}$$ of 21?

Question 11.
Shade the figures to show the fractions.
a) $$\frac{6}{11}$$

b) $$\frac{7}{20}$$

c) $$\frac{8}{15}$$

Question 12.
Which of the following shaded figures represent $$\frac{4}{9}$$ ?

Question 13.
Which of the following shaded figure represents $$\frac{5}{12}$$ and give reason.

fig b&d, Reason: 5 objectives out of 12 are shaded

Question 14.
Represent the grouped parts as fractions:
a)
$$\frac{4}{5}$$

b)
$$\frac{3}{7}$$

c)
$$\frac{5}{6}$$

### KSEEB Class 5 Maths Fractions Ex 5.2

I. Fill in the gaps using > or < signs.

### KSEEB Class 5 Maths Fractions Ex 5.3

I. Complete the series.

2 × 2 = 4
2 × 3 = 6

3 × 2 =6
3 × 3 = 9
3 × 4 = 12

5 × 2 = 10
7 × 2 = 14

5 × 3 = 15
7 × 3 = 21

5 × 6 = 30
7 × 6 = 42

II. Write the next three equivalent fractions.

2 × 3 = 6, 5 × 3 = 15
2 × 4 = 8, 5 × 4 = 20
2 × 5 = 10, 5 × 5 = 25

3 × 3 = 9
3 × 4 = 12
3 × 5 = 15

9 × 3 = 27, 11 × 3 = 33
9 × 4 = 36, 11 × 4 = 44
9 × 5 = 45, 11 × 5 = 55

III. Are the two fractions equivalent?

Question 1.
$$\frac{3}{5}$$ and $$\frac{18}{30}$$
Yes,Reason, $$\frac{3}{5} \times \frac{6}{6}=\frac{18}{30}$$

Question 2.
$$\frac{12}{17}$$ and $$\frac{8}{20}$$
No, Both terms are different

Question 3.
$$\frac{2}{7}$$ and $$\frac{7}{21}$$”
No, Both terms are different

Question 4.
$$\frac{5}{11}$$ and $$\frac{25}{55}$$
Yes,Reason, $$\frac{5 \times 5}{11 \times 5}=\frac{25}{55}$$

IV. Find an equivalent raction of $$\frac{4}{7}$$ having:

1. 16 as numerator
$$\frac{4 \times 4}{7 \times 4}=\frac{16}{28}$$

2. 24 as numerator
$$\frac{4 \times 6}{7 \times 6}=\frac{24}{42}$$

3. 21 as denominator
$$\frac{4 \times 3}{7 \times 3}=\frac{12}{24}$$

4. 84 as denominator
$$\frac{4 \times 12}{7 \times 12}=\frac{48}{84}$$

### KSEEB Class 5 Maths Fractions Ex 5.5

I. Reduce each of the following fractions into its lowest form.

1. $$\frac{8}{16}=\frac{1}{2}$$
2. $$\frac{5}{10}=\frac{1}{2}$$
3. $$\frac{54}{108}=\frac{1}{2}$$
4. $$\frac{4}{20}=\frac{1}{5}$$
5. $$\frac{3}{15}=\frac{1}{5}$$
6. $$\frac{12}{16}=\frac{3}{4}$$
7. $$\frac{9}{27}=\frac{1}{3}$$
8. $$\frac{36}{48}=\frac{3}{4}$$
9. $$\frac{24}{56}=\frac{3}{7}$$
10. $$\frac{24}{72}=\frac{1}{3}$$

### KSEEB Class 5 Maths Fractions Additional Questions

Question 1.
Estimate the degree of closeness of the fractions $$\frac{2}{7}, \frac{3}{7}$$ and $$\frac{5}{7}$$ and $$\frac{1}{4}, \frac{1}{2}$$ and $$\frac{3}{4}$$

$$\frac{2}{7}$$ is closer to $$\frac{1}{4}, \frac{3}{7}$$ is closer to $$\frac{1}{2}$$
$$\frac{5}{7}$$ is closer to $$\frac{3}{4}$$
Estimate the degree of closeness of the fractions $$\frac{2}{9}, \frac{4}{9}, \frac{5}{9}$$ and $$\frac{7}{9}$$ to $$\frac{1}{4}, \frac{1}{2}$$ and $$\frac{3}{4}$$ .
$$\frac{2}{9}$$ is closer to $$\frac{1}{4}, \frac{4}{9}$$ is closer to $$\frac{1}{2}$$
$$\frac{5}{9}$$ is closer to $$\frac{1}{2}, \frac{7}{9}$$ is closer to $$\frac{3}{4}$$