KSEEB Solutions for Class 7 Karnataka State Syllabus

Expert Teachers at KSEEBSolutions.com has created KSEEB Solutions for Class 7 all subjects Pdf Free Download in English Medium and Kannada Medium of 7th Standard Karnataka Textbook Solutions, Textbook Questions and Answers, Guide, Notes Pdf, Model Question Papers with Answers, Study Material, are part of KSEEB Solutions. Here we have given KTBS Karnataka State Board Syllabus for Class 7 Textbook Solutions based on NCERT Syllabus.

Karnataka State Board Syllabus for Class 7 Textbooks Solutions

KSEEB Solutions for Class 7 Karnataka State Syllabus

KSEEB Solutions for Class 7 Karnataka State Syllabus
KSEEB Solutions for Class 7 Karnataka State Syllabus

We hope the given KSEEB Solutions for Class 7 all subjects Pdf Free Download in English Medium and Kannada Medium of 7th Std Karnataka Textbook Solutions, Textbook Questions and Answers, Guide, Notes Pdf, Model Question Papers with Answers, Study Material will help you. If you have any query regarding KTBS Karnataka State Board Syllabus for Class 7 Textbooks Solutions based on NCERT Syllabus, drop a comment below and we will get back to you at the earliest.

KSEEB Solutions for Class 7 Maths Karnataka State Syllabus

Expert Teachers at KSEEBSolutions.com has created KSEEB Solutions for Class 7 Maths Pdf Free Download in English Medium and Kannada Medium of 7th Standard Karnataka Maths Textbook Solutions Answers Guide, Textbook Questions and Answers, Notes Pdf, Model Question Papers with Answers, Study Material, are part of KSEEB Solutions for Class 7. Here we have given KTBS Karnataka State Board Syllabus for Class 7 Maths Textbook Solutions based on NCERT Syllabus.

Karnataka State Board Syllabus for Class 7 Maths Solutions in English Medium

KSEEB Solutions for Class 7 Maths

7th Class Maths Textbook Solutions Karnataka State Syllabus

KSEEB Solutions for Class 7 Maths Chapter 1 Integers

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals

KSEEB Solutions for Class 7 Maths Chapter 3 Data Handling

KSEEB Solutions for Class 7 Maths Chapter 4 Simple Equations

KSEEB Solutions for Class 7 Maths Chapter 5 Lines and Angles

KSEEB Solutions for Class 7 Maths MP Board Class 7th Maths Chapter 6 The Triangles and Its Properties

KSEEB Solutions for Class 7 Maths Chapter 7 Congruence of Triangles

Karnataka State Syllabus Class 7 Maths Chapter 8 Comparing Quantities

Karnataka State Syllabus Class 7 Maths Chapter 9 Rational Numbers

Karnataka State Syllabus Class 7 Maths Chapter 10 Practical Geometry

Karnataka State Syllabus Class 7 Maths Chapter 11 Perimeter and Area

Karnataka State Syllabus Class 7 Maths Chapter 12 Algebraic Expressions

Karnataka State Syllabus Class 7 Maths Chapter 13 Exponents and Powers

Karnataka State Syllabus Class 7 Maths Chapter 14 Symmetry

Karnataka State Syllabus Class 7 Maths Chapter 15 Visualising Solid Shapes

Karnataka State Board Syllabus for Class 7 Maths Solutions in Kannada Medium

7th Class Maths Textbook Solutions in Kannada Medium Karnataka State Syllabus

KSEEB Solutions for Class 7 Maths Chapter 1 Purnamsagalu

KSEEB Solutions for Class 7 Maths Chapter 2 Bhinnarashigalu Mattu Dasamansagalu

KSEEB Solutions for Class 7 Maths Chapter 3 Dattamgala Nirvahane

KSEEB Solutions for Class 7 Maths Chapter 4 Sarala Samikaranagalu

KSEEB Solutions for Class 7 Maths Chapter 5 Rekhegalu Mattu Konagalu

KSEEB Solutions for Class 7 Maths MP Board Class 7th Maths Chapter 6 Tribhuja Mattu Adara Gunagalu

KSEEB Solutions for Class 7 Maths Chapter 7 Tribhujagala Sarvasamate

Karnataka State Syllabus Class 7 Maths Chapter 8 Parimanagala Holike

Karnataka State Syllabus Class 7 Maths Chapter 9 Bhagalabdha Sankhyegalu

Karnataka State Syllabus Class 7 Maths Chapter 10 Prayogika Rekhaganita

Karnataka State Syllabus Class 7 Maths Chapter 11 Suttalate Mattu Vistirna

Karnataka State Syllabus Class 7 Maths Chapter 12 Bijoktigalu

Karnataka State Syllabus Class 7 Maths Chapter 13 Ghatagalu Mattu Ghatankagalu

Karnataka State Syllabus Class 7 Maths Chapter 14 Samamiti

Karnataka State Syllabus Class 7 Maths Chapter 15 Ghanakrutigalu

We hope the given KSEEB Solutions for Class 7 Maths Pdf Free Download in English Medium and Kannada Medium of 7th Std Karnataka Maths Textbook Answers Solutions Guide, Textbook Questions and Answers, Notes Pdf, Model Question Papers with Answers, Study Material will help you. If you have any queries regarding KTBS Karnataka State Board Syllabus for Class 7 Maths Textbooks Solutions based on NCERT Syllabus, drop a comment below and we will get back to you at the earliest.

Tili Kannada Text Book Class 7 Solutions Answers Guide

Tili Kannada Text Book Class 7 Answers Solutions Guide Notes Pdf free download is part of KSEEB Solutions for Class 7. Here we have given Karnataka State Board Syllabus 7th Standard 2nd Language Tili Kannada Textbook Solutions.

Tili Kannada Text Book Class 7 Answers Solutions Guide (2nd Language)

Tili Kannada Text Book Class 7 Solutions 2nd Language

Class 7 Tili Kannada Gadya Bhaga​ Karnataka State Board Solutions

Class 7 Tili Kannada Padya Bhaga​ Karnataka State Board Solutions

Class 7 Tili Kannada Puraka Odu Karnataka State Board Solutions

We hope the given Tili Kannada Text Book Class 7 Solutions Answers Guide Notes Pdf free download will help you. If you have any queries regarding Karnataka State Board Syllabus 7th Standard 2nd Language Tili Kannada Textbook Answers, drop a comment below and we will get back to you at the earliest.

Siri Kannada Text Book Class 7 Solutions Answers Guide

Siri Kannada Text Book Class 7 Answers Solutions Guide Notes Pdf free download is part of KSEEB Solutions for Class 7. Here we have given Karnataka State Board Syllabus 7th Standard 1st Language Siri Kannada Textbook NCERT Solutions. Students can also read Tili Kannada Text Book Class 7 Solutions of 2nd language.

Siri Kannada Text Book Class 7 Answers Solutions Guide (1st Language)

Siri Kannada Text Book Class 7 Solutions 1st Language

Class 7 Siri Kannada Gadya Bhaga​ Karnataka State Board Solutions

Class 7 Siri Kannada Padya Bhaga​ Karnataka State Board Solutions

Class 7 Siri Kannada Puraka Patagalu Karnataka State Board Solutions

Tili Kannada Text Book Class 7 Answers Solutions Guide (2nd Language)

Tili Kannada Text Book Class 7 Solutions 2nd Language

Class 7 Tili Kannada Gadya Bhaga​ Karnataka State Board Solutions

Class 7 Tili Kannada Padya Bhaga​ Karnataka State Board Solutions

Class 7 Tili Kannada Puraka Odu Karnataka State Board Solutions

We hope the given Siri Kannada Text Book Class 7 Solutions Answers Guide Notes Pdf free download will help you. If you have any queries regarding Karnataka State Board Syllabus 7th Standard 1st Language Siri Kannada Textbook Answers, drop a comment below and we will get back to you at the earliest.

KSEEB Solutions for Class 7 Physical Education Karnataka State Syllabus

Expert Teachers at KSEEBSolutions.com has created KSEEB Solutions for Class 7 Physical Education Pdf Free Download in English Medium and Kannada Medium of 7th Standard Karnataka Physical Education Textbook Solutions Answers Guide, Textbook Questions and Answers, Notes Pdf, Study Material, are part of KSEEB Solutions for Class 7. Here we have given KTBS Karnataka State Board Syllabus for Class 7 Physical Education Textbook Solutions based on NCERT Syllabus.

Karnataka State Board Syllabus for Class 7 Physical Education Solutions in Kannada Medium

7th Class Physical Education Textbook Solutions in Kannada Medium Karnataka State Syllabus

KSEEB Solutions for Class 7 Physical Education Karnataka State Syllabus

We hope the given KSEEB Solutions for Class 7 Physical Education Pdf Free Download in English Medium and Kannada Medium of 7th Std Karnataka Physical Education Textbook Answers Solutions Guide, Textbook Questions and Answers, Notes Pdf, Study Material will help you. If you have any queries regarding KTBS Karnataka State Board Syllabus for Class 7 Physical Education Textbook Solutions, drop a comment below and we will get back to you at the earliest.

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

Students can Download Chapter 2 Fractions and Decimals Ex 2.1, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

Multiplying and Dividing Rational Expressions Calculator.

Question 1.
Solve:
i)
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 1
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 2

ii)
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 3
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 4

iii)
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 5
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 6
L.C.M = 5 × 7 × 1 × 1 = 35
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 7
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 8

iv)
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 9
Solution:

Online Subtracting Fractions Calculator subtracts the fractions 9/11 and 4/5 i.e. 1/55

The given fractions are 9/11 and 4/5

Firstly the L.C.M should be done for the denominators of the two fractions 9/11 and 4/5

9/114/5

The LCM of 11 and 5 (denominators of the fractions) is 55

Given numbers has no common factors except 1. So, there LCM is their product i.e 55

 

= 9 x 5 – 4 x 11/55

= 45 – 44/55

= 1/55

Result: 1/55

v)
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 12
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 13
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 14

vi)
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 15
⇒ convert mixed fractions to improper fraction
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 16

vii)
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 17
convert mixed fractions to improper fraction
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 18

Using a fraction and whole number calculator in situations where you struggle to solve your arithmetic assignments can be useful.

Question 2.
Arrange the following in descending order:
i)
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 19
= We need to arrange these in descending order,
To find which number is greater or smaller, we make their denominators equal.
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 20

ii)
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 21
⇒ We make their denominators equal, to find the descending order.
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 22

Free quadratic equation completing the square calculator – Solve quadratic equations using completing the square step-by-step.

Question 3.
In a “magic square”, the sum of the numbers in each row, in each column and along the diagonals is the same. Is this a magic square ?
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 23
Solution:
For Row,
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 24
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 25
For diagonals,
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 26
Since Sum of air rows, columns and diagonals are equal.

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

Question 4.
A rectangular sheet of paper is 12\(\frac{1}{2}\) cm long and 10\(\frac{2}{3}\) cm wide. Find its perimeter.
Solution:
Length of rectangular sheet of paper = 12\(\frac{1}{2}\) cm
(breadth) width of rectangular sheet paper = 10\(\frac{2}{3}\) cm
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 27
Perimeter of rectangle = 2 (length + breadth)
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 28
converting the above fraction to mixed fraction,
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 29

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

2 2/3 as an improper fraction in its simplest form.

Question 5.
Find the perimeters of
(i) ∆ ABE
(ii) the rectangle BCDE in this figure. Whose perimeter is greater ?
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 30
Solution:
(i) ∆ ABE
perimeter of ∆ ABE
perimeter = AB + AE + BE
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 31
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 311

ii) The rectangle BCDE in this figure
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 32
Perimeter of rectangle BCDE,
As it is a rectangle, opposite sides are equal
BC = DE CD = BE
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 33
perimeter of rectangle = 2(l + b)
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 34
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 35
Also,
We have to find which perimeter is greater
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 36
To find which fraction is greater, we make its denominator equal.
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 37
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 38
Perimeter of ∆ ABE > Perimeter of BCDE
(Thus, Perimeter of ∆ ABE is greater)

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

Question 6.
Salil wants to put a picture in a frame. The picture is 7\(\frac{3}{10}\) cm wide. How much should the picture be trimmed ?
Solution:
There are two things here – picture, and frame
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 39
so, picture has to be trimmed
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 40
\(=\frac{3}{10}\)
∴ Picture has to trimmed by = \(=\frac{3}{10}\) cm

Question 7.
Ritu ate \(\frac{3}{5}\) part of an apple and the remaining apple was eaten by her brother Somu. How much part of the apple did Somu eat ? Who had the larger share ? By how much ?
Solution:
Total part = 1
Part eaten by Ritu = \(\frac{3}{5}\)
Part eaten by Somu = Total part – part eaten by Ritu
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 41
Now,
We have to tell who ate the larger share so, we have to compare,
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 42
∴ Ritu ate the larger share.
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 43
Ritu ate large share by \(\frac{1}{5}\)

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

Question 8.
Michael finished colouring in \(\frac{7}{12}\) hour. Vaibhav finished colouring the same picture in \(\frac{3}{4}\) hour. Who worked longer ? By what fraction was it longer ?
Solution:
Michael finished work in = \(\frac{7}{12}\) hour
Vaibhav finished work in = \(\frac{3}{4}\)
We need to find who worked longer.
i.e., we need to find greater of = \(\frac{7}{12}\) & \(\frac{3}{4}\)
We make their denominators equal
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 44
∴ Vaibhav worked longer.
We also need to find by how much
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 45
Vaibhav worked longer by \(\frac{1}{6}\) hours.

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

Students can Download Chapter 2 Fractions and Decimals Ex 2.5, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

Question 1.
Which is greater ?
i) 0.5 or 0.05
Solution:
0.5 > 0.05 (∵ 0.5 = 0.50)

ii) 0.7 or 0.5
Solution:
0.7 > 0.5

iii) 7 or 0.7
Solution:
7 > 0.7 (∵ 7 = 7.0)

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

iv) 1.37 or 1.49
Solution:
1.49 > 1.37

v) 2.03 or 2.30
Solution:
2.30 > 2.03

vi) 0.8 or 0.88
Solution:
0.88 > 0.8 (∵ 0.8 = 80)

1 1/2 as a decimal is equal to 1.5.

Question 2.
Express as rupees using decimals :
i) 7 paise
Solution:
7 paise = Rs. 0.07

ii) 7 rupees 7 paise
Solution:
7 rupees 7 paise Rs. 7.07

iii) 77 rupees 77paise
Solution:
77 rupees 77 paise = ₹ 77.77

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

iv) 50 paise
Solution:
50 paise = 0.50

v) 235 paise
Solution:
235 paise = 2.35

Question 3.
i) Express 5cm in metre and kilometre
Solution:
5 cm = 0.05m = 0.00005km.

ii) Express 35mm in cm, m and km
Solution:
35mm = 3.5cm = 0.000035km

Question 4.
Express in kg :
i) 200g
Solution:
200g = 0.200kg = 0.2 kg

ii) 3470g
Solution:
3470g = 3.470kg

iii) 4 kg 8 g
Solution:
4kg 8g = 4.008 kg

Question 5.
Write the following decimal numbers in the expanded form :
i) 20.03
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 1

ii) 2.03
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 21

iii) 200.03
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 22

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

iv) 2.034
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 23

Question 6.
Write the place value of 2 in the following decimal numbers :

i) 2.56
Solution:
2.56 place value of 2 in the decimal number 2.56 = 2 ones place)

ii) 21.37
Solution:
21.37 place value of 2 in the decimal number 21.37 = 2 × 10 = 20. (2 is in tens place)

iii) 10.25
Solution:
10.25 = palce value of 2 in the decimal
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 24

iv) 9.42
Solution:
9.42 = place value of 2 in the decimal number
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 25
(2 is in hundredths place)

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

v) 63.352
Solution:
63.352 = place value of 2 in the decimal number
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 26

Question 7.
Dinesh went from place A to place B and from 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelles more and by how much ?
Solution:
Distance travelled from A to B = 7.5kms
Distance travelled from B to C = 12.7kms
Total distance travelled from A to B & B to C = 20.2 kms.
Ayub
Distance travelled from A to D = 9.3 kms
Distance travelled from D to C = 11.8 kms
Total distance travelled from A to D & D to C = 21.1 kms
∴ Ayub travelled more distance than Dinesh by = 21.1 – 20.2 = 0.9 kms.

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

Question 8.
Shyama bought 5 kg 300g apples and 3 kg 250 g mangoes. Sarala bought 4 kg of 800 g oranges and 4 kg 150g bananas. Who bought more fruits?
Solution:
Shyama:
Weight of Apples bought = 5.300kgs
Weight of Mangoes bought = 3.250kgs
Total weight of fruits = 8.550kgs

Sarala:
Weight of oranges bought = 4.800kgs
Weight of Bananas bought = 4.150kgs
Total weight of fruits = 8.950kgs
8.950 >8.550
∴ Sarala bought more fruits than Shyama.

KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

Question 9.
How much less is 28 km than 42.6 km?
Solution:
KSEEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 30
∴ 28 km is less than 42.6 km by 14.6 kms.

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

Students can Download Chapter 8 Comparing Quantities Ex 8.3, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

Percentage difference calculator tool makes the calculation faster, and it displays the difference in the percentage in a fraction of seconds.

Question 1.
Tell what is the profit or loss in the following transactions. Also find profit per cent or loss per cent in each case.
a) Gardening shears bought for ₹ 250 and sold for ₹ 325.
Solution:
C. P = Rs 250
S. P = Rs. 325
S.P > C.P
∴ It is profit.
Total profit = S.P – C.P
= 325 – 250 = Rs 75
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 1

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

b) A refrigerator bought for ₹ 12,000 and sold at ₹ 13,500.
Solution:
C. P = Rs. 12,000
S.P = Rs. 13,500
S.P > C.P
It is profit
Total profit = S. P – C. P
= 13,500 – 12,000
= Rs.1,500/-
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 2

c) A cupboard bought for ₹ 2,500 and sold at ₹ 3,000.
Solution:
C.P = Rs. 2,500
S. P = Rs. 3,000
S.P > C.P
It is profit
Total profit = S. P – C. P
= 3000 – 2500
= Rs. 500
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 3

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

d) A skirt bought for 250 and sold at ₹ 150.
C.P = Rs. 250/-
S.P = Rs. 150/-
S.P < C.P
∴ It is loss
Total loss = C.P – S.P
= 250 – 150 = Rs. 100
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 4

Percentage Difference Calculator is very simple app to calculate percentage difference between 2 values.

Question 2.
Convert each part of the ratio to percentage :
a) 3 : 1
Solution:
Total parts = 3 + 1 = 4
Percentage of First part of the ratio =
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 5
Percentage of 2nd part of the ration =
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 6

b) 2 : 3 : 5
Solution:
Total parts = 2 + 3 + 5 = 10
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 100
% of second part of the ratio =
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 101
% of third part of the ratio =
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 102

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

c) 1 : 4
Total parts = 1 + 4 = 5
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 8

d) 1 : 2 : 5
Total parts. = 1 + 2 + 5 = 8
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 9
% of second part of the ratio =
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 103

Question 3.
The population of a city decreased from 25,000 to 24,500. Find the percentage decrease.
Solution:
Decreased population = 25,000 – 24,500
= 500
Percentage of decrease =
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 11

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

Question 4.
Arun bought a car for 3, 50, 000. The next year, the price went upto ₹ 3,70,000. What was the percentage of price increase ?
Solution:
Price of a car = Rs. 3,50,000
Increased price of a car = Rs. 3,70,000
Total increase = Rs. 20,000
Percentage of price increase =
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 12

Question 5.
I buy a T. V. for ₹ 10,000 and sell it at a profit of 20%. How much money do I get for it ?
Solution:
C.P of a T.V = Rs. 10,000
Profit = 20%
20% of Rs. 10,000
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 13
∴ Amount I get = C. P + profit
= 10,000 + 2,000
= Rs. 12,000

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

Question 6.
Juhi sells a washing machine for ₹ 13,500. She loses 20% in the bargain. What was the price at which she bought it ?
Solution:
S. P = C. P – Loss
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 15
∴ She bought that washing machine for Rs. 16,875.

CGPA into Percentage … cumulative grading percentage of current grade.

Question 7.
i) Chalk contains calcium, carbon and oxygen in the ratio 10 : 3 : 12. Find the percentage of carbon in chalk.
Solution:
Total parts = 10 + 3 + 12 = 25
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 16
% of carbon in chalk =
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 17

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

ii) If in a stick of chalk. carbon is 3g, what is the chalk stick?
Solution:
Let the weight of chalk stick be ‘M’
Then 12% of M = 3
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 18
∴ The weight of the chalk stick is 25 grams.

Question 8.
Amina buys a book for ₹ 275 and sells it at a loss of 15%. How much does she sell it for ?
Solution:
C. P of a book = Rs. 275
loss = 15% of C. P
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 19
S.P = C.P – Loss
= 275 – 41.25
= Rs. 233.751
∴ She sells it for Rs. 233.75.

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

Question 9.
Find the amount to be paid at the end of 3 years in each case:
a) Principal = ₹ 1,200 at 12 % p.a
P = Rs. 1200/-
R = 12%
T = 3 years
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 70
A = P + I = 1200 + 432 = Rs. 1,632
∴ The amount to paid at the end of 3 years is Rs. 1,632

b) Principal = ₹ 7,500 at 5% p.a
P = Rs. 7,500
R = 5%
T = 3 years
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 71
A = P + I
= 7500 + 1125
= Rs. 8,625
∴ The amount to be paid at the end of 3 years is Rs. 8,625.

Question 10.
What rate gives ₹ 280 as interest on a sum of ₹ 56,000 in 2 years ?
Solution:
P = Rs. 56,000/-
R = ?
T = 2 years
I = Rs. 280
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 72
∴ The rate of interest is 0.25% per annum.

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

Question 11.
If Meena gives an interest of ? 45 for one year at 9% rate p.a. What is the sum she has borrowed ?
Solution:
P = ?
R = 9%
T = 1 years
I = Rs. 45
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 73
∴ She has borrowed the sum of Rs. 500

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2

Students can Download Chapter 8 Comparing Quantities Ex 8.2, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2

The percentage difference calculator is here to help you compare two numbers.

Question 1.
Convert the given fractional numbers to percents.
a) \(\frac{1}{8}\)
Solution:
Percent means per hundred. So multi-plied by 100.
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 1

b) \(\frac{5}{4}\)
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 2

c) \(\frac{3}{40}\)
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 3

d) \(\frac{2}{7}\)
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 4

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2

Question 2.
Convert the given decimal fractions to per cents.
a) 0.65
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 5

b) 2.1
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 6

c) 0.02
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 7

d) 12.35
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 8

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2

The percent decrease calculator calculates the amount of decrease, in which we would say, “x percent decrease”.

Question 3.
Estimate what part of the figures is coloured and hence find the per cent which is coloured.
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 9
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 10
∴ In the first figure 25% is coloured.
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 11
∴ in the second figur e 50% Is coloured,.
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 111
∴ In the third figure 37.5 % is coloured.

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2

Question 4.
Find :
a) 15% of 250
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 12

b) 1% of 1 hour
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 13

c) 20% of ₹ 2500
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 14

d) 75% of ₹ 1 kg
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 15

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2

Question 5.
Find the whole quantity if
a) 5% of it is 600.
Solution:
Let the whole quantity be ‘m’
∴ 5% of m = 600
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 16
∴ The whole quantity is 12,000.

b) 12% of its 1080.
Solution:
Let the whole quantity be ‘m’
∴ 12% of m = Rs. 1080
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 17
∴ The whole amount be Rs. 9.000

c) 40 % of it is 500 km
Solution:
Let the whole quantity be ‘m’
∴ 40% of m = 500 km
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 18
∴ The whole amount is 1250 kms

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2

d) 70% of it is 14 minutes
Let the whole quantity be ‘m’
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 19
∴ The whole amount is 20 minutes

e) 8% of it is 40 litres.
Let the whole quantity be ‘m’
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 20
∴ The whole amount be 500 liters

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2

Question 6.
Convert given per cents to decimal fractions and also to fractions in simplest forms:
Solution:
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 21

Question 7.
In a city, 30% are females, 40% are males and the remaining are children. What percent are children?
Solution:
females = 30%
males = 40%
children = 100 – (30 + 40)
remaining are children = 100 – 70 = 30%
∴ Percentage of children = 30%

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2

Percentage difference calculator tool makes the calculation faster, and it displays the difference in the percentage in a fraction of seconds.

Question 8.
Out of 15,000 votes in a constituency, 60% voted. Find the percentage of voters who did not vote. Can you now find how many actually did not vote?
Solution:
Total no. of voters in a constituency } = 15,000
Percentage of voted = 60%
∴ Percentage of voters who did not vote
= 100 – 60 = 40%
Actual number of voters who did not vote} = 40% of 15,000
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 80
6000 voters who did not vote.

I hope you guys are now clear about how to convert CGPA to percentage in the SPPU mark sheet.

Question 9.
Meeta saves ₹ 400 from her salary. If this is 10% of her salary. What is her salary?
Solution:
Let Meeta’s salary be ‘M’
10% of M is = Rs. 400
∴ M =?
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 81
∴ Her salary be Rs. 4,000/-

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2

Question 10.
A local cricket team played 20 matches in one season. It won 25% of them. How many matches did they win?
Let the total matches won by them be M 25% of 20 = M
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 82
∴ They win 5 matches.

Tili Kannada Text Book Class 7 Solutions Gadya Chapter 1 Annadana

Students can Download Kannada Lesson 1 Annadana Questions and Answers, Summary, Notes Pdf, Tili Kannada Text Book Class 7 Solutions, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.

Tili Kannada Text Book Class 7 Solutions Gadya Bhaga Chapter 1 Annadana (Chandrasekhara Kambara)

Annadana Questions and Answers, Summary, Notes

Tili Kannada Text Book Class 7 Solutions Gadya Chapter 1 Annadana 1

Tili Kannada Text Book Class 7 Solutions Gadya Chapter 1 Annadana 2
Tili Kannada Text Book Class 7 Solutions Gadya Chapter 1 Annadana 3

Tili Kannada Text Book Class 7 Solutions Gadya Chapter 1 Annadana 4
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Tili Kannada Text Book Class 7 Solutions Gadya Chapter 1 Annadana 6
Tili Kannada Text Book Class 7 Solutions Gadya Chapter 1 Annadana 7

Tili Kannada Text Book Class 7 Solutions Gadya Chapter 1 Annadana 8
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Tili Kannada Text Book Class 7 Solutions Gadya Chapter 1 Annadana 10
Tili Kannada Text Book Class 7 Solutions Gadya Chapter 1 Annadana 11

Tili Kannada Text Book Class 7 Solutions Gadya Chapter 1 Annadana 12
Tili Kannada Text Book Class 7 Solutions Gadya Chapter 1 Annadana 13

Annadana Summary in Kannada

Annadana Summary in Kannada 1


Annadana Summary in Kannada 3

Annadana Summary in Kannada 4
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Annadana Summary in Kannada 7

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